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Physics-

General

Easy

Question

A ray of light travelling in air is incident at a grazing angle on a large transparent slab of thickness $t equals 2.0 m$ . The point of incidence is the origin. The medium has a variable refractive index(y) given by $mu left parenthesis y right parenthesis equals square root of k y plus 1 end root$ Where y is in m and $k equals 0.25 m to the power of negative 1 end exponent$

a) Express a relation between the angle of incidence and the slope of the trajectory m, in terms of the refractive index at that point m ( y)</span

$\frac{\sqrt{μ^{2} - 1}}{\sin^{- 1} (\frac{1}{μ})}$
$\frac{\sqrt{μ^{2} + 1}}{\sin^{- 1} (\frac{1}{μ})}$
$\frac{\sqrt{μ^{2} + 1}}{\sin^{- 1} (\frac{1}{μ})}$
$\frac{μ}{\sin^{- 1} (\frac{1}{μ})}$

The correct answer is: $fraction numerator square root of mu to the power of 2 end exponent minus 1 end root over denominator sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator mu end fraction close parentheses end fraction$

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