Average torque on a projectile of mass is , initial speed u and-Turito

General

Easy

Physics-

Average torque on a projectile of mass $m$ , initial speed $u$ and angles of projection $theta$ , between initial and final position $P$ and $Q$ as shown in figure about the point of projection is

Physics-General

$\frac{1}{2} m u^{2} \sin 2 θ$
$m u^{2} \sin θ$
$m u^{2} \cos θ$
$\frac{1}{2} m u^{2} \cos 2 θ$

Answer:The correct answer is: $fraction numerator 1 over denominator 2 end fraction blank m u to the power of 2 end exponent sin invisible function application 2 theta$ Time of flight. $T equals fraction numerator 2 u sin invisible function application theta over denominator g end fraction$
Horizontal range, $R equals fraction numerator u to the power of 2 end exponent sin invisible function application 2 theta over denominator g end fraction$
Change in angular momentum,
$open vertical bar d stack L with rightwards arrow on top close vertical bar equals open vertical bar stack L with rightwards arrow on top subscript f end subscript minus stack L with rightwards arrow on top subscript i end subscript close vertical bar$ about point of projection
$equals left parenthesis m u sin invisible function application theta right parenthesis cross times fraction numerator u to the power of 2 end exponent sin invisible function application 2 theta over denominator g end fraction$
$equals fraction numerator m u to the power of 3 end exponent sin invisible function application theta sin invisible function application 2 theta over denominator g end fraction$
$T o r q u e blank open vertical bar stack tau with rightwards arrow on top close vertical bar equals fraction numerator c h a n g e blank i n blank a n g u l a r blank m o m e n t u m over denominator t i m e blank o f blank f l i g h t end fraction$
$equals open vertical bar fraction numerator d stack L with rightwards arrow on top over denominator T end fraction close vertical bar$

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Related Questions to study

General

physics-

A particle originally at a rest at the highest point of a smooth circle in a vertical plane, is gently pushed and starts sliding along the circle. It will leave the circle at a vertical distance $h$ below the highest point such that

From law of conservation of energy, potential energy of fall gets converted to kinetic energy.

therefore blank P E equals K E

m g h equals fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent

o r blank v equals square root of 2 g h end root blank open parentheses i close parentheses

Also, the horizontal component of force is equal centrifugal force.

therefore blank m g cos invisible function application theta equals fraction numerator m v to the power of 2 end exponent over denominator R end fraction open parentheses i i close parentheses

From Eq. (i)

therefore blank m g cos invisible function application theta equals fraction numerator 2 m g h over denominator R end fraction blank open parentheses i i i close parentheses

From

increment A O B comma

cos invisible function application theta equals fraction numerator left parenthesis R minus h over denominator R end fraction

⟹ m g open parentheses fraction numerator open parentheses R minus h close parentheses over denominator R end fraction close parentheses equals fraction numerator 2 m g h over denominator R end fraction

⟹ blank 3 h equals R

⟹ h equals fraction numerator R over denominator 3 end fraction

A particle originally at a rest at the highest point of a smooth circle in a vertical plane, is gently pushed and starts sliding along the circle. It will leave the circle at a vertical distance $h$ below the highest point such that

physics-General

From law of conservation of energy, potential energy of fall gets converted to kinetic energy.

therefore blank P E equals K E

m g h equals fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent

o r blank v equals square root of 2 g h end root blank open parentheses i close parentheses

Also, the horizontal component of force is equal centrifugal force.

therefore blank m g cos invisible function application theta equals fraction numerator m v to the power of 2 end exponent over denominator R end fraction open parentheses i i close parentheses

From Eq. (i)

therefore blank m g cos invisible function application theta equals fraction numerator 2 m g h over denominator R end fraction blank open parentheses i i i close parentheses

From

increment A O B comma

cos invisible function application theta equals fraction numerator left parenthesis R minus h over denominator R end fraction

⟹ m g open parentheses fraction numerator open parentheses R minus h close parentheses over denominator R end fraction close parentheses equals fraction numerator 2 m g h over denominator R end fraction

⟹ blank 3 h equals R

⟹ h equals fraction numerator R over denominator 3 end fraction

General

physics-

A 0.098 kg block slides down a frictionless track as shown. The vertical component of the velocity of block at $A$ is

fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent equals m g open parentheses 3 minus 1 close parentheses equals 2 m g

v equals square root of 4 g equals 2 square root of g

Vertical component at

A equals 2 square root of g sin invisible function application 30 degree equals square root of g

A 0.098 kg block slides down a frictionless track as shown. The vertical component of the velocity of block at $A$ is

physics-General

fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent equals m g open parentheses 3 minus 1 close parentheses equals 2 m g

v equals square root of 4 g equals 2 square root of g

Vertical component at

A equals 2 square root of g sin invisible function application 30 degree equals square root of g

General

physics-

A small mass $m$ is attached to a massless string whose other end is fixed at $P$ as shown in the figure. The mass is undergoing circular motion in the $x minus y$ plane with center at $O$ and constant angular speed $omega$ . If the angular momentum of the system, calculated about $O blank$ and $P$ are denoted by $stack L with rightwards arrow on top subscript O end subscript$ and $stack L with rightwards arrow on top subscript P end subscript$ respectively, then

physics-General

General

chemistry-

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is $v subscript 0 end subscript$ , then the ratio of tensions in the three sections of the string is

Let

omega

is the angular speed of revolution

T subscript 3 end subscript equals m omega to the power of 2 end exponent 3 l

T subscript 2 end subscript minus T subscript 3 end subscript equals m omega to the power of 2 end exponent 2 l rightwards double arrow T subscript 2 end subscript equals m omega to the power of 2 end exponent 5 l

T subscript 1 end subscript minus T subscript 2 end subscript equals m omega to the power of 2 end exponent l rightwards double arrow T subscript 1 end subscript equals m omega to the power of 2 end exponent 6 l

T subscript 3 end subscript colon T subscript 2 end subscript colon T subscript 1 end subscript equals 3 blank colon 5 blank colon 6

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is $v subscript 0 end subscript$ , then the ratio of tensions in the three sections of the string is

physics-General

Let

omega

is the angular speed of revolution

T subscript 3 end subscript equals m omega to the power of 2 end exponent 3 l

T subscript 2 end subscript minus T subscript 3 end subscript equals m omega to the power of 2 end exponent 2 l rightwards double arrow T subscript 2 end subscript equals m omega to the power of 2 end exponent 5 l

T subscript 1 end subscript minus T subscript 2 end subscript equals m omega to the power of 2 end exponent l rightwards double arrow T subscript 1 end subscript equals m omega to the power of 2 end exponent 6 l

T subscript 3 end subscript colon T subscript 2 end subscript colon T subscript 1 end subscript equals 3 blank colon 5 blank colon 6

General

chemistry-

Wurtz reaction of methyl iodide yields an organic compound X. which of the following reaction also yields X ?

open parentheses A close parentheses 2 C H subscript 3 end subscript I plus 2 N a rightwards arrow stack C H subscript 3 end subscript minus C H subscript 3 end subscript with E t h a n e open parentheses X close parentheses below plus 2 N a I

Error converting from MathML to accessible text.

Wurtz reaction of methyl iodide yields an organic compound X. which of the following reaction also yields X ?

chemistry-General

open parentheses A close parentheses 2 C H subscript 3 end subscript I plus 2 N a rightwards arrow stack C H subscript 3 end subscript minus C H subscript 3 end subscript with E t h a n e open parentheses X close parentheses below plus 2 N a I

Error converting from MathML to accessible text.

General

physics-

Two particles 1 and 2 are projected with same speed $v$ as shown in figure. Particle 2 is on the ground and particle 1 is at a height $h$ from the ground and at a horizontal distance $s$ from particle 2. If a graph is plotted between $v$ and $s$ for the condition of collision of the two then ( $v$ on $y$ -axis and $s$ on $x$ -axis)

Assuming particle 2 to be at rest, substituting in

y equals x tan invisible function application theta minus fraction numerator g x to the power of 2 end exponent over denominator 2 u to the power of 2 end exponent cos to the power of 2 end exponent invisible function application theta end fraction blank left parenthesis theta equals 0 degree right parenthesis

We have

negative h equals fraction numerator negative g over denominator 2 left parenthesis 4 v to the power of 2 end exponent right parenthesis end fraction

v equals square root of fraction numerator g over denominator 8 h end fraction end root

Which is a straight line passing through origin with slope

square root of fraction numerator g over denominator 8 h end fraction end root

Two particles 1 and 2 are projected with same speed $v$ as shown in figure. Particle 2 is on the ground and particle 1 is at a height $h$ from the ground and at a horizontal distance $s$ from particle 2. If a graph is plotted between $v$ and $s$ for the condition of collision of the two then ( $v$ on $y$ -axis and $s$ on $x$ -axis)

physics-General

Assuming particle 2 to be at rest, substituting in

y equals x tan invisible function application theta minus fraction numerator g x to the power of 2 end exponent over denominator 2 u to the power of 2 end exponent cos to the power of 2 end exponent invisible function application theta end fraction blank left parenthesis theta equals 0 degree right parenthesis

We have

negative h equals fraction numerator negative g over denominator 2 left parenthesis 4 v to the power of 2 end exponent right parenthesis end fraction

v equals square root of fraction numerator g over denominator 8 h end fraction end root

Which is a straight line passing through origin with slope

square root of fraction numerator g over denominator 8 h end fraction end root

General

chemistry-

The name of monomers present in the following polymer

chemistry-General

General

chemistry-

The major product obtained on monobromination (with Br₂/ FeBr₃) of the following compound A is

Since both OCH₃ and CH₃ are o. p directing, the following products are possible

Since OCH₃ group is bulkier than CH₃ i.e., sterically less hindered ; product (I) is formed Therefore option (B) is correct

The major product obtained on monobromination (with Br₂/ FeBr₃) of the following compound A is

chemistry-General

Since both OCH₃ and CH₃ are o. p directing, the following products are possible

Since OCH₃ group is bulkier than CH₃ i.e., sterically less hindered ; product (I) is formed Therefore option (B) is correct

General

physics-

A weightless thread can bear tension up to $3.7 blank k g$ wt. A stone of mass $500 blank g m s$ is tied to it and revolved in a circular path of radius $4 blank m$ in a vertical plane. If $g equals 10 blank m s to the power of negative 2 end exponent$ , then the maximum angular velocity of the stone will be

Max. tension that string can bear

equals 3.7 blank k g w t equals 37 blank N

Tension at lowest point of vertical loop

equals m g plus m omega to the power of 2 end exponent r

equals 0.5 cross times 10 plus 0.5 cross times omega to the power of 2 end exponent cross times 4 equals 5 plus 2 omega to the power of 2 end exponent

therefore 37 equals 5 plus 2 omega to the power of 2 end exponent rightwards double arrow omega equals 4 blank r a d divided by s

A weightless thread can bear tension up to $3.7 blank k g$ wt. A stone of mass $500 blank g m s$ is tied to it and revolved in a circular path of radius $4 blank m$ in a vertical plane. If $g equals 10 blank m s to the power of negative 2 end exponent$ , then the maximum angular velocity of the stone will be

physics-General

Max. tension that string can bear

equals 3.7 blank k g w t equals 37 blank N

Tension at lowest point of vertical loop

equals m g plus m omega to the power of 2 end exponent r

equals 0.5 cross times 10 plus 0.5 cross times omega to the power of 2 end exponent cross times 4 equals 5 plus 2 omega to the power of 2 end exponent

therefore 37 equals 5 plus 2 omega to the power of 2 end exponent rightwards double arrow omega equals 4 blank r a d divided by s

General

chemistry-

Out of phenoxide and ethnocide ion, only ethoxide ion will react with iodoethane to give diethyl ether

C subscript 2 end subscript H subscript 5 end subscript I plus to the power of minus end exponent O C subscript 2 end subscript H subscript 5 end subscript rightwards arrow C subscript 2 end subscript H subscript 5 end subscript minus O minus C subscript 2 end subscript H subscript 5 end subscript plus I to the power of minus end exponent

chemistry-General

Out of phenoxide and ethnocide ion, only ethoxide ion will react with iodoethane to give diethyl ether

C subscript 2 end subscript H subscript 5 end subscript I plus to the power of minus end exponent O C subscript 2 end subscript H subscript 5 end subscript rightwards arrow C subscript 2 end subscript H subscript 5 end subscript minus O minus C subscript 2 end subscript H subscript 5 end subscript plus I to the power of minus end exponent

General

physics-

A man 80 kg is supported by two cables as shown in the figure. Then the ratio of tensions $T subscript 1 end subscript$ and $T subscript 2 end subscript$ is

From figure in equilibrium position

T subscript 1 end subscript s i n 30 degree equals T subscript 2 end subscript s i n 60 degree

T subscript 1 end subscript cross times fraction numerator 1 over denominator 2 end fraction equals T subscript 2 end subscript cross times fraction numerator square root of 3 over denominator 2 end fraction

fraction numerator T subscript 1 end subscript over denominator T subscript 2 end subscript end fraction equals square root of 3

A man 80 kg is supported by two cables as shown in the figure. Then the ratio of tensions $T subscript 1 end subscript$ and $T subscript 2 end subscript$ is

physics-General

From figure in equilibrium position

T subscript 1 end subscript s i n 30 degree equals T subscript 2 end subscript s i n 60 degree

T subscript 1 end subscript cross times fraction numerator 1 over denominator 2 end fraction equals T subscript 2 end subscript cross times fraction numerator square root of 3 over denominator 2 end fraction

fraction numerator T subscript 1 end subscript over denominator T subscript 2 end subscript end fraction equals square root of 3

General

chemistry-

Which of the carbon atoms present in the molecule given below are asymmetric?

(ii) and (iii) carbon atoms are asymmetric

Which of the carbon atoms present in the molecule given below are asymmetric?

chemistry-General

(ii) and (iii) carbon atoms are asymmetric

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Average torque on a projectile of mass $m$ , initial speed $u$ and angles of projection $theta$ , between initial and final position $P$ and $Q$ as shown in figure about the point of projection is

$\frac{1}{2} m u^{2} \sin 2 θ$
$m u^{2} \sin θ$
$m u^{2} \cos θ$
$\frac{1}{2} m u^{2} \cos 2 θ$

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Related Questions to study

A particle originally at a rest at the highest point of a smooth circle in a vertical plane, is gently pushed and starts sliding along the circle. It will leave the circle at a vertical distance $h$ below the highest point such that

A particle originally at a rest at the highest point of a smooth circle in a vertical plane, is gently pushed and starts sliding along the circle. It will leave the circle at a vertical distance $h$ below the highest point such that

A 0.098 kg block slides down a frictionless track as shown. The vertical component of the velocity of block at $A$ is

A 0.098 kg block slides down a frictionless track as shown. The vertical component of the velocity of block at $A$ is

The monomer used to produce neoprene is

The monomer used to produce neoprene is

What is ‘A’ in the following reaction?

What is ‘A’ in the following reaction?

What is ‘A’ in the following reaction?

What is ‘A’ in the following reaction?

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is $v subscript 0 end subscript$ , then the ratio of tensions in the three sections of the string is

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is $v subscript 0 end subscript$ , then the ratio of tensions in the three sections of the string is

Wurtz reaction of methyl iodide yields an organic compound X. which of the following reaction also yields X ?

Wurtz reaction of methyl iodide yields an organic compound X. which of the following reaction also yields X ?

The name of monomers present in the following polymer

The name of monomers present in the following polymer

The major product obtained on monobromination (with Br₂/ FeBr₃) of the following compound A is

The major product obtained on monobromination (with Br₂/ FeBr₃) of the following compound A is

A man 80 kg is supported by two cables as shown in the figure. Then the ratio of tensions $T subscript 1 end subscript$ and $T subscript 2 end subscript$ is

A man 80 kg is supported by two cables as shown in the figure. Then the ratio of tensions $T subscript 1 end subscript$ and $T subscript 2 end subscript$ is

Which of the carbon atoms present in the molecule given below are asymmetric?

Which of the carbon atoms present in the molecule given below are asymmetric?

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Average torque on a projectile of mass , initial speed and angles of projection , between initial and final position and as shown in figure about the point of projection is

Answer:The correct answer is: Time of flight. Horizontal range, Change in angular momentum, about point of projection

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A particle originally at a rest at the highest point of a smooth circle in a vertical plane, is gently pushed and starts sliding along the circle. It will leave the circle at a vertical distance below the highest point such that

A particle originally at a rest at the highest point of a smooth circle in a vertical plane, is gently pushed and starts sliding along the circle. It will leave the circle at a vertical distance below the highest point such that

A 0.098 kg block slides down a frictionless track as shown. The vertical component of the velocity of block at is

A 0.098 kg block slides down a frictionless track as shown. The vertical component of the velocity of block at is

A small mass is attached to a massless string whose other end is fixed at as shown in the figure. The mass is undergoing circular motion in the plane with center at and constant angular speed . If the angular momentum of the system, calculated about and are denoted by and respectively, then

A small mass is attached to a massless string whose other end is fixed at as shown in the figure. The mass is undergoing circular motion in the plane with center at and constant angular speed . If the angular momentum of the system, calculated about and are denoted by and respectively, then

The monomer used to produce neoprene is

The monomer used to produce neoprene is

What is ‘A’ in the following reaction?

What is ‘A’ in the following reaction?

What is ‘A’ in the following reaction?

What is ‘A’ in the following reaction?

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is , then the ratio of tensions in the three sections of the string is

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is , then the ratio of tensions in the three sections of the string is

Wurtz reaction of methyl iodide yields an organic compound X. which of the following reaction also yields X ?

Wurtz reaction of methyl iodide yields an organic compound X. which of the following reaction also yields X ?

Two particles 1 and 2 are projected with same speed as shown in figure. Particle 2 is on the ground and particle 1 is at a height from the ground and at a horizontal distance from particle 2. If a graph is plotted between and for the condition of collision of the two then ( on -axis and on -axis)

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The name of monomers present in the following polymer

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The major product obtained on monobromination (with Br2/ FeBr3) of the following compound A is

The major product obtained on monobromination (with Br2/ FeBr3) of the following compound A is

A weightless thread can bear tension up to wt. A stone of mass is tied to it and revolved in a circular path of radius in a vertical plane. If , then the maximum angular velocity of the stone will be

A weightless thread can bear tension up to wt. A stone of mass is tied to it and revolved in a circular path of radius in a vertical plane. If , then the maximum angular velocity of the stone will be

A man 80 kg is supported by two cables as shown in the figure. Then the ratio of tensions and is

A man 80 kg is supported by two cables as shown in the figure. Then the ratio of tensions and is

Which of the carbon atoms present in the molecule given below are asymmetric?

Which of the carbon atoms present in the molecule given below are asymmetric?

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Average torque on a projectile of mass $m$ , initial speed $u$ and angles of projection $theta$ , between initial and final position $P$ and $Q$ as shown in figure about the point of projection is

A particle originally at a rest at the highest point of a smooth circle in a vertical plane, is gently pushed and starts sliding along the circle. It will leave the circle at a vertical distance $h$ below the highest point such that

A particle originally at a rest at the highest point of a smooth circle in a vertical plane, is gently pushed and starts sliding along the circle. It will leave the circle at a vertical distance $h$ below the highest point such that

A 0.098 kg block slides down a frictionless track as shown. The vertical component of the velocity of block at $A$ is

A 0.098 kg block slides down a frictionless track as shown. The vertical component of the velocity of block at $A$ is

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is $v subscript 0 end subscript$ , then the ratio of tensions in the three sections of the string is

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is $v subscript 0 end subscript$ , then the ratio of tensions in the three sections of the string is

The major product obtained on monobromination (with Br₂/ FeBr₃) of the following compound A is

The major product obtained on monobromination (with Br₂/ FeBr₃) of the following compound A is

A man 80 kg is supported by two cables as shown in the figure. Then the ratio of tensions $T subscript 1 end subscript$ and $T subscript 2 end subscript$ is

A man 80 kg is supported by two cables as shown in the figure. Then the ratio of tensions $T subscript 1 end subscript$ and $T subscript 2 end subscript$ is