Physics-
General
Easy

Question

The graph, shown in the adjacent diagram, represents the variation of temperature left parenthesis T right parenthesis of two bodies, x and y having same surface area, with time (t) due to the emission of radiation. Find the correct relation between the emissivity and absorptivity power of the two bodies.

  1. E subscript x end subscript greater than E subscript y end subscript a n d a subscript x end subscript less than a subscript y end subscript    
  2. E subscript x end subscript less than E subscript x end subscript a n d a subscript x end subscript greater than a subscript y end subscript    
  3. E subscript x end subscript greater than E subscript x end subscript a n d a subscript x end subscript greater than a subscript y end subscript    
  4. E subscript x end subscript less than E subscript x end subscript a n d a subscript x end subscript less than a subscript y end subscript    

The correct answer is: E subscript x end subscript greater than E subscript x end subscript a n d a subscript x end subscript greater than a subscript y end subscript


    Rate of cooling left parenthesis negative fraction numerator d T over denominator d t end fraction right parenthesis proportional to emissivity(e)
    From the graph,
    open parentheses negative fraction numerator d T over denominator d t end fraction close parentheses subscript x end subscript greater than open parentheses negative fraction numerator d T over denominator d t end fraction close parentheses subscript y end subscript
    therefore e subscript x end subscript greater than e subscript y end subscript
    Further emissivity (e)proportional to absorptive power (a) (good absorbers are good emitters also)
    therefore a subscript x end subscript greater than a subscript y end subscript

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