Physics-
General
Easy

Question

Consider a body, shown in figure, consisting of two identical balls, each of mass M connected by a light rigid rod. If an impulseJ equals M v is impared to the body at one of its ends, what would be its angular velocity?

  1. v divided by L    
  2. 2 v divided by L    
  3. v divided by 3 L    
  4. v divided by 4 L    

The correct answer is: v divided by L


    Let omega be the angular velocity of the rod. Applying ,
    Angular impulse = change in angular momentum about centre of mass of the system

    J. fraction numerator L over denominator 2 end fraction equals I subscript c end subscript omega
    therefore open parentheses M v close parentheses open parentheses fraction numerator L over denominator 2 end fraction close parentheses equals open parentheses 2 close parentheses open parentheses fraction numerator M L to the power of 2 end exponent over denominator 4 end fraction close parentheses. omega
    therefore omega equals fraction numerator v over denominator L end fraction

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