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Physics-

General

Easy

Question

A hollow sphere is released from the top of a wedge, friction is sufficient for pure rolling of sphere on the wedge. There is no friction between the wedge and the ground. Radius of sphere is R. At the instant it leaves the wedge horizontally. Velocity of centre of mass of sphere w.r.t. ground is-

$\sqrt{\frac{5}{7} g h}$
$\sqrt{2 g h}$
$\sqrt{\frac{3}{7} g h}$
$\sqrt{\frac{11}{7} g h}$

The correct answer is: $square root of fraction numerator 3 over denominator 7 end fraction g h end root$

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