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A uniform hollow sphere is released from the top of a fixed inclined plane of inclination 37 to the power of ring operator end exponent and height 3m. It rolls without sliding. The acceleration of the centre of mass of the hollow sphere is

  1. fraction numerator 30 over denominator 7 end fraction m divided by s to the power of 2 end exponent    
  2. fraction numerator 18 over denominator 5 end fraction m divided by s to the power of 2 end exponent    
  3. fraction numerator 9 over denominator 5 end fraction m divided by s to the power of 2 end exponent    
  4. fraction numerator 15 over denominator 7 end fraction m divided by s to the power of 2 end exponent    

The correct answer is: fraction numerator 18 over denominator 5 end fraction m divided by s to the power of 2 end exponent


    a equals fraction numerator g s i n invisible function application theta over denominator 1 plus fraction numerator K to the power of 2 end exponent over denominator R to the power of 2 end exponent end fraction end fraction equals fraction numerator left parenthesis 10 right parenthesis left parenthesis 3 divided by 5 right parenthesis over denominator 1 plus fraction numerator 2 over denominator 3 end fraction end fraction equals fraction numerator 18 over denominator 5 end fraction m s to the power of negative 2 end exponent

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