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Physics-

General

Easy

Question

ABCD is a square where each side is a uniform wire of resistance 1 $capital omega$ A point E lies on CD such that if a uniform wire of resistance 1 $capital omega$ is connected across AE and constant potential difference is applied across A and C, then B and E are equipotential

$\frac{C E}{E D} = 1$
$\frac{C E}{E D} = \frac{1}{\sqrt{2}}$
$\frac{C E}{E D} = \frac{1}{2}$
$\frac{C E}{E D} = \sqrt{2}$

The correct answer is: $fraction numerator C E over denominator E D end fraction equals square root of 2$

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