General
Easy
Physics-

Consider the given velocity-time graph It represents the motion of

Physics-General

  1. A projectile projected vertically upward, from a point    
  2. A bullet fired horizontally from the top of a tower    
  3. A car with constant acceleration along a straight road    
  4. An electron in the hydrogen atom    

    Answer:The correct answer is: A projectile projected vertically upward, from a point

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    General
    physics-

    An aero plane moving horizontally at a speed of 200 blank m divided by s and at a height of 8.0 cross times 10 to the power of 3 end exponent blank m is to drop a bomb on a target. At what horizontal distance from the target should the bomb be released

    Horizontal distance travelled by the bomb S equals u cross times t
    equals 200 cross times square root of fraction numerator 2 h over denominator g end fraction end root equals 200 cross times square root of fraction numerator 2 cross times 8 cross times 10 to the power of 3 end exponent over denominator 9.8 end fraction end root equals 8.081 blank k m

    An aero plane moving horizontally at a speed of 200 blank m divided by s and at a height of 8.0 cross times 10 to the power of 3 end exponent blank m is to drop a bomb on a target. At what horizontal distance from the target should the bomb be released

    physics-General
    Horizontal distance travelled by the bomb S equals u cross times t
    equals 200 cross times square root of fraction numerator 2 h over denominator g end fraction end root equals 200 cross times square root of fraction numerator 2 cross times 8 cross times 10 to the power of 3 end exponent over denominator 9.8 end fraction end root equals 8.081 blank k m
    General
    chemistry-

    Which of the carbon atoms present in the molecule given below are asymmetric?

    (ii) and (iii) carbon atoms are asymmetric

    Which of the carbon atoms present in the molecule given below are asymmetric?

    chemistry-General
    (ii) and (iii) carbon atoms are asymmetric
    General
    chemistry-

    Out of phenoxide and ethnocide ion, only ethoxide ion will react with iodoethane to give diethyl ether C subscript 2 end subscript H subscript 5 end subscript I plus to the power of minus end exponent O C subscript 2 end subscript H subscript 5 end subscript rightwards arrow C subscript 2 end subscript H subscript 5 end subscript minus O minus C subscript 2 end subscript H subscript 5 end subscript plus I to the power of minus end exponent

    chemistry-General
    Out of phenoxide and ethnocide ion, only ethoxide ion will react with iodoethane to give diethyl ether C subscript 2 end subscript H subscript 5 end subscript I plus to the power of minus end exponent O C subscript 2 end subscript H subscript 5 end subscript rightwards arrow C subscript 2 end subscript H subscript 5 end subscript minus O minus C subscript 2 end subscript H subscript 5 end subscript plus I to the power of minus end exponent
    General
    chemistry-

    Which of the following compounds will undergo racemization when solution of KOH hydrolyses?
    i)
    ii) CH3CH2CH2Cl
    iii)
    iv) </span

    Due to chirality of open parentheses H minus stack stack stack stack C with vertical line below with C subscript 2 end subscript H subscript 5 end subscript below with vertical line on top with C H subscript 3 end subscript on top minus C l close parentheses only compound (d) will undergo reacemisation

    Which of the following compounds will undergo racemization when solution of KOH hydrolyses?
    i)
    ii) CH3CH2CH2Cl
    iii)
    iv) </span

    chemistry-General
    Due to chirality of open parentheses H minus stack stack stack stack C with vertical line below with C subscript 2 end subscript H subscript 5 end subscript below with vertical line on top with C H subscript 3 end subscript on top minus C l close parentheses only compound (d) will undergo reacemisation
    General
    chemistry-

    The major product obtained on monobromination (with Br2/ FeBr3) of the following compound A is

    Since both OCH3 and CH3 are o. p directing, the following products are possible

    Since OCH3 group is bulkier than CH3 i.e., sterically less hindered ; product (I) is formed Therefore option (B) is correct

    The major product obtained on monobromination (with Br2/ FeBr3) of the following compound A is

    chemistry-General
    Since both OCH3 and CH3 are o. p directing, the following products are possible

    Since OCH3 group is bulkier than CH3 i.e., sterically less hindered ; product (I) is formed Therefore option (B) is correct
    General
    chemistry-

    The name of monomers present in the following polymer

    The name of monomers present in the following polymer

    chemistry-General
    General
    physics-

    Two particles 1 and 2 are projected with same speed v as shown in figure. Particle 2 is on the ground and particle 1 is at a height h from the ground and at a horizontal distance s from particle 2. If a graph is plotted between v and s for the condition of collision of the two then (v on y-axis and s on x-axis)

    Assuming particle 2 to be at rest, substituting in
    y equals x tan invisible function application theta minus fraction numerator g x to the power of 2 end exponent over denominator 2 u to the power of 2 end exponent cos to the power of 2 end exponent invisible function application theta end fraction blank left parenthesis theta equals 0 degree right parenthesis

    We have negative h equals fraction numerator negative g over denominator 2 left parenthesis 4 v to the power of 2 end exponent right parenthesis end fraction
    or v equals square root of fraction numerator g over denominator 8 h end fraction end root
    Which is a straight line passing through origin with slopesquare root of fraction numerator g over denominator 8 h end fraction end root

    Two particles 1 and 2 are projected with same speed v as shown in figure. Particle 2 is on the ground and particle 1 is at a height h from the ground and at a horizontal distance s from particle 2. If a graph is plotted between v and s for the condition of collision of the two then (v on y-axis and s on x-axis)

    physics-General
    Assuming particle 2 to be at rest, substituting in
    y equals x tan invisible function application theta minus fraction numerator g x to the power of 2 end exponent over denominator 2 u to the power of 2 end exponent cos to the power of 2 end exponent invisible function application theta end fraction blank left parenthesis theta equals 0 degree right parenthesis

    We have negative h equals fraction numerator negative g over denominator 2 left parenthesis 4 v to the power of 2 end exponent right parenthesis end fraction
    or v equals square root of fraction numerator g over denominator 8 h end fraction end root
    Which is a straight line passing through origin with slopesquare root of fraction numerator g over denominator 8 h end fraction end root
    General
    chemistry-

    Wurtz reaction of methyl iodide yields an organic compound X. which of the following reaction also yields X ?

    open parentheses A close parentheses 2 C H subscript 3 end subscript I plus 2 N a rightwards arrow stack C H subscript 3 end subscript minus C H subscript 3 end subscript with E t h a n e open parentheses X close parentheses below plus 2 N a I
    Error converting from MathML to accessible text.

    Wurtz reaction of methyl iodide yields an organic compound X. which of the following reaction also yields X ?

    chemistry-General
    open parentheses A close parentheses 2 C H subscript 3 end subscript I plus 2 N a rightwards arrow stack C H subscript 3 end subscript minus C H subscript 3 end subscript with E t h a n e open parentheses X close parentheses below plus 2 N a I
    Error converting from MathML to accessible text.
    General
    maths-

    If A is a square matrix of order 3 then ∣ Adj open parentheses bold Adj space A squared close parentheses ∣ equals

    If A is a square matrix of order 3 then ∣ Adj open parentheses bold Adj space A squared close parentheses ∣ equals

    maths-General
    General
    chemistry-

    In the reaction R – OH + HX → R – X + H2O, The reactivity of different alcohols is

    This is because the order the relative stabilities of the carbocation formed in this reactions is : tertiary > secondary > primary.

    In the reaction R – OH + HX → R – X + H2O, The reactivity of different alcohols is

    chemistry-General
    This is because the order the relative stabilities of the carbocation formed in this reactions is : tertiary > secondary > primary.
    General
    physics-

    A particle originally at a rest at the highest point of a smooth circle in a vertical plane, is gently pushed and starts sliding along the circle. It will leave the circle at a vertical distance h below the highest point such that

    From law of conservation of energy, potential energy of fall gets converted to kinetic energy.

    therefore blank P E equals K E
    m g h equals fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent
    o r blank v equals square root of 2 g h end root blank open parentheses i close parentheses
    Also, the horizontal component of force is equal centrifugal force.
    therefore blank m g cos invisible function application theta equals fraction numerator m v to the power of 2 end exponent over denominator R end fraction open parentheses i i close parentheses
    From Eq. (i)
    therefore blank m g cos invisible function application theta equals fraction numerator 2 m g h over denominator R end fraction blank open parentheses i i i close parentheses
    From increment A O B comma
    cos invisible function application theta equals fraction numerator left parenthesis R minus h over denominator R end fraction
    ⟹ m g open parentheses fraction numerator open parentheses R minus h close parentheses over denominator R end fraction close parentheses equals fraction numerator 2 m g h over denominator R end fraction
    ⟹ blank 3 h equals R
    ⟹ h equals fraction numerator R over denominator 3 end fraction

    A particle originally at a rest at the highest point of a smooth circle in a vertical plane, is gently pushed and starts sliding along the circle. It will leave the circle at a vertical distance h below the highest point such that

    physics-General
    From law of conservation of energy, potential energy of fall gets converted to kinetic energy.

    therefore blank P E equals K E
    m g h equals fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent
    o r blank v equals square root of 2 g h end root blank open parentheses i close parentheses
    Also, the horizontal component of force is equal centrifugal force.
    therefore blank m g cos invisible function application theta equals fraction numerator m v to the power of 2 end exponent over denominator R end fraction open parentheses i i close parentheses
    From Eq. (i)
    therefore blank m g cos invisible function application theta equals fraction numerator 2 m g h over denominator R end fraction blank open parentheses i i i close parentheses
    From increment A O B comma
    cos invisible function application theta equals fraction numerator left parenthesis R minus h over denominator R end fraction
    ⟹ m g open parentheses fraction numerator open parentheses R minus h close parentheses over denominator R end fraction close parentheses equals fraction numerator 2 m g h over denominator R end fraction
    ⟹ blank 3 h equals R
    ⟹ h equals fraction numerator R over denominator 3 end fraction
    General
    physics-

    Average torque on a projectile of mass m, initial speed u and angles of projection theta, between initial and final position P and Q as shown in figure about the point of projection is

    Time of flight. T equals fraction numerator 2 u sin invisible function application theta over denominator g end fraction
    Horizontal range, R equals fraction numerator u to the power of 2 end exponent sin invisible function application 2 theta over denominator g end fraction
    Change in angular momentum,
    open vertical bar d stack L with rightwards arrow on top close vertical bar equals open vertical bar stack L with rightwards arrow on top subscript f end subscript minus stack L with rightwards arrow on top subscript i end subscript close vertical bar about point of projection
    equals left parenthesis m u sin invisible function application theta right parenthesis cross times fraction numerator u to the power of 2 end exponent sin invisible function application 2 theta over denominator g end fraction
    equals fraction numerator m u to the power of 3 end exponent sin invisible function application theta sin invisible function application 2 theta over denominator g end fraction
    T o r q u e blank open vertical bar stack tau with rightwards arrow on top close vertical bar equals fraction numerator c h a n g e blank i n blank a n g u l a r blank m o m e n t u m over denominator t i m e blank o f blank f l i g h t end fraction
    equals open vertical bar fraction numerator d stack L with rightwards arrow on top over denominator T end fraction close vertical bar

    Average torque on a projectile of mass m, initial speed u and angles of projection theta, between initial and final position P and Q as shown in figure about the point of projection is

    physics-General
    Time of flight. T equals fraction numerator 2 u sin invisible function application theta over denominator g end fraction
    Horizontal range, R equals fraction numerator u to the power of 2 end exponent sin invisible function application 2 theta over denominator g end fraction
    Change in angular momentum,
    open vertical bar d stack L with rightwards arrow on top close vertical bar equals open vertical bar stack L with rightwards arrow on top subscript f end subscript minus stack L with rightwards arrow on top subscript i end subscript close vertical bar about point of projection
    equals left parenthesis m u sin invisible function application theta right parenthesis cross times fraction numerator u to the power of 2 end exponent sin invisible function application 2 theta over denominator g end fraction
    equals fraction numerator m u to the power of 3 end exponent sin invisible function application theta sin invisible function application 2 theta over denominator g end fraction
    T o r q u e blank open vertical bar stack tau with rightwards arrow on top close vertical bar equals fraction numerator c h a n g e blank i n blank a n g u l a r blank m o m e n t u m over denominator t i m e blank o f blank f l i g h t end fraction
    equals open vertical bar fraction numerator d stack L with rightwards arrow on top over denominator T end fraction close vertical bar
    General
    physics-

    A 0.098 kg block slides down a frictionless track as shown. The vertical component of the velocity of block at A is

    fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent equals m g open parentheses 3 minus 1 close parentheses equals 2 m g or v equals square root of 4 g equals 2 square root of g
    Vertical component at A equals 2 square root of g sin invisible function application 30 degree equals square root of g

    A 0.098 kg block slides down a frictionless track as shown. The vertical component of the velocity of block at A is

    physics-General
    fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent equals m g open parentheses 3 minus 1 close parentheses equals 2 m g or v equals square root of 4 g equals 2 square root of g
    Vertical component at A equals 2 square root of g sin invisible function application 30 degree equals square root of g
    General
    physics-

    A small mass m is attached to a massless string whose other end is fixed at P as shown in the figure. The mass is undergoing circular motion in the x minus y plane with center at O and constant angular speed omega. If the angular momentum of the system, calculated about O blankand P are denoted by stack L with rightwards arrow on top subscript O end subscript and stack L with rightwards arrow on top subscript P end subscript respectively, then

    A small mass m is attached to a massless string whose other end is fixed at P as shown in the figure. The mass is undergoing circular motion in the x minus y plane with center at O and constant angular speed omega. If the angular momentum of the system, calculated about O blankand P are denoted by stack L with rightwards arrow on top subscript O end subscript and stack L with rightwards arrow on top subscript P end subscript respectively, then

    physics-General
    General
    chemistry-

    The monomer used to produce neoprene is

    The monomer used to produce neoprene is

    chemistry-General