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Question

A particle of mass 4m which is at rest explodes into four equal fragments. All 4 fragments are scattered in the same horizontal plane. Three fragments are found to move with velocity V each as shown in the fig. The total energy released in the process of explosion is

  1. m V to the power of 2 end exponent left parenthesis 3 minus square root of 2 right parenthesis    
  2. m V to the power of 2 end exponent left parenthesis 3 minus square root of 2 right parenthesis divided by 2    
  3. 2mV2    
  4. m V to the power of 2 end exponent left parenthesis 1 plus square root of 2 right parenthesis divided by 2    

The correct answer is: m V to the power of 2 end exponent left parenthesis 3 minus square root of 2 right parenthesis

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