Physics-
General
Easy

Question

The resonance point in X subscript L end subscript minus f and X subscript C end subscript minus f curves is

  1. P    
  2. Q    
  3. R    
  4. S    

The correct answer is: R

Related Questions to study

General
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A constant voltage at different frequencies is applied across a capacitance C as shown in the figure. Which of the following graphs

Correctly depicts the variation of current with frequency ?

A constant voltage at different frequencies is applied across a capacitance C as shown in the figure. Which of the following graphs

Correctly depicts the variation of current with frequency ?

physics-General
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A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

voltage across Q is.

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

voltage across Q is.

physics-General
General
physics-

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Maximum current through circuit is.

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Maximum current through circuit is.

physics-General
parallel
General
physics-

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Impedance of p at this frequency is.

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Impedance of p at this frequency is.

physics-General
General
physics-

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given When power loss through resistor is 50 watt, then angular frequency of applied a.c voltage is

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given When power loss through resistor is 50 watt, then angular frequency of applied a.c voltage is

physics-General
General
physics-

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given The current in the circuit is

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given The current in the circuit is

physics-General
parallel
General
physics-

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L,C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given The value of applied peak voltage is

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L,C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given The value of applied peak voltage is

physics-General
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The potential different across a 2H inductor as a function of time is shown in figure. At time t=0, current is zero Current versus time graph across the inductor will be

The potential different across a 2H inductor as a function of time is shown in figure. At time t=0, current is zero Current versus time graph across the inductor will be

physics-General
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The potential different across a 2H inductor as a function of time is shown in figure. At time t=0, current is zero Current at t=2s is

The potential different across a 2H inductor as a function of time is shown in figure. At time t=0, current is zero Current at t=2s is

physics-General
parallel
General
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For the circuit shown in figure, the current through the inductor is 1.6 amp. While the current through the condenser is 0.4 amp. Then

For the circuit shown in figure, the current through the inductor is 1.6 amp. While the current through the condenser is 0.4 amp. Then

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In a parallel LCR circuit shown in figure, at resonance,

In a parallel LCR circuit shown in figure, at resonance,

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Which of the following plots may represent the reactance of a series LC combination

Which of the following plots may represent the reactance of a series LC combination

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The figure shows variation of R comma X subscript L end subscript and X subscript C end subscript with frequency f in a series L,C,R circuit. Then for what frequency point, the circuit is inductive

The figure shows variation of R comma X subscript L end subscript and X subscript C end subscript with frequency f in a series L,C,R circuit. Then for what frequency point, the circuit is inductive

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The graphs given below depict the dependence of two reactive impedances X subscript 1 end subscript and X subscript 2 end subscript on the frequency of the alternating e.m.f. applied individually to them. We can then say that

The graphs given below depict the dependence of two reactive impedances X subscript 1 end subscript and X subscript 2 end subscript on the frequency of the alternating e.m.f. applied individually to them. We can then say that

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When an ac source of e.m.f. e equals E subscript 0 end subscript s i n invisible function application left parenthesis 100 t right parenthesis is connected across a circuit, the phase difference between the e.m.f. e and the current i in the circuit is observed to be pi divided by 4, as shown in the diagram. If the circuit consists possibly only of RC or LC in series, find the relationship between the two elements

When an ac source of e.m.f. e equals E subscript 0 end subscript s i n invisible function application left parenthesis 100 t right parenthesis is connected across a circuit, the phase difference between the e.m.f. e and the current i in the circuit is observed to be pi divided by 4, as shown in the diagram. If the circuit consists possibly only of RC or LC in series, find the relationship between the two elements

physics-General
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