Physics-
General
Easy

Question

A particle is projected with a speed v at 45 degree with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height h is

  1. Zero    
  2. fraction numerator m v h to the power of 2 end exponent over denominator square root of 2 end fraction    
  3. fraction numerator m v h over denominator square root of 2 end fraction    
  4. fraction numerator m v h to the power of 3 end exponent over denominator square root of 2 end fraction    

The correct answer is: fraction numerator m v h over denominator square root of 2 end fraction


    Velocity of particle at maximum height h is v to the power of ´ end exponent equals v cos invisible function application theta where v equals initial velocity of particle at which it is projected, theta equals angle of projection
    Angular momentum, L equals m v to the power of ´ end exponent h equals m v cos invisible function application theta h
    equals m v h cos invisible function application 45 degree equals fraction numerator m v h over denominator square root of 2 end fraction

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