Physics-

General

Easy

Question

# Figure shows the acceleration-time graphs of a particle. Which of the following represents the corresponding velocity-time graphs?

## The correct answer is:

### Since acceleration is constant, therefore there is uniform increase in velocity. So, the graph is a straight line slopping upward to the right. When acceleration becomes zero, velocity is constant. So graph is a straight line parallel to the time-axis.

### Related Questions to study

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### If and , then the possible values of χ between and are

### If and , then the possible values of χ between and are

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### A) Area bounded by = 2 and coordinate axes

B) Area bounded by and

C) Area bounded by between x=0,x=1,x- axis

D) Area bounded by and y=2x Arrange the above statements in the ascending order of areas.

### A) Area bounded by = 2 and coordinate axes

B) Area bounded by and

C) Area bounded by between x=0,x=1,x- axis

D) Area bounded by and y=2x Arrange the above statements in the ascending order of areas.

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### Velocity-time - graph for a moving object is shown in the figure. Total displacement of the object during the same interval when there is non-zero acceleration and retardation is

Between time interval to , there is non-zero acceleration and retardation. Hence distance travelled during this interval

Area between time interval to

Area between time interval to

### Velocity-time - graph for a moving object is shown in the figure. Total displacement of the object during the same interval when there is non-zero acceleration and retardation is

Physics-General

Between time interval to , there is non-zero acceleration and retardation. Hence distance travelled during this interval

Area between time interval to

Area between time interval to

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### A particle moves along the sides of a square of side wuth a velocity of . Its average velocity is

Average velocity =

### A particle moves along the sides of a square of side wuth a velocity of . Its average velocity is

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Average velocity =

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### The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in are respectively

Displacement = Summation of all the area with sign

Distance = Summation of all the areas without sign

Distance = Summation of all the areas without sign

### The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in are respectively

physics-General

Displacement = Summation of all the area with sign

Distance = Summation of all the areas without sign

Distance = Summation of all the areas without sign

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### The area bounded by , Y-axis and the line y=e is

### The area bounded by , Y-axis and the line y=e is

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### If then the general value of 'α ' is

### If then the general value of 'α ' is

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### The parabolas divide the square region bounded by the lines x=4, y=4 and the co-ordinate axes. If are respectively the areas of these parts numbered from top to bottom then is

### The parabolas divide the square region bounded by the lines x=4, y=4 and the co-ordinate axes. If are respectively the areas of these parts numbered from top to bottom then is

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### The figure shows a double slit experiment *P* and *Q* are the slits. The path lengths *PX* and *QX* are and respectively, where *n *is a whole number and is the wavelength. Taking the central fringe as zero, what is formed at *X*

For brightness, path difference

So second is bright.

So second is bright.

### The figure shows a double slit experiment *P* and *Q* are the slits. The path lengths *PX* and *QX* are and respectively, where *n *is a whole number and is the wavelength. Taking the central fringe as zero, what is formed at *X*

physics-General

For brightness, path difference

So second is bright.

So second is bright.

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### If then = ---

### If then = ---

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### A particle starts from rest. Its acceleration time is as shown in the figure. The maximum speed of the particle will be

Area under acceleration-time graph gives the change in velocity. Hence,

Therefore, the correct option is [b].

Therefore, the correct option is [b].

### A particle starts from rest. Its acceleration time is as shown in the figure. The maximum speed of the particle will be

physics-General

Area under acceleration-time graph gives the change in velocity. Hence,

Therefore, the correct option is [b].

Therefore, the correct option is [b].

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### In figure, one car at rest and velocity of the light from head light is , tehn velocity of light from head light for the moving car at velocity , would be

Since (negligible)

### In figure, one car at rest and velocity of the light from head light is , tehn velocity of light from head light for the moving car at velocity , would be

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Since (negligible)

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### If α and β are two different solutions lying between and of the equation then Tan α + Tan β is

### If α and β are two different solutions lying between and of the equation then Tan α + Tan β is

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### A particle of mass is initially situated at the point inside a hemispherical surface of radius as shown in figure. A horizontal acceleration of magnitudeis suddenly produced on the particle in the horizontal direction. If gravitational acceleration is neglected, the time taken by particle to touch the sphere again is

Let the particle touches the sphere t the point

Let

In

or

Let

In

or

### A particle of mass is initially situated at the point inside a hemispherical surface of radius as shown in figure. A horizontal acceleration of magnitudeis suddenly produced on the particle in the horizontal direction. If gravitational acceleration is neglected, the time taken by particle to touch the sphere again is

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Let the particle touches the sphere t the point

Let

In

or

Let

In

or

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### A cyclist starts from the centre of a circular park of radius 1 km, reaches the edge of the park, then cycles along the circumference and returns to the point as shown in figure. If the round trip takes 10 min, the net displacement and average speed of the cyclist (in metre and kilometer per hour) are

Since, the initial position of cyclist coincides with final position, so his net displacement is zero.

### A cyclist starts from the centre of a circular park of radius 1 km, reaches the edge of the park, then cycles along the circumference and returns to the point as shown in figure. If the round trip takes 10 min, the net displacement and average speed of the cyclist (in metre and kilometer per hour) are

physics-General

Since, the initial position of cyclist coincides with final position, so his net displacement is zero.