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Physics-

General

Easy

Question

Equivalent capacitance between $A a n d B$ is

14 $μ F$
4 $μ F$
6 $μ F$
2 $μ F$

The correct answer is: 2 $mu F$

The capacitors 2 $blank mu F$ and 2 $blank mu F$ of arm $A C D$ are in series. So, their equivalent capacitance is 1 $blank mu F$ which is in parallel with capacitor of 1 $blank mu F$ of arm $A D$ .
So, equivalent capacitance now is 2 $blank mu F$ .
This capacitance is now in series with 2 $blank mu F$ capacitance of arm $B D$ which equivalents to 1 $blank mu F$ is in parallel with 1 $blank mu F$ capacitance of arm $A B.$
So, final effective capacitance=2 $blank mu F$ .

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