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A weightless thread can bear tension up to3.7 blank k g wt. A stone of mass 500 blank g m s is tied to it and revolved in a circular path of radius 4 blank m in a vertical plane. If g equals 10 blank m s to the power of negative 2 end exponent , then the maximum angular velocity of the stone will be

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  1. 4 blank r a d i a n s divided by s e c    
  2. 16 blank r a d i a n s divided by s e c    
  3. square root of 21 blank r a d i a n s divided by s e c    
  4. 2 blank r a d i a n s divided by s e c    

    Answer:The correct answer is: 4 blank r a d i a n s divided by s e cMax. tension that string can bear equals 3.7 blank k g w t equals 37 blank N
    Tension at lowest point of vertical loop equals m g plus m omega to the power of 2 end exponent r
    equals 0.5 cross times 10 plus 0.5 cross times omega to the power of 2 end exponent cross times 4 equals 5 plus 2 omega to the power of 2 end exponent
    therefore 37 equals 5 plus 2 omega to the power of 2 end exponent rightwards double arrow omega equals 4 blank r a d divided by s

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