Physics-
General
Easy

Question

A plane mirror is placed at the bottom of the tank containing a liquid of refractive index mu. P is a small object at a height h above the mirror. An observer O-vertically above P outside the liquid see P and its image in the mirror. The apparent distance between these two will be

  1. 2 mu h    
  2. fraction numerator 2 h over denominator mu end fraction    
  3. fraction numerator 2 h over denominator mu minus 1 end fraction    
  4. h open parentheses 1 plus fraction numerator 1 over denominator mu end fraction close parentheses    

The correct answer is: fraction numerator 2 h over denominator mu end fraction


    Image formation by a mirror (either plane or spherical) does not depend on the medium.
    The image of P will be formed at a distance h below the mirror. If d = depth of liquid in the tank.
    Apparent depth of P equals x subscript 1 end subscript equals fraction numerator d minus h over denominator mu end fraction
    Apparent depth of the image of P equals x subscript 2 end subscript equals fraction numerator d plus h over denominator mu end fraction
    \ Apparent distance between P and it's image equals x subscript 2 end subscript minus x subscript 1 end subscript equals fraction numerator 2 h over denominator mu end fraction

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