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Question

A particle is projected from a point A with velocity u square root of 2 at an angle of 45 degree with horizontal as shown in figure. It strikes the plane B C at right angles. The velocity of the particle at the time of collision is

  1. fraction numerator square root of 3 u end root over denominator 2 end fraction    
  2. fraction numerator u over denominator 2 end fraction    
  3. fraction numerator 2 u over denominator square root of 3 end fraction    
  4. u    

The correct answer is: fraction numerator 2 u over denominator square root of 3 end fraction


    Let v be the velocity at the time of collision

    Then, u square root of 2 cos invisible function application 45 degree equals v sin invisible function application 60 degree
    open parentheses u square root of 2 close parentheses open parentheses fraction numerator 1 over denominator square root of 2 end fraction close parentheses equals fraction numerator square root of 3 v over denominator 2 end fraction blank therefore v equals fraction numerator 2 over denominator square root of 3 end fraction u

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