Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

Figure given shows the distance–time graph of the motion of a car. It follows from the graph that the car is

At rest
In uniform motion
In non-uniform acceleration
Uniformly accelerated

The correct answer is: Uniformly accelerated

Since $x equals 1.2 t to the power of 2 end exponent$ which is in form $x equals fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent$
Thus, the motion is uniformly accelerated

Related Questions to study

A rocket is fired upwards. Its engine explodes fully is 12s. The height reached by the rocket as calculated from its velocity-time graph is

A rocket is fired upwards. Its engine explodes fully is 12s. The height reached by the rocket as calculated from its velocity-time graph is

physics-General

In the relation $straight P equals alpha over beta straight e to the power of fraction numerator alpha z over denominator k theta end fraction end exponent$ P is pressure, Z is distance, k is Boltzmann constant and $theta$ is the temperature. The dimensional formula of β b will be:

In the relation $straight P equals alpha over beta straight e to the power of fraction numerator alpha z over denominator k theta end fraction end exponent$ P is pressure, Z is distance, k is Boltzmann constant and $theta$ is the temperature. The dimensional formula of β b will be:

physics-General

The number of values of k for which the system of equations $left parenthesis k plus 1 right parenthesis x plus 8 y equals 4 k comma k x plus left parenthesis k plus 3 right parenthesis y equals 3 k$ $negative 1$ has infinite number of solutions is

The number of values of k for which the system of equations $left parenthesis k plus 1 right parenthesis x plus 8 y equals 4 k comma k x plus left parenthesis k plus 3 right parenthesis y equals 3 k$ $negative 1$ has infinite number of solutions is

parallel

The value of λ such that the system $x minus 2 y plus z equals negative 4 comma 2 x minus y plus 2 z equals 2 comma x plus y plus lambda z equals 4$
has no solution is

The value of λ such that the system $x minus 2 y plus z equals negative 4 comma 2 x minus y plus 2 z equals 2 comma x plus y plus lambda z equals 4$
has no solution is

Let $A equals open parentheses table row cell negative 5 end cell cell negative 8 end cell cell negative 7 end cell row 3 5 4 row 2 3 3 end table close parentheses comma B equals open parentheses table row cell x end cell row cell y end cell row cell z end cell end table close parentheses$ If AB is a scalar $left parenthesis not equal to 0 right parenthesis$ multiple of B, then $x plus y equals$

Let $A equals open parentheses table row cell negative 5 end cell cell negative 8 end cell cell negative 7 end cell row 3 5 4 row 2 3 3 end table close parentheses comma B equals open parentheses table row cell x end cell row cell y end cell row cell z end cell end table close parentheses$ If AB is a scalar $left parenthesis not equal to 0 right parenthesis$ multiple of B, then $x plus y equals$

An open tank is filled with Hg upto a height of 76cm. Find the pressure at the bottom of the tank and middle of the tank. (If atmospheric pressure is 1 atm) respectively are

An open tank is filled with Hg upto a height of 76cm. Find the pressure at the bottom of the tank and middle of the tank. (If atmospheric pressure is 1 atm) respectively are

chemistry-General

parallel

For one mole of a van der Waals gas when b=0 and T = 300 K, the PV vs 1/V plot is shown below. The value of ‘a’ (atmliter² .mol^–2) is

For one mole of a van der Waals gas when b=0 and T = 300 K, the PV vs 1/V plot is shown below. The value of ‘a’ (atmliter² .mol^–2) is

chemistry-General

In the equation $integral fraction numerator d t over denominator square root of 2 a t minus t squared end root end fraction equals a to the power of x sin to the power of negative 1 end exponent space open square brackets t over a minus 1 close square brackets$ The value of x is :

In the equation $integral fraction numerator d t over denominator square root of 2 a t minus t squared end root end fraction equals a to the power of x sin to the power of negative 1 end exponent space open square brackets t over a minus 1 close square brackets$ The value of x is :

physics-General

If $tan space left parenthesis pi cos space theta right parenthesis equals cot space left parenthesis pi Sin space theta right parenthesis$ then the value(s) of $cos space open parentheses theta minus pi over 4 close parentheses$ is are

If $tan space left parenthesis pi cos space theta right parenthesis equals cot space left parenthesis pi Sin space theta right parenthesis$ then the value(s) of $cos space open parentheses theta minus pi over 4 close parentheses$ is are

parallel

From a high tower at time $t equals 0$ , one stone is dropped from rest and simultaneously another stone is projected vertically up with an initial velocity. The graph of the distance $S$ between the two stones, before either his the ground, plotted against time $t$ will be as

From a high tower at time $t equals 0$ , one stone is dropped from rest and simultaneously another stone is projected vertically up with an initial velocity. The graph of the distance $S$ between the two stones, before either his the ground, plotted against time $t$ will be as

physics-General

Let M and N be two 3×3 non- singular symmetric matrices such that MN $equals$ NM .If $P to the power of T end exponent$ denotes the transpose of the matrix P, then $M to the power of 2 end exponent N to the power of 2 end exponent open parentheses M to the power of T end exponent N close parentheses to the power of negative 1 end exponent open parentheses M N to the power of negative 1 end exponent close parentheses to the power of T end exponent$ is equal to

Let M and N be two 3×3 non- singular symmetric matrices such that MN $equals$ NM .If $P to the power of T end exponent$ denotes the transpose of the matrix P, then $M to the power of 2 end exponent N to the power of 2 end exponent open parentheses M to the power of T end exponent N close parentheses to the power of negative 1 end exponent open parentheses M N to the power of negative 1 end exponent close parentheses to the power of T end exponent$ is equal to

If A is 3×3 non-singular matrix then $d e t invisible function application open parentheses A to the power of negative 1 end exponent a d j A close parentheses equals$

If A is 3×3 non-singular matrix then $d e t invisible function application open parentheses A to the power of negative 1 end exponent a d j A close parentheses equals$

parallel

If cos3A + cos3B + cos3C =1 then one of the angles of ΔABC is

If cos3A + cos3B + cos3C =1 then one of the angles of ΔABC is

Let points A(7, 5), B(2, 1), C(10, 3) the vertices of a ΔABC. I is incentre of ΔABC. E and D are points of contact of incircle and sides AC and BC of ΔABC respectively. If G is the intersection points of angle bisector of ΔB and line joining ED. Then angle between line AG and BG is

Let points A(7, 5), B(2, 1), C(10, 3) the vertices of a ΔABC. I is incentre of ΔABC. E and D are points of contact of incircle and sides AC and BC of ΔABC respectively. If G is the intersection points of angle bisector of ΔB and line joining ED. Then angle between line AG and BG is

In a ΔABC as in given figure $fraction numerator B D over denominator C D end fraction equals fraction numerator 1 over denominator 4 end fraction$ and $fraction numerator A E over denominator C E end fraction equals fraction numerator 1 over denominator 5 end fraction$ find the ratio of $fraction numerator capital delta P A E over denominator capital delta P B D end fraction$

In a ΔABC as in given figure $fraction numerator B D over denominator C D end fraction equals fraction numerator 1 over denominator 4 end fraction$ and $fraction numerator A E over denominator C E end fraction equals fraction numerator 1 over denominator 5 end fraction$ find the ratio of $fraction numerator capital delta P A E over denominator capital delta P B D end fraction$

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.