Physics-
General
Easy

Question

The network shown in the figure is a part of a complete circuit. If at a certain instant the current i is 5 A and is decreasing at the rate of 1 0 to the power of 3 end exponent A divided by s then V subscript A end subscript minus V subscript B end subscript is

  1. 5 V    
  2. 10 V    
  3. 15 V    
  4. 20 V    

The correct answer is: 15 V


    By using Kirchoff’s voltage law
    V subscript A end subscript minus i   R plus E minus L fraction numerator d i over denominator d t end fraction equals V subscript B end subscript rightwards double arrow V subscript B end subscript minus V subscript A end subscript equals 15   v o l t.

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