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Physics-

General

Easy

Question

The four capacitors, each of 25 $mu$ F are connected as shown in figure. The DC voltmeter reads 200 V. the change on each plate of capacitor is

$\pm 2 \times 10^{- 3}$ C
$\pm 5 \times 10^{- 3}$ C
$\pm 2 \times 10^{- 2}$ C
$\pm 5 \times 10^{- 2}$ C

The correct answer is: $plus-or-minus 5 cross times 10 to the power of negative 3 end exponent$ C

Charge on each plate of each capacitor
$Q equals plus-or-minus C V equals plus-or-minus 25 cross times 10 to the power of negative 6 end exponent cross times 200$
$equals plus-or-minus 5 cross times 10 to the power of negative 3 end exponent C$

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