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Physics-

General

Easy

Question

A piece of iron of density $7.8 cross times 10 to the power of 3 end exponent k g divided by 3$ and volume 100cm³ is totally immersed in water Calculate upthrust if $open parentheses d equals 1000 to the power of k g end exponent divided by m to the power of 3 end exponent close parentheses$

7.8 N
100 N
1 N
$10^{3}$ N

The correct answer is: 1 N

Density of substance = $rho subscript s end subscript equals 7.8 cross times 10 to the power of 3 end exponent k g divided by m to the power of 3 end exponent$
Density of water = $rho subscript w end subscript equals 1000 k g divided by m to the power of 3 end exponent$
Volume of substance = $100 c m to the power of 3 end exponent equals 100 cross times 10 to the power of negative 6 end exponent m to the power of 3 end exponent$
Volume of immersed substance= $100 cross times 10 to the power of negative 6 end exponent m to the power of 3 end exponent$
g= acceleration due to gravity.
Thus,
upthrust = $V subscript i end subscript rho subscript L end subscript g$
$equals 100 cross times 10 to the power of negative 6 end exponent cross times 1000 cross times 10$
=1N

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