Physics-
General
Easy

Question

A small block slides with velocity 0.5 square root of g r end root on the horizontal frictionless surface as shown in the figure. The block leaves the surface at point C. The angle q in the figure is:

  1. c o s to the power of negative 1 end exponent invisible function application fraction numerator 4 over denominator 9 end fraction    
  2. c o s to the power of negative 1 end exponent invisible function application fraction numerator 3 over denominator 4 end fraction    
  3. cos to the power of negative 1 end exponent invisible function application fraction numerator 1 over denominator 2 end fraction    
  4. c o s to the power of negative 1 end exponent invisible function application fraction numerator 4 over denominator 5 end fraction    

The correct answer is: c o s to the power of negative 1 end exponent invisible function application fraction numerator 3 over denominator 4 end fraction

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