Physics-
General
Easy

Question

The charge deposited on 4 mu F capacitor the circuit is

  1. 6 cross times 10 to the power of negative 6 end exponent C    
  2. 12 cross times 10 to the power of negative 6 end exponent C    
  3. 24 cross times 10 to the power of negative 6 end exponent C    
  4. 36 cross times 10 to the power of negative 6 end exponent C    

The correct answer is: 24 cross times 10 to the power of negative 6 end exponent C



    As the capacitors 4 mu F and 2 mu F are connected in parallel and are in series with 6blank mu F capacitor, their equivalent capacitance is
    fraction numerator left parenthesis 2 plus 4 right parenthesis cross times 6 over denominator 2 plus 4 plus 6 end fraction equals 3 blank mu F
    Charge in the circuit
    Q equals blank 3 blank mu F cross times 12 V equals 36 mu C

    Since, the capacitors 4 mu F and 2mu F are connected in parallel, therefore potential difference across them is same.
    rightwards double arrow fraction numerator Q subscript 1 end subscript over denominator Q subscript 2 end subscript end fraction equals fraction numerator C subscript 1 end subscript over denominator C subscript 2 end subscript end fraction equals fraction numerator 4 over denominator 2 end fraction o r Q subscript 1 end subscript equals 2 Q subscript 2 end subscript
    Also Q equals Q subscript 1 end subscript plus Q subscript 2 end subscript
    therefore blank 36 mu C equals 2 Q subscript 2 end subscript plus Q subscript 2 end subscript or Q subscript 2 end subscript equals fraction numerator 36 mu C over denominator 3 end fraction equals 12 mu C
    Q subscript 1 end subscript equals Q minus Q subscript 2 end subscript equals 36 mu C minus 12 mu C
    equals 24 blank mu C equals 24 cross times 10 to the power of negative 6 end exponent C

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