A particle of mass is is rotating in a horizontal circle of rad-Turito

Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

General

Easy

Physics-

A particle of mass $m$ is rotating in a horizontal circle of radius $R$ and is attached to a hanging mass $M$ as shown in the figure. The speed of rotation required by the mass $m$ keep $M$ steady is

Physics-General

$\sqrt{\frac{m g R}{M}}$
$\sqrt{\frac{m R}{M g}}$
$\sqrt{\frac{m g}{M R}}$
$\sqrt{\frac{m g R}{m}}$

Answer:The correct answer is: $square root of fraction numerator m g R over denominator m end fraction end root$ To keep the mass M steady, let T is the tension in the string joining the two. Then for particle $m comma$
$T equals fraction numerator m v to the power of 2 end exponent over denominator R end fraction open parentheses i close parentheses$
For mass $M comma$
$T equals M g left parenthesis i i right parenthesis$
From Eqs. (i) and (ii)
$fraction numerator m v to the power of 2 end exponent over denominator R end fraction equals M g ⟹ v equals square root of fraction numerator M g R over denominator m end fraction end root$

Book A Free Demo

Name

Mobile

+91

Email

Grade

I agree to get WhatsApp notifications & Marketing updates

Related Questions to study

A point mass $m$ is suspended from a light thread of length $l comma$ fixed at $O$ , is whirled in a horizontal circle at constant speed as shown. From your point of view, stationary with respect to the mass, the forces on the mass are

T equals t e n s i o n comma blank W equals w e i g h t blank a n d blank F equals c e n t r i f u g a l blank f o r c e

A point mass $m$ is suspended from a light thread of length $l comma$ fixed at $O$ , is whirled in a horizontal circle at constant speed as shown. From your point of view, stationary with respect to the mass, the forces on the mass are

physics-General

T equals t e n s i o n comma blank W equals w e i g h t blank a n d blank F equals c e n t r i f u g a l blank f o r c e

A particle is projected from a point $A$ with velocity $u square root of 2$ at an angle of $45 degree$ with horizontal as shown in figure. It strikes the plane $B C$ at right angles. The velocity of the particle at the time of collision is

v

be the velocity at the time of collision

u square root of 2 cos invisible function application 45 degree equals v sin invisible function application 60 degree

open parentheses u square root of 2 close parentheses open parentheses fraction numerator 1 over denominator square root of 2 end fraction close parentheses equals fraction numerator square root of 3 v over denominator 2 end fraction blank therefore v equals fraction numerator 2 over denominator square root of 3 end fraction u

A particle is projected from a point $A$ with velocity $u square root of 2$ at an angle of $45 degree$ with horizontal as shown in figure. It strikes the plane $B C$ at right angles. The velocity of the particle at the time of collision is

physics-General

v

be the velocity at the time of collision

u square root of 2 cos invisible function application 45 degree equals v sin invisible function application 60 degree

open parentheses u square root of 2 close parentheses open parentheses fraction numerator 1 over denominator square root of 2 end fraction close parentheses equals fraction numerator square root of 3 v over denominator 2 end fraction blank therefore v equals fraction numerator 2 over denominator square root of 3 end fraction u

Assertion: At constant pressure for the change H2O(s)→H2O(g) work done is negative.
Reason: During phase transition work done is always negative.

Assertion: At constant pressure for the change H2O(s)→H2O(g) work done is negative.
Reason: During phase transition work done is always negative.

chemistry-General

In view of the signs of DG° or the following reactions:
PbO2 +Pb→2PbO,DrG°<0
SnO2 +Sn→2SnO,DrG°>0, which oxidation states are more characteristic for lead and tin?

In view of the signs of DG° or the following reactions:
PbO2 +Pb→2PbO,DrG°<0
SnO2 +Sn→2SnO,DrG°>0, which oxidation states are more characteristic for lead and tin?

chemistry-General

Considerthereaction:4NO_2(g) O_2(g) →2N₂O_5(g) ,DH=–111kJ IfN2O5(s)isformedinsteadofN2O5(g)intheabove reaction,theDHvaluewillbe:(given,DHofsublimationfor N2O5is54kJmol )</span

Considerthereaction:4NO_2(g) O_2(g) →2N₂O_5(g) ,DH=–111kJ IfN2O5(s)isformedinsteadofN2O5(g)intheabove reaction,theDHvaluewillbe:(given,DHofsublimationfor N2O5is54kJmol )</span

chemistry-General

Thevalueofenthalpychange(DH)forthe reactionC2H5OH(l)+3O2(g)→2CO2(g)+3H2O(l) at 27°Cis–1366.5kJmol–1.The valueofinter- nalenergychangefortheabovereactionat this temperaturewillbe-

Thevalueofenthalpychange(DH)forthe reactionC2H5OH(l)+3O2(g)→2CO2(g)+3H2O(l) at 27°Cis–1366.5kJmol–1.The valueofinter- nalenergychangefortheabovereactionat this temperaturewillbe-

chemistry-General

Fromthethermochemicalreactions,C(graphite)+½O2 →CO;DH=–110.5KJ CO+1/2O2 →CO2;DH=–83.2KJ Theheatofreactionof C(graphite)+O2 →CO2is-

Fromthethermochemicalreactions,C(graphite)+½O2 →CO;DH=–110.5KJ CO+1/2O2 →CO2;DH=–83.2KJ Theheatofreactionof C(graphite)+O2 →CO2is-

chemistry-General

TheDH° for CO2(g) ,CO₍_g₎ and H₂O_(g) are –393.5,–110.5and–241.8Kjmol–1respectively the standard enthalpychange (in KJ) for the reactionCO2(g)+H2(g)→CO(g)+H2O(g)is-

TheDH° for CO2(g) ,CO₍_g₎ and H₂O_(g) are –393.5,–110.5and–241.8Kjmol–1respectively the standard enthalpychange (in KJ) for the reactionCO2(g)+H2(g)→CO(g)+H2O(g)is-

chemistry-General

Which of the followingequationsrespresents standardheatofformationofCH4 ?

Which of the followingequationsrespresents standardheatofformationofCH4 ?

chemistry-General

2molesof COaremixedwith 1moleofO2ina containerof1l.Theycompletelytoform2moles ofCO2.Ifthe pressurein the vesselchanges from70atmto40atm,whatwill bethevalue of DU in kJat500K(The gasesdeviateappreciably from idealbehaviour.) 2CO+O2→2CO2;DH=-560kJ/mol, 1Latm=0.1kJ For theprocessH2O(l)(1 bar,373K)→H2O(g) (1bar,373K),thecorrect setofthermodynamic parametersis-

2molesof COaremixedwith 1moleofO2ina containerof1l.Theycompletelytoform2moles ofCO2.Ifthe pressurein the vesselchanges from70atmto40atm,whatwill bethevalue of DU in kJat500K(The gasesdeviateappreciably from idealbehaviour.) 2CO+O2→2CO2;DH=-560kJ/mol, 1Latm=0.1kJ For theprocessH2O(l)(1 bar,373K)→H2O(g) (1bar,373K),thecorrect setofthermodynamic parametersis-

chemistry-General

The conversion A to B is carried out by the following path:
Given: DS(A→C) =50e.u.,DS(C→D) =30 e.u., DS(B→D) =20e.u. Where e.u.is entropy unit then DS(A→B) is

The conversion A to B is carried out by the following path:
Given: DS(A→C) =50e.u.,DS(C→D) =30 e.u., DS(B→D) =20e.u. Where e.u.is entropy unit then DS(A→B) is

chemistry-General

Three balls are dropped from the top of a building with equal speed at different angles. When the balls strike ground their velocities are $v subscript 1 end subscript comma v blank subscript 2 end subscript$ and $v subscript 3 end subscript$ respectively, then

All the balls are projected from the same height, therefore their velocities will be equal.

S o comma blank v subscript 1 end subscript equals v subscript 2 end subscript equals v subscript 3 end subscript

Three balls are dropped from the top of a building with equal speed at different angles. When the balls strike ground their velocities are $v subscript 1 end subscript comma v blank subscript 2 end subscript$ and $v subscript 3 end subscript$ respectively, then

physics-General

All the balls are projected from the same height, therefore their velocities will be equal.

S o comma blank v subscript 1 end subscript equals v subscript 2 end subscript equals v subscript 3 end subscript

When does the current flow through the following circuit ?

When does the current flow through the following circuit ?

The following circuit when expressed in symbolic form of logic is :

The following circuit when expressed in symbolic form of logic is :

The trajectory of a particle moving in vast maidan is as shown in the figure. The coordinates of a position $A$ are $open parentheses 0 , 2 close parentheses.$ The coordinates of another point at which the instantaneous velocity is same as the average velocity between the points are

The trajectory of a particle moving in vast maidan is as shown in the figure. The coordinates of a position $A$ are $open parentheses 0 , 2 close parentheses.$ The coordinates of another point at which the instantaneous velocity is same as the average velocity between the points are

physics-General