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Physics-

General

Easy

Question

A circular current carrying loop of radius R is bent about its diameter by $.90 to the power of ring operator end exponent$ and placed in a magnetic field $stack B with rightwards arrow on top equals B subscript 0 end subscript left parenthesis stack i with bar on top plus stack j with tilde on top right parenthesis$ as shown in figure.

The torque acting on the loop is zero
The magnetic moment of the loop is $\frac{1 π R^{2}}{2} (- \vec{i} - j)$
The angular acceleration of the loop is non zero.
The magnetic moment of the loop is $\frac{t - R^{2}}{2} (- 1 + 3)$

The correct answer is: The magnetic moment of the loop is $fraction numerator 1 pi R to the power of 2 end exponent over denominator 2 end fraction left parenthesis negative stack i with rightwards arrow on top minus j right parenthesis$

$stack M with rightwards arrow on top equals fraction numerator l pi R to the power of 2 end exponent over denominator 2 end fraction left parenthesis negative stack i with tilde on top minus stack j with rightwards arrow on top right parenthesis semicolon stack tau with rightwards arrow on top equals stack M with rightwards arrow on top cross times stack B with rightwards arrow on top equals 0$

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