A spherical shell, made of material of electrical conductivity -Turito

General

Easy

Physics-

A spherical shell, made of material of electrical conductivity $fraction numerator 10 to the power of 9 end exponent over denominator pi end fraction left parenthesis capital omega minus m right parenthesis to the power of negative 1 end exponent$ has + - thickness t = 2 mm and radius r = 10 cm. In an arrangement, its inside surface is kept at a lower potential than its outside surface The resistance offered by the shell is equal to
"

Physics-General

$5 \times 10^{- 11} Ω$
$5 \times 10^{- 12} Ω$
$5 π \times 10^{- 12} Ω$
$2.5 π \times 10^{- 12} Ω$

Answer:The correct answer is: $5 cross times 10 to the power of negative 11 end exponent capital omega$

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In the shown wire frame, each side of a square (the smallest square) has a resistance R. The equivalent resistance of the circuit between the points A and B is :

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Two circular rings of identical radii and resistance of 36Weach are placed in such a way that they cross each other’s centre C1 and C2 as shown in figure. Conducting joints are made at intersection points A and B of the rings. An ideal cell of emf 20 volts is connected across AB. The power delivered by cell is

From the figure

Two circular rings of identical radii and resistance of 36Weach are placed in such a way that they cross each other’s centre C1 and C2 as shown in figure. Conducting joints are made at intersection points A and B of the rings. An ideal cell of emf 20 volts is connected across AB. The power delivered by cell is

A cell of emf E having an internal resistance 'r ' is connected to an external resistance R. The potential difference ' V ' across the resistance R varies with R as shown by the curve:

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In a practical wheat stone bridge circuit as shown, when one more resistance of 100 W is connected is parallel with unknown resistance ' x ', then ratio $l subscript 1 end subscript$ ₁ $l subscript 2 end subscript$ become ' 2 '. l1 is balance length. AB is a uniform wire. Then value of ' x ' must be:

wheat stone bridge is in balanced condition

In a practical wheat stone bridge circuit as shown, when one more resistance of 100 W is connected is parallel with unknown resistance ' x ', then ratio $l subscript 1 end subscript$ ₁ $l subscript 2 end subscript$ become ' 2 '. l1 is balance length. AB is a uniform wire. Then value of ' x ' must be:

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wheat stone bridge is in balanced condition

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In the figure shown the current flowing through 2 R is :

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In the shown arrangement of the experiment of the meter bridge if AC corresponding to null deflection of galvanometer is x, what would be its value if the radius of the wire AB is doubled?

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In the circuit shown in the figure, the current through

Net resistance of the circuit is 9W.
\ current drawn from the battery

In the circuit shown in the figure, the current through

physics-General

Net resistance of the circuit is 9W.
\ current drawn from the battery

General

maths-

The value of $not stretchy integral subscript 0 end subscript superscript pi end superscript open vertical bar sin to the power of 3 end exponent invisible function application rightwards arrow over short leftwards arrow theta close vertical bar d theta$ is

I equals not stretchy integral subscript 0 end subscript superscript pi end superscript vertical line sin to the power of 3 end exponent invisible function application theta vertical line d theta

Since

sin invisible function application theta

is positive in interval

left parenthesis 0 comma pi right parenthesis

therefore I equals not stretchy integral subscript 0 end subscript superscript pi end superscript sin to the power of 3 end exponent invisible function application theta d theta equals not stretchy integral subscript 0 end subscript superscript pi end superscript sin invisible function application theta left parenthesis 1 minus cos to the power of 2 end exponent invisible function application theta right parenthesis d theta

equals not stretchy integral subscript 0 end subscript superscript pi end superscript sin invisible function application theta d theta plus not stretchy integral subscript 0 end subscript superscript pi end superscript left parenthesis negative sin invisible function application theta right parenthesis cos to the power of 2 end exponent invisible function application theta d theta

equals left square bracket negative cos invisible function application theta right square bracket subscript 0 end subscript superscript pi end superscript plus open parentheses fraction numerator cos to the power of 3 end exponent invisible function application theta over denominator 3 end fraction close parentheses subscript 0 end subscript superscript pi end superscript equals fraction numerator 4 over denominator 3 end fraction

The value of $not stretchy integral subscript 0 end subscript superscript pi end superscript open vertical bar sin to the power of 3 end exponent invisible function application rightwards arrow over short leftwards arrow theta close vertical bar d theta$ is

maths-General

I equals not stretchy integral subscript 0 end subscript superscript pi end superscript vertical line sin to the power of 3 end exponent invisible function application theta vertical line d theta

Since

sin invisible function application theta

is positive in interval

left parenthesis 0 comma pi right parenthesis

therefore I equals not stretchy integral subscript 0 end subscript superscript pi end superscript sin to the power of 3 end exponent invisible function application theta d theta equals not stretchy integral subscript 0 end subscript superscript pi end superscript sin invisible function application theta left parenthesis 1 minus cos to the power of 2 end exponent invisible function application theta right parenthesis d theta

equals not stretchy integral subscript 0 end subscript superscript pi end superscript sin invisible function application theta d theta plus not stretchy integral subscript 0 end subscript superscript pi end superscript left parenthesis negative sin invisible function application theta right parenthesis cos to the power of 2 end exponent invisible function application theta d theta

equals left square bracket negative cos invisible function application theta right square bracket subscript 0 end subscript superscript pi end superscript plus open parentheses fraction numerator cos to the power of 3 end exponent invisible function application theta over denominator 3 end fraction close parentheses subscript 0 end subscript superscript pi end superscript equals fraction numerator 4 over denominator 3 end fraction

General

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In the given figure, $angle 1 equals 8 x minus 6 to the power of ring operator end exponent comma angle 3 equals 3 x plus 4 to the power of ring operator end exponent$ and then find $angle 4 equals 4 x plus 2 to the power of ring operator end exponent$ then find $angle 1.$

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find the value of x in given figure.

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find the value of x in given figure. $blank l parallel to m$ and $text PI|Q end text$

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in $triangle A B C$ ,if $A equals x plus 20 to the power of ring operator comma B with blank below equals 2 open parentheses x minus 10 to the power of ring operator close parentheses comma C C equals 3 over 2 x$ then triangle is ..... triangle

maths-General

General

maths-

Lines PS, QT and RU intersect at a common point ‘O’. P is joined to Q, R to S and T to U to form triangles. Then find the value of $angle P plus angle Q plus angle R plus angle S plus angle T plus angle U equals$

maths-General

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$triangle A B C$ is an Isosceles Triangle, if $A equals 92 to the power of ring operator end exponent$ then find ABD .

maths-General

General

physics-

In which of the following case current shown by ammeter is maximum

Current is maximum when resistance in the circuit is minimum. i.e. when S₁ ,S₃ ,S₅ are closed because then all resistances will be short circuited

I subscript m a x end subscript equals fraction numerator V subscript 0 end subscript over denominator R end fraction

In which of the following case current shown by ammeter is maximum

physics-General

Current is maximum when resistance in the circuit is minimum. i.e. when S₁ ,S₃ ,S₅ are closed because then all resistances will be short circuited

I subscript m a x end subscript equals fraction numerator V subscript 0 end subscript over denominator R end fraction

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Can’t find what you’re looking for?

$5 \times 10^{- 11} Ω$
$5 \times 10^{- 12} Ω$
$5 π \times 10^{- 12} Ω$
$2.5 π \times 10^{- 12} Ω$

Answer:The correct answer is: $5 cross times 10 to the power of negative 11 end exponent capital omega$

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Related Questions to study

In the shown wire frame, each side of a square (the smallest square) has a resistance R. The equivalent resistance of the circuit between the points A and B is :

In the shown wire frame, each side of a square (the smallest square) has a resistance R. The equivalent resistance of the circuit between the points A and B is :

A cell of emf E having an internal resistance 'r ' is connected to an external resistance R. The potential difference ' V ' across the resistance R varies with R as shown by the curve:

A cell of emf E having an internal resistance 'r ' is connected to an external resistance R. The potential difference ' V ' across the resistance R varies with R as shown by the curve:

In the figure shown the current flowing through 2 R is :

In the figure shown the current flowing through 2 R is :

In the shown arrangement of the experiment of the meter bridge if AC corresponding to null deflection of galvanometer is x, what would be its value if the radius of the wire AB is doubled?

In the shown arrangement of the experiment of the meter bridge if AC corresponding to null deflection of galvanometer is x, what would be its value if the radius of the wire AB is doubled?

In the circuit shown in the figure, the current through

In the circuit shown in the figure, the current through

The value of $not stretchy integral subscript 0 end subscript superscript pi end superscript open vertical bar sin to the power of 3 end exponent invisible function application rightwards arrow over short leftwards arrow theta close vertical bar d theta$ is

The value of $not stretchy integral subscript 0 end subscript superscript pi end superscript open vertical bar sin to the power of 3 end exponent invisible function application rightwards arrow over short leftwards arrow theta close vertical bar d theta$ is

In the given figure, $angle 1 equals 8 x minus 6 to the power of ring operator end exponent comma angle 3 equals 3 x plus 4 to the power of ring operator end exponent$ and then find $angle 4 equals 4 x plus 2 to the power of ring operator end exponent$ then find $angle 1.$

In the given figure, $angle 1 equals 8 x minus 6 to the power of ring operator end exponent comma angle 3 equals 3 x plus 4 to the power of ring operator end exponent$ and then find $angle 4 equals 4 x plus 2 to the power of ring operator end exponent$ then find $angle 1.$

find the value of x in given figure.

find the value of x in given figure.

find the value of x in given figure. $blank l parallel to m$ and $text PI|Q end text$

find the value of x in given figure. $blank l parallel to m$ and $text PI|Q end text$

in $triangle A B C$ ,if $A equals x plus 20 to the power of ring operator comma B with blank below equals 2 open parentheses x minus 10 to the power of ring operator close parentheses comma C C equals 3 over 2 x$ then triangle is ..... triangle

in $triangle A B C$ ,if $A equals x plus 20 to the power of ring operator comma B with blank below equals 2 open parentheses x minus 10 to the power of ring operator close parentheses comma C C equals 3 over 2 x$ then triangle is ..... triangle

Lines PS, QT and RU intersect at a common point ‘O’. P is joined to Q, R to S and T to U to form triangles. Then find the value of $angle P plus angle Q plus angle R plus angle S plus angle T plus angle U equals$

Lines PS, QT and RU intersect at a common point ‘O’. P is joined to Q, R to S and T to U to form triangles. Then find the value of $angle P plus angle Q plus angle R plus angle S plus angle T plus angle U equals$

$triangle A B C$ is an Isosceles Triangle, if $A equals 92 to the power of ring operator end exponent$ then find ABD .

$triangle A B C$ is an Isosceles Triangle, if $A equals 92 to the power of ring operator end exponent$ then find ABD .

In which of the following case current shown by ammeter is maximum

In which of the following case current shown by ammeter is maximum

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A spherical shell, made of material of electrical conductivity has + - thickness t = 2 mm and radius r = 10 cm. In an arrangement, its inside surface is kept at a lower potential than its outside surface The resistance offered by the shell is equal to"

Answer:The correct answer is:

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Related Questions to study

In the shown wire frame, each side of a square (the smallest square) has a resistance R. The equivalent resistance of the circuit between the points A and B is :

In the shown wire frame, each side of a square (the smallest square) has a resistance R. The equivalent resistance of the circuit between the points A and B is :

A cell of emf E having an internal resistance 'r ' is connected to an external resistance R. The potential difference ' V ' across the resistance R varies with R as shown by the curve:

A cell of emf E having an internal resistance 'r ' is connected to an external resistance R. The potential difference ' V ' across the resistance R varies with R as shown by the curve:

In a practical wheat stone bridge circuit as shown, when one more resistance of 100 W is connected is parallel with unknown resistance ' x ', then ratio 1 become ' 2 '. l1 is balance length. AB is a uniform wire. Then value of ' x ' must be:

In a practical wheat stone bridge circuit as shown, when one more resistance of 100 W is connected is parallel with unknown resistance ' x ', then ratio 1 become ' 2 '. l1 is balance length. AB is a uniform wire. Then value of ' x ' must be:

In the figure shown the current flowing through 2 R is :

In the figure shown the current flowing through 2 R is :

In the shown arrangement of the experiment of the meter bridge if AC corresponding to null deflection of galvanometer is x, what would be its value if the radius of the wire AB is doubled?

In the shown arrangement of the experiment of the meter bridge if AC corresponding to null deflection of galvanometer is x, what would be its value if the radius of the wire AB is doubled?

In the circuit shown in the figure, the current through

In the circuit shown in the figure, the current through

The value of is

The value of is

In the given figure, and then find then find

In the given figure, and then find then find

find the value of x in given figure.

find the value of x in given figure.

find the value of x in given figure. and

find the value of x in given figure. and

in ,if then triangle is ..... triangle

in ,if then triangle is ..... triangle

Lines PS, QT and RU intersect at a common point ‘O’. P is joined to Q, R to S and T to U to form triangles. Then find the value of

Lines PS, QT and RU intersect at a common point ‘O’. P is joined to Q, R to S and T to U to form triangles. Then find the value of

is an Isosceles Triangle, if then find ABD .

is an Isosceles Triangle, if then find ABD .

In which of the following case current shown by ammeter is maximum

In which of the following case current shown by ammeter is maximum

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Answer:The correct answer is: $5 cross times 10 to the power of negative 11 end exponent capital omega$

The value of $not stretchy integral subscript 0 end subscript superscript pi end superscript open vertical bar sin to the power of 3 end exponent invisible function application rightwards arrow over short leftwards arrow theta close vertical bar d theta$ is

The value of $not stretchy integral subscript 0 end subscript superscript pi end superscript open vertical bar sin to the power of 3 end exponent invisible function application rightwards arrow over short leftwards arrow theta close vertical bar d theta$ is

In the given figure, $angle 1 equals 8 x minus 6 to the power of ring operator end exponent comma angle 3 equals 3 x plus 4 to the power of ring operator end exponent$ and then find $angle 4 equals 4 x plus 2 to the power of ring operator end exponent$ then find $angle 1.$

In the given figure, $angle 1 equals 8 x minus 6 to the power of ring operator end exponent comma angle 3 equals 3 x plus 4 to the power of ring operator end exponent$ and then find $angle 4 equals 4 x plus 2 to the power of ring operator end exponent$ then find $angle 1.$

find the value of x in given figure. $blank l parallel to m$ and $text PI|Q end text$

find the value of x in given figure. $blank l parallel to m$ and $text PI|Q end text$

in $triangle A B C$ ,if $A equals x plus 20 to the power of ring operator comma B with blank below equals 2 open parentheses x minus 10 to the power of ring operator close parentheses comma C C equals 3 over 2 x$ then triangle is ..... triangle

in $triangle A B C$ ,if $A equals x plus 20 to the power of ring operator comma B with blank below equals 2 open parentheses x minus 10 to the power of ring operator close parentheses comma C C equals 3 over 2 x$ then triangle is ..... triangle

Lines PS, QT and RU intersect at a common point ‘O’. P is joined to Q, R to S and T to U to form triangles. Then find the value of $angle P plus angle Q plus angle R plus angle S plus angle T plus angle U equals$

Lines PS, QT and RU intersect at a common point ‘O’. P is joined to Q, R to S and T to U to form triangles. Then find the value of $angle P plus angle Q plus angle R plus angle S plus angle T plus angle U equals$

$triangle A B C$ is an Isosceles Triangle, if $A equals 92 to the power of ring operator end exponent$ then find ABD .

$triangle A B C$ is an Isosceles Triangle, if $A equals 92 to the power of ring operator end exponent$ then find ABD .