General
Easy
Physics-

An object is dropped from rest. Its v-t graph is

Physics-General

    Answer:The correct answer is: Using
    V equals u plus a t
    V equals g t(i)
    Comparing with y equals m x plus c
    Equation (i) represents a straight line passing through origin inclined x-axis (slope -g)

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    Related Questions to study

    General
    physics-

    Which graph represents the uniform acceleration

    Since slope of graph remains constant for velocity-time graph

    Which graph represents the uniform acceleration

    physics-General
    Since slope of graph remains constant for velocity-time graph
    General
    physics-

    In circuit shown below, the resistances are given in ohm and the battery is assumed ideal with emf equal to 3V. The voltage across the resistance R subscript 4 end subscript is

    Equivalent resistance of the given network
    R subscript e q end subscript equals 75 capital omega
    ∴ Total current through battery,
    i equals fraction numerator 3 over denominator 75 end fraction
    i subscript 1 end subscript equals i subscript 2 end subscript equals fraction numerator 3 over denominator 75 cross times 2 end fraction equals fraction numerator 3 over denominator 150 end fraction

    Current through resistance
    R subscript 4 end subscript equals fraction numerator 3 over denominator 150 end fraction cross times fraction numerator 60 over denominator open parentheses 30 plus 60 close parentheses end fraction
    equals fraction numerator 3 over denominator 150 end fraction cross times fraction numerator 60 over denominator 90 end fraction
    equals fraction numerator 2 over denominator 150 end fraction A
    V subscript 4 end subscript equals i subscript 4 end subscript cross times R subscript 4 end subscript
    equals fraction numerator 2 over denominator 150 end fraction cross times 30
    equals fraction numerator 2 over denominator 5 end fraction equals 0.4 blank v o l t

    In circuit shown below, the resistances are given in ohm and the battery is assumed ideal with emf equal to 3V. The voltage across the resistance R subscript 4 end subscript is

    physics-General
    Equivalent resistance of the given network
    R subscript e q end subscript equals 75 capital omega
    ∴ Total current through battery,
    i equals fraction numerator 3 over denominator 75 end fraction
    i subscript 1 end subscript equals i subscript 2 end subscript equals fraction numerator 3 over denominator 75 cross times 2 end fraction equals fraction numerator 3 over denominator 150 end fraction

    Current through resistance
    R subscript 4 end subscript equals fraction numerator 3 over denominator 150 end fraction cross times fraction numerator 60 over denominator open parentheses 30 plus 60 close parentheses end fraction
    equals fraction numerator 3 over denominator 150 end fraction cross times fraction numerator 60 over denominator 90 end fraction
    equals fraction numerator 2 over denominator 150 end fraction A
    V subscript 4 end subscript equals i subscript 4 end subscript cross times R subscript 4 end subscript
    equals fraction numerator 2 over denominator 150 end fraction cross times 30
    equals fraction numerator 2 over denominator 5 end fraction equals 0.4 blank v o l t
    General
    physics-

    The resistance across A blank a n d blank Bin the figure below will be

    Resistance are in parallel
    therefore blank R subscript e q end subscript equals fraction numerator R over denominator 3 end fraction

    The resistance across A blank a n d blank Bin the figure below will be

    physics-General
    Resistance are in parallel
    therefore blank R subscript e q end subscript equals fraction numerator R over denominator 3 end fraction
    General
    physics-

    Five equal resistances, each of resistance R commaare connected as shown in figure below. A bettery of V volt is connected between A blank a n d blank B.The current flowing in F C will be

    I equals fraction numerator V over denominator R end fraction

    therefore blank C u r r e n t blank i n blank F C equals fraction numerator 1 over denominator 2 end fraction equals fraction numerator V over denominator 2 R end fraction

    Five equal resistances, each of resistance R commaare connected as shown in figure below. A bettery of V volt is connected between A blank a n d blank B.The current flowing in F C will be

    physics-General
    I equals fraction numerator V over denominator R end fraction

    therefore blank C u r r e n t blank i n blank F C equals fraction numerator 1 over denominator 2 end fraction equals fraction numerator V over denominator 2 R end fraction
    General
    maths-

    Sine function whose period is 6 is

    Sine function whose period is 6 is

    maths-General
    General
    maths-

    The cosecant function whose period is 4 is

    The cosecant function whose period is 4 is

    maths-General
    General
    physics-

    The resistance is connected as shown in the figure below. Find the equivalent resistance between the points A and B.

    ) 3blank capital omega
    R’=3+7=10capital omega
    R’ and 10capital omega are in parallel, so
    R to the power of ´ end exponent equals fraction numerator 10 cross times 10 over denominator 10 plus 10 end fraction equals 5 capital omega
    R to the power of ´ end exponent a n d blank 5 capital omega blankare in series, so
    R’=5+5=10capital omega
    Now, R’ and 10capital omega are in parallel, so
    R equals fraction numerator 10 cross times 10 over denominator 10 plus 10 end fraction equals 5 capital omega

    The resistance is connected as shown in the figure below. Find the equivalent resistance between the points A and B.

    physics-General
    ) 3blank capital omega
    R’=3+7=10capital omega
    R’ and 10capital omega are in parallel, so
    R to the power of ´ end exponent equals fraction numerator 10 cross times 10 over denominator 10 plus 10 end fraction equals 5 capital omega
    R to the power of ´ end exponent a n d blank 5 capital omega blankare in series, so
    R’=5+5=10capital omega
    Now, R’ and 10capital omega are in parallel, so
    R equals fraction numerator 10 cross times 10 over denominator 10 plus 10 end fraction equals 5 capital omega
    General
    physics-

    In the circuit shown, the currents i subscript 1 end subscript blank a n d blank i subscript 2 end subscriptare

    R equals fraction numerator 12 cross times 4 over denominator 12 plus 4 end fraction plus 2 equals 5 capital omega
    I equals fraction numerator E over denominator R plus r end fraction equals fraction numerator 12 over denominator 6 end fraction equals 2 A
    I subscript 1 end subscript plus I subscript 1 end subscript equals 2 A
    I proportional to fraction numerator 1 over denominator R end fraction
    therefore I subscript 1 end subscript equals 0.5 A comma blank I subscript 2 end subscript equals 1.5 A

    In the circuit shown, the currents i subscript 1 end subscript blank a n d blank i subscript 2 end subscriptare

    physics-General
    R equals fraction numerator 12 cross times 4 over denominator 12 plus 4 end fraction plus 2 equals 5 capital omega
    I equals fraction numerator E over denominator R plus r end fraction equals fraction numerator 12 over denominator 6 end fraction equals 2 A
    I subscript 1 end subscript plus I subscript 1 end subscript equals 2 A
    I proportional to fraction numerator 1 over denominator R end fraction
    therefore I subscript 1 end subscript equals 0.5 A comma blank I subscript 2 end subscript equals 1.5 A
    General
    physics-

    In the circuit shown the equivalent resistance between A and B is

    The three resistances between A and B are parallel,
    fraction numerator 1 over denominator R subscript c o m b end subscript end fraction equals fraction numerator 1 over denominator R subscript 1 end subscript end fraction plus fraction numerator 1 over denominator R subscript 2 end subscript end fraction plus fraction numerator 1 over denominator R subscript 3 end subscript end fraction
    equals fraction numerator 1 over denominator 9 end fraction plus fraction numerator 1 over denominator 9 end fraction plus fraction numerator 1 over denominator 9 end fraction
    fraction numerator 1 over denominator R subscript c o m b end subscript end fraction equals fraction numerator 3 over denominator 9 end fraction
    ⟹ R subscript c o m b end subscript equals 3 capital omega

    In the circuit shown the equivalent resistance between A and B is

    physics-General
    The three resistances between A and B are parallel,
    fraction numerator 1 over denominator R subscript c o m b end subscript end fraction equals fraction numerator 1 over denominator R subscript 1 end subscript end fraction plus fraction numerator 1 over denominator R subscript 2 end subscript end fraction plus fraction numerator 1 over denominator R subscript 3 end subscript end fraction
    equals fraction numerator 1 over denominator 9 end fraction plus fraction numerator 1 over denominator 9 end fraction plus fraction numerator 1 over denominator 9 end fraction
    fraction numerator 1 over denominator R subscript c o m b end subscript end fraction equals fraction numerator 3 over denominator 9 end fraction
    ⟹ R subscript c o m b end subscript equals 3 capital omega
    General
    physics-

    Six equal resistances are connected between points P, Q and R as shown in the figure. Then the net resistance will be maximum between

    R subscript P Q end subscript equals fraction numerator 5 over denominator 11 end fraction r comma blank R subscript Q R end subscript equals fraction numerator 4 over denominator 11 end fraction r a n d R subscript P R end subscript equals fraction numerator 3 over denominator 11 end fraction r
    therefore R subscript P Q end subscriptis maximum.

    Six equal resistances are connected between points P, Q and R as shown in the figure. Then the net resistance will be maximum between

    physics-General
    R subscript P Q end subscript equals fraction numerator 5 over denominator 11 end fraction r comma blank R subscript Q R end subscript equals fraction numerator 4 over denominator 11 end fraction r a n d R subscript P R end subscript equals fraction numerator 3 over denominator 11 end fraction r
    therefore R subscript P Q end subscriptis maximum.
    General
    physics-

    In the circuit given E=0.6V, R subscript 1 end subscript=100capital omega,R subscript 2 end subscript equals R subscript 3 end subscript equals 50 capital omega comma blank R subscript 4 end subscript equals 75 capital omega. The equivalent resistance of the circuit, in ohm is

    R subscript 2 end subscript comma blank R subscript 3 end subscript a n d R subscript 4 end subscript are in parallel order, so their equivalent resistance
    fraction numerator 1 over denominator R to the power of ´ end exponent end fraction equals fraction numerator 1 over denominator R to the power of 2 end exponent end fraction plus fraction numerator 1 over denominator R to the power of 3 end exponent end fraction plus fraction numerator 1 over denominator R to the power of 4 end exponent end fraction
    equals fraction numerator 1 over denominator 50 end fraction plus fraction numerator 1 over denominator 50 end fraction plus fraction numerator 1 over denominator 75 end fraction
    equals fraction numerator 30 plus 30 plus 20 over denominator 1500 end fraction
    equals fraction numerator 80 over denominator 1500 end fraction equals fraction numerator 4 over denominator 75 end fraction
    therefore blank R to the power of ´ end exponent equals fraction numerator 75 over denominator 4 end fraction capital omega
    R equals R subscript 1 end subscript plus R to the power of ´ end exponent equals 100 plus fraction numerator 75 over denominator 4 end fraction
    equals fraction numerator 475 over denominator 4 end fraction capital omega equals 118.75 capital omega

    In the circuit given E=0.6V, R subscript 1 end subscript=100capital omega,R subscript 2 end subscript equals R subscript 3 end subscript equals 50 capital omega comma blank R subscript 4 end subscript equals 75 capital omega. The equivalent resistance of the circuit, in ohm is

    physics-General
    R subscript 2 end subscript comma blank R subscript 3 end subscript a n d R subscript 4 end subscript are in parallel order, so their equivalent resistance
    fraction numerator 1 over denominator R to the power of ´ end exponent end fraction equals fraction numerator 1 over denominator R to the power of 2 end exponent end fraction plus fraction numerator 1 over denominator R to the power of 3 end exponent end fraction plus fraction numerator 1 over denominator R to the power of 4 end exponent end fraction
    equals fraction numerator 1 over denominator 50 end fraction plus fraction numerator 1 over denominator 50 end fraction plus fraction numerator 1 over denominator 75 end fraction
    equals fraction numerator 30 plus 30 plus 20 over denominator 1500 end fraction
    equals fraction numerator 80 over denominator 1500 end fraction equals fraction numerator 4 over denominator 75 end fraction
    therefore blank R to the power of ´ end exponent equals fraction numerator 75 over denominator 4 end fraction capital omega
    R equals R subscript 1 end subscript plus R to the power of ´ end exponent equals 100 plus fraction numerator 75 over denominator 4 end fraction
    equals fraction numerator 475 over denominator 4 end fraction capital omega equals 118.75 capital omega
    General
    maths-

    If f left parenthesis x right parenthesis equals sin squared space open parentheses pi over 8 plus x over 2 close parentheses minus sin squared space open parentheses pi over 8 minus x over 2 close parentheses, then the period of fis

    If f left parenthesis x right parenthesis equals sin squared space open parentheses pi over 8 plus x over 2 close parentheses minus sin squared space open parentheses pi over 8 minus x over 2 close parentheses, then the period of fis

    maths-General
    General
    physics-

    The current I drawn from the 5V source will be

    The given circuit can be redrawn as

    The current I drawn from the 5V source will be

    physics-General
    The given circuit can be redrawn as
    General
    physics-

    The plot represents the flow of current through a wire at three different times.

    The ratio of charges flowing through the wire at different times is

    ) 2 : 3 : 3
    Therefore, charge is equal to area under the curve.
    ∴ Ist rectangle =q=lb=2
    IInd rectangle =q=lb=2
    I I I r d blank t r i a n g l e equals q equals fraction numerator 1 over denominator 2 end fraction l b equals 2
    Hence, ratio is 1:1:1.

    The plot represents the flow of current through a wire at three different times.

    The ratio of charges flowing through the wire at different times is

    physics-General
    ) 2 : 3 : 3
    Therefore, charge is equal to area under the curve.
    ∴ Ist rectangle =q=lb=2
    IInd rectangle =q=lb=2
    I I I r d blank t r i a n g l e equals q equals fraction numerator 1 over denominator 2 end fraction l b equals 2
    Hence, ratio is 1:1:1.
    General
    physics-

    Consider a thin square sheet of side L and thickness t comma made of a material of resistivity rho. The resistance between two opposite faces, shown by the shaded areas in the figure is

    R equals fraction numerator rho open parentheses L close parentheses over denominator A end fraction equals fraction numerator rho L over denominator t L end fraction equals fraction numerator rho over denominator t end fraction
    i e comma blank R is independent of L.
    Hence the correct option is (c).

    Consider a thin square sheet of side L and thickness t comma made of a material of resistivity rho. The resistance between two opposite faces, shown by the shaded areas in the figure is

    physics-General
    R equals fraction numerator rho open parentheses L close parentheses over denominator A end fraction equals fraction numerator rho L over denominator t L end fraction equals fraction numerator rho over denominator t end fraction
    i e comma blank R is independent of L.
    Hence the correct option is (c).