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Physics-

General

Easy

Question

A particle is projected with initial speed of $V subscript 0 end subscript$ and angle of $theta$ . Find the horizontal displacement when its velocity is perpendicular to initial velocity.

$\frac{V_{0}^{2}}{g t a n θ}$
$\frac{V_{0}^{2}}{g s i n θ}$
$\frac{V_{0} s i n θ}{g}$
$\frac{V_{0}^{2}}{t a n θ}$

The correct answer is: $fraction numerator V subscript 0 end subscript blank to the power of 2 end exponent over denominator g t a n invisible function application theta end fraction$

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