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A ray of light passes through four transparent media with refractive indices mu subscript 1 end subscript. mu subscript 2 end subscript mu subscript 3 end subscript comma text  and end text mu subscript 4 end subscript as shown in the figure. The surfaces of all media are parallel. If the emergent ray CD is parallel to the incident ray AB, we must have

Physics-General

  1. mu subscript 4 end subscript equals mu subscript 1 end subscript    
  2. mu subscript 1 end subscript equals mu subscript 2 end subscript    
  3. mu subscript 2 end subscript equals mu subscript 3 end subscript    
  4. mu subscript 3 end subscript equals mu subscript 4 end subscript    

    Answer:The correct answer is: mu subscript 4 end subscript equals mu subscript 1 end subscriptFor successive refraction through different media mu sin invisible function application theta equalsconstant. Here as theta is same in the two extreme media, mu subscript 1 end subscript equals mu subscript 4 end subscript.

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    From figure given in question theta equals 2 c equals 98 degree.
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    A ray of light is incident at an angle i from denser to rare medium. The reflected and the refracted rays are mutually perpendicular. The angle of reflection and the angle of refraction are respectively r and r’, then the critical angle will be

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    chemistry-General

    Both shows H-bonding, however the increase in hydrophobic character (due to two alkyl groups in ether), the H-bonding weakens.
    General
    chemistry-

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    chemistry-General
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    chemistry-General
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    chemistry-General
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