Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

A bob of mass $m subscript 1 end subscript$ hangs by a light inextensible string which passes over a fixed smooth pulley P and connects a ring of mass $m subscript 2 end subscript$ . The ring is constrained to move along a smooth rigid horizontal rod. The instantaneous velocities and accelerations of the bodies are $v subscript 1 end subscript comma a subscript 1 end subscript$ and $v subscript 2 end subscript$ , a $blank subscript 2 end subscript$ respectively then :

$v_{1} = v_{2} c o s θ, a_{1} = a_{2} c o s θ$
$v_{2} = v_{1} c o s θ, a_{2} = a_{1} c o s θ$
$v_{1} = v_{2} s i n θ, a_{1} = a_{2} s i n θ$
$m_{2} v_{2} = m_{1} v_{1} s i n θ, m_{2} a_{2} = m_{1} a_{1} s i n θ$

The correct answer is: $v subscript 1 end subscript equals v subscript 2 end subscript c o s invisible function application theta comma a subscript 1 end subscript equals a subscript 2 end subscript c o s invisible function application theta$

Related Questions to study

The block A is pushed towards the wall by a distance and released. The normal reaction by vertical wall on the block B v/s compression in spring is given by :

The block A is pushed towards the wall by a distance and released. The normal reaction by vertical wall on the block B v/s compression in spring is given by :

physics-General

Two springs are a series combination and are attached to a book of mass 'm' which is in equilibrium. The spring constants and the extensions in the springs are as shown in the figure. Then the force exerted by the spring on the block is :

Two springs are a series combination and are attached to a book of mass 'm' which is in equilibrium. The spring constants and the extensions in the springs are as shown in the figure. Then the force exerted by the spring on the block is :

physics-General

In the situation shown in the figure, the system is in equilibrium. All the strings, spring and pulley are light. Just after cutting the string AB,

In the situation shown in the figure, the system is in equilibrium. All the strings, spring and pulley are light. Just after cutting the string AB,

physics-General

parallel

System shown in figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass 2 m and m just after the string is cut will be :

System shown in figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass 2 m and m just after the string is cut will be :

physics-General

Mass M is displaced by a vertical distance $x subscript 0 end subscript$ from equilibrium position by applying a force F The spring constant are $k subscript 1 end subscript$ and $k subscript 2 end subscript open parentheses k subscript 1 end subscript greater than k subscript 2 end subscript close parentheses$ . Find the force F

Mass M is displaced by a vertical distance $x subscript 0 end subscript$ from equilibrium position by applying a force F The spring constant are $k subscript 1 end subscript$ and $k subscript 2 end subscript open parentheses k subscript 1 end subscript greater than k subscript 2 end subscript close parentheses$ . Find the force F

physics-General

In the two systems as shown, what should be value of mass M so that extensions in two springs (of same spring constant k) is same (in kg ) ?

In the two systems as shown, what should be value of mass M so that extensions in two springs (of same spring constant k) is same (in kg ) ?

physics-General

parallel

Fig shows variation of force acting on a body, with time. Assuming the body to start from rest, the variation of its momentum with time is best represented by which plot?

Fig shows variation of force acting on a body, with time. Assuming the body to start from rest, the variation of its momentum with time is best represented by which plot?

physics-General

The variation of force acting on a particle of mass m with time is shown in figure. If the initial speed of particle is zero, then what is the speed of particle at $t equals t subscript 0 end subscript$ ?

The variation of force acting on a particle of mass m with time is shown in figure. If the initial speed of particle is zero, then what is the speed of particle at $t equals t subscript 0 end subscript$ ?

physics-General

Find the mass M of the hanging block in figure. Which will prevent the smaller block from slipping over the triangular block. All the surfaces are frictionless and the strings and the pulleys are light.

Find the mass M of the hanging block in figure. Which will prevent the smaller block from slipping over the triangular block. All the surfaces are frictionless and the strings and the pulleys are light.

physics-General

parallel

A man of mass m=60 kg is standing on weighing machine fixed on a triangular wedge of angle $q equals 60 to the power of ring operator end exponent$ as shown in the figure. The wedge is moving up with an upward acceleration $a equals 2 blank m divided by s to the power of 2 end exponent$ . The weight registered by machine is:

A man of mass m=60 kg is standing on weighing machine fixed on a triangular wedge of angle $q equals 60 to the power of ring operator end exponent$ as shown in the figure. The wedge is moving up with an upward acceleration $a equals 2 blank m divided by s to the power of 2 end exponent$ . The weight registered by machine is:

physics-General

A block of mass 1 kg is at rest relative to a smooth wedge moving leftwards with constant acceleration $a equals 5 blank m divided by s to the power of 2 end exponent.$ Let $N$ be the normal reaction between the block and the wedge. Then : $open parentheses g equals 10 blank m divided by s to the power of 2 end exponent close parentheses$

A block of mass 1 kg is at rest relative to a smooth wedge moving leftwards with constant acceleration $a equals 5 blank m divided by s to the power of 2 end exponent.$ Let $N$ be the normal reaction between the block and the wedge. Then : $open parentheses g equals 10 blank m divided by s to the power of 2 end exponent close parentheses$

physics-General

A block is placed on an inclined plane moving towards right horizontally with an acceleration $a subscript 0 end subscript equals g$ . The length of the plane AC=1 m. Friction is absent everywhere. The time taken by the block to reach from C to A is $open parentheses g equals 10 blank m divided by s to the power of 2 end exponent close$

A block is placed on an inclined plane moving towards right horizontally with an acceleration $a subscript 0 end subscript equals g$ . The length of the plane AC=1 m. Friction is absent everywhere. The time taken by the block to reach from C to A is $open parentheses g equals 10 blank m divided by s to the power of 2 end exponent close$

physics-General

parallel

A block of mass $m$ is pulled by a string acts which passes over a smooth pulley P fitted with the wedge of mass M. A horizontal force F=mg acts on the string. If the string is massless and inextensible, assuming frictionless contacting surfaces and $theta equals c o s to the power of negative 1 end exponent invisible function application fraction numerator 4 over denominator 5 end fraction$ then

A block of mass $m$ is pulled by a string acts which passes over a smooth pulley P fitted with the wedge of mass M. A horizontal force F=mg acts on the string. If the string is massless and inextensible, assuming frictionless contacting surfaces and $theta equals c o s to the power of negative 1 end exponent invisible function application fraction numerator 4 over denominator 5 end fraction$ then

physics-General

Find the acceleration of the wedge so that the block is stationary with respect to wedge

Find the acceleration of the wedge so that the block is stationary with respect to wedge

physics-General

In the figure the heavy mass $m$ moves down the smooth surface of a wedge making an angle $alpha$ with the horizontal. The wedge is on a smooth surface. The mass of the wedge is M. The direction of motion of the mass $m$ makes an angle $beta$ with the horizontal, then 'Tan $beta$ ' is

In the figure the heavy mass $m$ moves down the smooth surface of a wedge making an angle $alpha$ with the horizontal. The wedge is on a smooth surface. The mass of the wedge is M. The direction of motion of the mass $m$ makes an angle $beta$ with the horizontal, then 'Tan $beta$ ' is

physics-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.