Physics-
General
Easy

Question

The displacement-time graphs for two sound waves A and B are shown in the figure, then the ratio of their intensities I subscript A end subscript divided by I subscript B end subscript is equal to

  1. 1 : 4    
  2. 1 : 16    
  3. 1 : 2    
  4. 1 : 1    

The correct answer is: 1 : 1


    Intensity proportional to a to the power of 2 end exponent omega to the power of 2 end exponent
    Here fraction numerator a subscript A end subscript over denominator a subscript B end subscript end fraction equals fraction numerator 2 over denominator 1 end fraction and fraction numerator omega subscript A end subscript over denominator omega subscript B end subscript end fraction equals fraction numerator 1 over denominator 2 end fraction rightwards double arrow fraction numerator I subscript A end subscript over denominator I subscript B end subscript end fraction equals open parentheses fraction numerator 2 over denominator 1 end fraction close parentheses to the power of 2 end exponent cross times open parentheses fraction numerator 1 over denominator 2 end fraction close parentheses to the power of 2 end exponent equals fraction numerator 1 over denominator 1 end fraction

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