Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

In the electrical network shown in the figure, the potential difference across 3 $capital omega$ resistance will be

12V
2.4V
24 V
36 V

The correct answer is: 24 V

As 3 $capital omega$ and 6 $capital omega$ resistances are
In parallel their equivalent resistance will be 2 $capital omega$ . Here 2 $capital omega$ and 4 $capital omega$ are in series, their equivalent resistance will be 6 $capital omega$ . From current distribution law

$i subscript 1 end subscript equals fraction numerator 12 cross times 18 over denominator 18 end fraction equals 12 A$
$i subscript 2 end subscript equals fraction numerator 6 cross times 18 over denominator 18 end fraction equals 6 A$

Now, 12A current is entering in parallel combination of 3 $capital omega$ and $6 capital omega$ again from current distribution law
$i subscript 1 end subscript superscript ´ ´ end superscript equals fraction numerator 6 cross times 12 over denominator 9 end fraction equals 8 A$
$i subscript 2 end subscript superscript ´ ´ end superscript equals fraction numerator 3 cross times 12 over denominator 9 end fraction equals 4 A.$
∴ Potential difference across 3 $capital omega$ resistance
=8×3=24V

Related Questions to study

The current $i subscript 1 end subscript$ and $i subscript 2 end subscript$ through the resistor $R subscript 1 end subscript open parentheses equals 10 capital omega close parentheses$ and $R subscript 2 end subscript open parentheses equals 30 capital omega close parentheses$ in the circuit diagram with $E subscript 1 end subscript equals 3 V comma E subscript 2 end subscript equals 3 blank a n d E subscript 3 end subscript equals 2 V$ are respectively.

The current $i subscript 1 end subscript$ and $i subscript 2 end subscript$ through the resistor $R subscript 1 end subscript open parentheses equals 10 capital omega close parentheses$ and $R subscript 2 end subscript open parentheses equals 30 capital omega close parentheses$ in the circuit diagram with $E subscript 1 end subscript equals 3 V comma E subscript 2 end subscript equals 3 blank a n d E subscript 3 end subscript equals 2 V$ are respectively.

physics-General

The Products are:

The Products are:

chemistry-General

In the set up shown, the two slits S₁ and S₂ are not equidistant from the slit S

The central fringe at O is then

In the set up shown, the two slits S₁ and S₂ are not equidistant from the slit S

The central fringe at O is then

physics-General

parallel

A group of N cells whose emf varies directly with the internal resistance as per the equation $E subscript N end subscript equals 1.5 r subscript N end subscript$ are connected as shown in the figure. The current I in the circuit is

A group of N cells whose emf varies directly with the internal resistance as per the equation $E subscript N end subscript equals 1.5 r subscript N end subscript$ are connected as shown in the figure. The current I in the circuit is

physics-General

In the circuit shown, the internal resistance of the cell is negligible. The steady state current in the 2 $blank capital omega$ resistance is

In the circuit shown, the internal resistance of the cell is negligible. The steady state current in the 2 $blank capital omega$ resistance is

physics-General

Two similar accumulators each of emf E and internal resistance r are connected as shown in the following figure. Then, the potential difference between x and y is

Two similar accumulators each of emf E and internal resistance r are connected as shown in the following figure. Then, the potential difference between x and y is

physics-General

parallel

A current of A enters one corner one corner P of an equilateral triangle $P Q R$ having 3 wires of resistance 2 $blank capital omega$ each and leaves by the corner R. then the current $I subscript 1 end subscript$ and $I subscript 2 end subscript$ are

A current of A enters one corner one corner P of an equilateral triangle $P Q R$ having 3 wires of resistance 2 $blank capital omega$ each and leaves by the corner R. then the current $I subscript 1 end subscript$ and $I subscript 2 end subscript$ are

physics-General

For the circuit shown in the figure the potential difference between A and B will be (in volt)

For the circuit shown in the figure the potential difference between A and B will be (in volt)

physics-General

If A = $open square brackets table row 0 1 row cell negative 1 end cell 0 end table close square brackets$ and (aI₂ + bA)² = A, then-

Hence Choice 2 is correct

If A = $open square brackets table row 0 1 row cell negative 1 end cell 0 end table close square brackets$ and (aI₂ + bA)² = A, then-

Hence Choice 2 is correct

parallel

If A = $open square brackets table row 4 2 row cell negative 1 end cell 1 end table close square brackets$ then (A– 2I) (A – 3I) equals-

If A = $open square brackets table row 4 2 row cell negative 1 end cell 1 end table close square brackets$ then (A– 2I) (A – 3I) equals-

If A = $open square brackets table row 1 2 row 2 3 end table close square brackets$ and A² – KA– I₂ = 0, then value of K is-

If A = $open square brackets table row 1 2 row 2 3 end table close square brackets$ and A² – KA– I₂ = 0, then value of K is-

If A = $open square brackets table row 1 k row 0 1 end table close square brackets$ then Aⁿequal to-

If A = $open square brackets table row 1 k row 0 1 end table close square brackets$ then Aⁿequal to-

parallel

If A and B are two matrix of same order then A² – B² = (A + B) (A – B) correct statement is-

If A and B are two matrix of same order then A² – B² = (A + B) (A – B) correct statement is-

If A = $open square brackets table row 1 1 row 0 1 end table close square brackets$ then Aⁿ =

If A = $open square brackets table row 1 1 row 0 1 end table close square brackets$ then Aⁿ =

If A = $open square brackets table row 1 alpha row 0 1 end table close square brackets$ , then A⁴ is equal to-

If A = $open square brackets table row 1 alpha row 0 1 end table close square brackets$ , then A⁴ is equal to-

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.