Physics-
General
Easy

Question

A wedge of mass M fitted with a spring of stiffness 'k' is kept on a smooth horizontal surface. A rod of mass m is kept on the wedge as shown in the figure. System is in equilibrium. Assuming that all surfaces are smooth, the potential energy stored in the spring is:

  1. fraction numerator m g to the power of 2 end exponent t a n to the power of 2 end exponent invisible function application theta over denominator 2 k end fraction    
  2. fraction numerator m to the power of 2 end exponent g t a n to the power of 2 end exponent invisible function application theta over denominator 2 k end fraction    
  3. fraction numerator m to the power of 2 end exponent g to the power of 2 end exponent t a n to the power of 2 end exponent invisible function application theta over denominator 2 k end fraction    
  4. fraction numerator m to the power of 2 end exponent g to the power of 2 end exponent t a n to the power of 2 end exponent invisible function application theta over denominator k end fraction    

The correct answer is: fraction numerator m to the power of 2 end exponent g to the power of 2 end exponent t a n to the power of 2 end exponent invisible function application theta over denominator 2 k end fraction

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A particle 'A' of mass fraction numerator 10 over denominator 7 end fraction kg is moving in the positive x–direction. Its initial position is x = 0 & initial velocity is 1 m divided by s. The velocity at x equals 10 m is:(use the graph given)

A particle 'A' of mass fraction numerator 10 over denominator 7 end fraction kg is moving in the positive x–direction. Its initial position is x = 0 & initial velocity is 1 m divided by s. The velocity at x equals 10 m is:(use the graph given)

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The perimeter of a right triangle is 132 cm. and the sum of the squares of its sides is 6050 cm2. What is the sum of the perpendicular sides –

Hence Choice 1 is correct

The perimeter of a right triangle is 132 cm. and the sum of the squares of its sides is 6050 cm2. What is the sum of the perpendicular sides –

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Hence Choice 1 is correct

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In figure, triangle ABC is right-angled at B. Given that AB = 9 cm, AC = 15 cm, calculate the length of BC

For such questions, we should know the Pythagoras theorem of a triangle.

In figure, triangle ABC is right-angled at B. Given that AB = 9 cm, AC = 15 cm, calculate the length of BC

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For such questions, we should know the Pythagoras theorem of a triangle.

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In DABC, AD is the median through A and E is the produced meets in F figure. Then the value of AF is equal to

Hence AF=(1/3)AC

In DABC, AD is the median through A and E is the produced meets in F figure. Then the value of AF is equal to

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Hence AF=(1/3)AC

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In the figure shown below, angle B equals angle C equals 65 to the power of ring operator end exponent and angle D equals 35 to the power of ring operator end exponent. Which one of the following is a true statement?

Hence Choice 1 is correct

In the figure shown below, angle B equals angle C equals 65 to the power of ring operator end exponent and angle D equals 35 to the power of ring operator end exponent. Which one of the following is a true statement?

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Hence Choice 1 is correct

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One of the angles of a triangle is 65 to the power of ring operator end exponent. If the difference of other two angles is 25 to the power of ring operator end exponent, the largest angle of this triangle has a measure of

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In figure angle X equals 62 to the power of ring operator end exponent comma angle X Y Z equals 54 to the power of ring operator end exponentIf YO and ZO are bisectors of angle X Y Z and angle X Z Y respectively of capital delta X Y Z, find angle Y O Z

Hence choice 4 is correct

In figure angle X equals 62 to the power of ring operator end exponent comma angle X Y Z equals 54 to the power of ring operator end exponentIf YO and ZO are bisectors of angle X Y Z and angle X Z Y respectively of capital delta X Y Z, find angle Y O Z

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Hence choice 4 is correct

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In figure if Q T perpendicular P R comma angle T Q R equals 40 to the power of ring operator end exponentand angle S P R equals 30 to the power of ring operator end exponent, find x and y.

Hence choice 2 is correct

In figure if Q T perpendicular P R comma angle T Q R equals 40 to the power of ring operator end exponentand angle S P R equals 30 to the power of ring operator end exponent, find x and y.

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Hence choice 2 is correct

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In Figure. PS is the bisector of angle Q P R and P T perpendicular Q R. Then angle T P S is equal to

Hence Choice 2 is correct

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Maths-General

Hence Choice 2 is correct

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Statement I: Kinetic energy of 'A' on sliding to J will be greater than the kinetic energy of B on falling to M.
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The blocks A and B shown in the figure have masses M subscript A end subscript equals 5 k g text  and  end text M subscript B end subscript equals 4 k g. The system is released from rest. The speed of B after A has travelled a distance 1 m along the incline is:

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A small block slides with velocity 0.5 square root of g r end root on the horizontal frictionless surface as shown in the figure. The block leaves the surface at point C. The angle q in the figure is:

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