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A bomb of 12 kg divedes in two parts whose ratio of masses is 1:4. If kinetic energy of smaller part is 288 text end text J, then momentum of bigger part in k g m divided by s e c will be

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  1. 48    
  2. 72     
  3. Data is incomplete    
  4. 108 to the power of 2 end exponent    

    Answer:The correct answer is: 48

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