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Physics-

General

Easy

Question

Current through ABC and A’ B’ C’ is I. What is the magnetic field at P? $B P equals P B to the power of ´ end exponent equals r$ (Here C’ B’ PBC are collinear)

$B = \frac{1}{4 π} \frac{2 I}{r}$
$B = \frac{μ_{0}}{4 π} (\frac{2 I}{r})$
$B = \frac{μ_{0}}{4 π} (\frac{I}{r})$
Zero

The correct answer is: $B equals fraction numerator mu subscript 0 end subscript over denominator 4 pi end fraction open parentheses fraction numerator 2 I over denominator r end fraction close parentheses$

Magnetic field $B equals 2 open square brackets fraction numerator mu subscript 0 end subscript I over denominator 4 pi r end fraction close square brackets$

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