Physics-

#### An object is dropped from rest. Its - graph is

Physics-General

#### Answer:The correct answer is: Using

(i)

Comparing with

Equation (i) represents a straight line passing through origin inclined -axis (slope -)

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### Related Questions to study

physics-

#### Which graph represents the uniform acceleration

Since slope of graph remains constant for velocity-time graph

#### Which graph represents the uniform acceleration

physics-General

Since slope of graph remains constant for velocity-time graph

physics-

#### In circuit shown below, the resistances are given in ohm and the battery is assumed ideal with emf equal to 3V. The voltage across the resistance is

Equivalent resistance of the given network

∴ Total current through battery,

Current through resistance

∴ Total current through battery,

Current through resistance

#### In circuit shown below, the resistances are given in ohm and the battery is assumed ideal with emf equal to 3V. The voltage across the resistance is

physics-General

Equivalent resistance of the given network

∴ Total current through battery,

Current through resistance

∴ Total current through battery,

Current through resistance

physics-

#### The resistance across in the figure below will be

Resistance are in parallel

#### The resistance across in the figure below will be

physics-General

Resistance are in parallel

physics-

#### Five equal resistances, each of resistance are connected as shown in figure below. A bettery of volt is connected between The current flowing in will be

#### Five equal resistances, each of resistance are connected as shown in figure below. A bettery of volt is connected between The current flowing in will be

physics-General

maths-

Sine function whose period is 6 is

Sine function whose period is 6 is

maths-General

maths-

The cosecant function whose period is 4 is

The cosecant function whose period is 4 is

maths-General

physics-

#### The resistance is connected as shown in the figure below. Find the equivalent resistance between the points A and B.

) 3

R’=3+7=10

R’ and 10 are in parallel, so

are in series, so

R’=5+5=10

Now, R’ and 10 are in parallel, so

R’=3+7=10

R’ and 10 are in parallel, so

are in series, so

R’=5+5=10

Now, R’ and 10 are in parallel, so

#### The resistance is connected as shown in the figure below. Find the equivalent resistance between the points A and B.

physics-General

) 3

R’=3+7=10

R’ and 10 are in parallel, so

are in series, so

R’=5+5=10

Now, R’ and 10 are in parallel, so

R’=3+7=10

R’ and 10 are in parallel, so

are in series, so

R’=5+5=10

Now, R’ and 10 are in parallel, so

physics-

#### In the circuit shown, the currents are

#### In the circuit shown, the currents are

physics-General

physics-

#### In the circuit shown the equivalent resistance between A and B is

The three resistances between A and B are parallel,

#### In the circuit shown the equivalent resistance between A and B is

physics-General

The three resistances between A and B are parallel,

physics-

#### Six equal resistances are connected between points P, and R as shown in the figure. Then the net resistance will be maximum between

is maximum.

#### Six equal resistances are connected between points P, and R as shown in the figure. Then the net resistance will be maximum between

physics-General

is maximum.

physics-

#### In the circuit given E=0.6V, =100,. The equivalent resistance of the circuit, in ohm is

are in parallel order, so their equivalent resistance

#### In the circuit given E=0.6V, =100,. The equivalent resistance of the circuit, in ohm is

physics-General

are in parallel order, so their equivalent resistance

maths-

#### If , then the period of fis

#### If , then the period of fis

maths-General

physics-

#### The current I drawn from the 5V source will be

The given circuit can be redrawn as

#### The current I drawn from the 5V source will be

physics-General

The given circuit can be redrawn as

physics-

#### The plot represents the flow of current through a wire at three different times.

The ratio of charges flowing through the wire at different times is

) 2 : 3 : 3

Therefore, charge is equal to area under the curve.

∴ Ist rectangle =q=lb=2

IInd rectangle =q=lb=2

Hence, ratio is 1:1:1.

Therefore, charge is equal to area under the curve.

∴ Ist rectangle =q=lb=2

IInd rectangle =q=lb=2

Hence, ratio is 1:1:1.

#### The plot represents the flow of current through a wire at three different times.

The ratio of charges flowing through the wire at different times is

physics-General

) 2 : 3 : 3

Therefore, charge is equal to area under the curve.

∴ Ist rectangle =q=lb=2

IInd rectangle =q=lb=2

Hence, ratio is 1:1:1.

Therefore, charge is equal to area under the curve.

∴ Ist rectangle =q=lb=2

IInd rectangle =q=lb=2

Hence, ratio is 1:1:1.

physics-

#### Consider a thin square sheet of side and thickness made of a material of resistivity The resistance between two opposite faces, shown by the shaded areas in the figure is

is independent of

Hence the correct option is (c).

#### Consider a thin square sheet of side and thickness made of a material of resistivity The resistance between two opposite faces, shown by the shaded areas in the figure is

physics-General

is independent of

Hence the correct option is (c).