Physics-
General
Easy

Question

A string is wrapped around the rim of a wheel of moment of inertia 0.20 kg-m to the power of 2 end exponent and radius 20 cm. The wheel is free to rotate about its axis and initially the wheel is rest. The string is now pulled by a force of 20N. The angular velocity of the string after 5 seconds will be:–

  1. 90 rad/s    
  2. 70 rad/s    
  3. 95 rad/s    
  4. 100 rad/s    

The correct answer is: 100 rad/s

Related Questions to study

General
physics-

In figure, the winch is mounted on an axle, and the 6-sided nut is welded to the winch. By turning the nut with a wrench, a person can rotate the winch. For instance, turning the nut clockwise lifts the block off the ground, because more and more rope gets wrapped around the winch. Three students agree that using a longer wrench makes it easier to turn the winch. But they disagree about why. All three students are talking about the case where the winch is used, over a 10 s time interval, to lift the block one metre off the ground.
Student 1 By using a longer wrench, the person decreases the average force he must exert on the wrench, in order to lift the block one metre in 10s.
Student 2 : Using a longer wrench reduces the work done by the person as he uses the winch to lift the block 1m in 10s.
Student 3 : Using a longer wrench reduces the power that the person must exert to lift the block 1m in 10s.Which of the following is true about student 2 and 3 :-

In figure, the winch is mounted on an axle, and the 6-sided nut is welded to the winch. By turning the nut with a wrench, a person can rotate the winch. For instance, turning the nut clockwise lifts the block off the ground, because more and more rope gets wrapped around the winch. Three students agree that using a longer wrench makes it easier to turn the winch. But they disagree about why. All three students are talking about the case where the winch is used, over a 10 s time interval, to lift the block one metre off the ground.
Student 1 By using a longer wrench, the person decreases the average force he must exert on the wrench, in order to lift the block one metre in 10s.
Student 2 : Using a longer wrench reduces the work done by the person as he uses the winch to lift the block 1m in 10s.
Student 3 : Using a longer wrench reduces the power that the person must exert to lift the block 1m in 10s.Which of the following is true about student 2 and 3 :-

physics-General
General
physics-

A pendulum beating seconds is taken from the earth to a planet having both the mass and radius half as compared to the earth The time period of the pendulum will be

A pendulum beating seconds is taken from the earth to a planet having both the mass and radius half as compared to the earth The time period of the pendulum will be

physics-General
General
physics-

the dimensions of (force constant / mass)blank to the power of 1 divided by 2 end exponent are the same as that

the dimensions of (force constant / mass)blank to the power of 1 divided by 2 end exponent are the same as that

physics-General
parallel
General
maths-

Which of the following statement is true

Which of the following statement is true

maths-General
General
maths-

Find real part of cos to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 3 over denominator 2 end fraction plus fraction numerator i over denominator 2 end fraction close parentheses

Find real part of cos to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 3 over denominator 2 end fraction plus fraction numerator i over denominator 2 end fraction close parentheses

maths-General
General
maths-

If 2 tan to the power of negative 1 end exponent invisible function application left parenthesis cos invisible function application x right parenthesis equals tan to the power of negative 1 end exponent invisible function application left parenthesis 2 text cosec  end text x right parenthesis comma then x =

If 2 tan to the power of negative 1 end exponent invisible function application left parenthesis cos invisible function application x right parenthesis equals tan to the power of negative 1 end exponent invisible function application left parenthesis 2 text cosec  end text x right parenthesis comma then x =

maths-General
parallel
General
maths-

The value of sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 3 over denominator 2 end fraction close parentheses minus sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator 2 end fraction close parentheses is

The value of sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 3 over denominator 2 end fraction close parentheses minus sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator 2 end fraction close parentheses is

maths-General
General
chemistry-

The enthalpy of vapourisation of liquid water using the data :
straight H subscript 2 left parenthesis straight g right parenthesis plus 1 divided by 2 straight O subscript 2 left parenthesis straight g right parenthesis not stretchy rightwards arrow straight H subscript 2 straight O left parenthesis ell right parenthesis semicolon ΔH equals negative 285.77 KJ mol to the power of negative 1 end exponent
straight H subscript 2 left parenthesis straight g right parenthesis plus 1 divided by 2 straight O subscript 2 left parenthesis straight g right parenthesis not stretchy rightwards arrow straight H subscript 2 straight O left parenthesis straight g right parenthesis semicolon ΔH equals negative 241.84 KJ mol to the power of negative 1 end exponent

The enthalpy of vapourisation of liquid water using the data :
straight H subscript 2 left parenthesis straight g right parenthesis plus 1 divided by 2 straight O subscript 2 left parenthesis straight g right parenthesis not stretchy rightwards arrow straight H subscript 2 straight O left parenthesis ell right parenthesis semicolon ΔH equals negative 285.77 KJ mol to the power of negative 1 end exponent
straight H subscript 2 left parenthesis straight g right parenthesis plus 1 divided by 2 straight O subscript 2 left parenthesis straight g right parenthesis not stretchy rightwards arrow straight H subscript 2 straight O left parenthesis straight g right parenthesis semicolon ΔH equals negative 241.84 KJ mol to the power of negative 1 end exponent

chemistry-General
General
chemistry-

The conversion A to B is carried out by the following path :
Given colon capital delta S subscript left parenthesis A rightwards arrow C right parenthesis end subscript equals 50 e.u.,capital delta S subscript left parenthesis C rightwards arrow D right parenthesis end subscript equals 30
e.u.,capital delta S subscript left parenthesis B rightwards arrow D right parenthesis end subscript equals 20 e.u.
Where e.u. is entropy unit then capital delta S subscript left parenthesis A rightwards arrow B right parenthesis end subscript is

The conversion A to B is carried out by the following path :
Given colon capital delta S subscript left parenthesis A rightwards arrow C right parenthesis end subscript equals 50 e.u.,capital delta S subscript left parenthesis C rightwards arrow D right parenthesis end subscript equals 30
e.u.,capital delta S subscript left parenthesis B rightwards arrow D right parenthesis end subscript equals 20 e.u.
Where e.u. is entropy unit then capital delta S subscript left parenthesis A rightwards arrow B right parenthesis end subscript is

chemistry-General
parallel
General
chemistry-

A reversible process is taking place at constant temperature and pressure. Then at equilibrium

A reversible process is taking place at constant temperature and pressure. Then at equilibrium

chemistry-General
General
chemistry-

Consider the following processes :

For B+Drightwards arrowE+2C, capital delta H will be-

Consider the following processes :

For B+Drightwards arrowE+2C, capital delta H will be-

chemistry-General
General
chemistry-

From the following bond energies :
H minus H bond energy : 431.37 text end text k J text end text m o l to the power of negative 1 end exponent
C equals C bond energy : 606.10 text end text k J text end text m o l to the power of negative 1 end exponent
C minus C bond energy : 336.49 text end text k J text end text m o l to the power of negative 1 end exponent
C minus H bond energy : 410.50 text end text k J text end text m o l to the power of negative 1 end exponent
Enthalpy for the reaction,

wilbe:

From the following bond energies :
H minus H bond energy : 431.37 text end text k J text end text m o l to the power of negative 1 end exponent
C equals C bond energy : 606.10 text end text k J text end text m o l to the power of negative 1 end exponent
C minus C bond energy : 336.49 text end text k J text end text m o l to the power of negative 1 end exponent
C minus H bond energy : 410.50 text end text k J text end text m o l to the power of negative 1 end exponent
Enthalpy for the reaction,

wilbe:

chemistry-General
parallel
General
chemistry-

For a phase change 

For a phase change 

chemistry-General
General
chemistry-

The heat change during the reaction 24 gC and 128 gS following the change C plus S subscript 2 end subscript rightwards arrow C S subscript 2 end subscript semicolon capital delta H equals 22 text end text K cal

The heat change during the reaction 24 gC and 128 gS following the change C plus S subscript 2 end subscript rightwards arrow C S subscript 2 end subscript semicolon capital delta H equals 22 text end text K cal

chemistry-General
General
chemistry-

In which reaction ΔS is positive -

In which reaction ΔS is positive -

chemistry-General
parallel

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