A ray of light passes through four transparent media with refra-Turito

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Physics-

General

Easy

Question

A ray of light passes through four transparent media with refractive indices $mu subscript 1 end subscript. mu subscript 2 end subscript mu subscript 3 end subscript comma text and end text mu subscript 4 end subscript$ as shown in the figure. The surfaces of all media are parallel. If the emergent ray CD is parallel to the incident ray AB, we must have

$μ_{1} = μ_{2}$
$μ_{2} = μ_{3}$
$μ_{3} = μ_{4}$
$μ_{4} = μ_{1}$

The correct answer is: $mu subscript 4 end subscript equals mu subscript 1 end subscript$

For successive refraction through different media $mu sin invisible function application theta equals$ constant. Here as $theta$ is same in the two extreme media, $mu subscript 1 end subscript equals mu subscript 4 end subscript$ .

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