Physics-
General
Easy

Question

In the circuit shown the value of I in ampere is

  1. 1    
  2. 060    
  3. 0.4    
  4. 1.5    

The correct answer is: 0.4


    We can simplify the network as shown

    So, net resistance,
    R=2.4+1.6=4.0capital omega
    Therefore, current from the battery.
    i equals fraction numerator V over denominator R end fraction equals fraction numerator 4 over denominator 4 end fraction equals 1 A
    Now, from the circuit (b),
    4I’ =6I
    ⟹ I to the power of ´ end exponent equals fraction numerator 3 over denominator 2 end fraction I
    But i=I+I’
    equals I plus fraction numerator 3 over denominator 2 end fraction I equals fraction numerator 5 over denominator 2 end fraction I
    therefore blank 1 equals fraction numerator 5 over denominator 2 end fraction I
    ⟹ I equals fraction numerator 2 over denominator 5 end fraction equals 0.4 A

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