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Physics-

General

Easy

Question

The current in the 1 $capital omega$ resistor shown in the circuit is

$\frac{2}{3} A$
3A
6A
2A

The correct answer is: 2A

In the given circuit 4 $capital omega$ resistors are connected in parallel, this combination is connected in series with 1 $capital omega$ resistance.

$therefore blank fraction numerator 1 over denominator R to the power of ´ end exponent end fraction equals fraction numerator 1 over denominator 4 end fraction plus fraction numerator 1 over denominator 4 end fraction equals fraction numerator 2 over denominator 4 end fraction equals fraction numerator 1 over denominator 2 end fraction$
$⟹ R to the power of ´ end exponent equals 2 capital omega$
Also, R’’=2 $capital omega$ +1 $capital omega$ =3 $capital omega$
From Ohm’s law, $V equals i R$
$therefore blank i equals fraction numerator V over denominator R end fraction equals fraction numerator 6 over denominator 3 end fraction equals 2 A$

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15 $capital omega$ )

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