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Physics-

General

Easy

Question

The time taken by the projectile to reach from $A$ to $B$ is $t comma$ then the distance $A B$ is equal to

$2 u t$
$\sqrt{3} u t$
$\frac{\sqrt{3}}{2} u t$
$\frac{u t}{\sqrt{3}}$

The correct answer is: $fraction numerator u t over denominator square root of 3 end fraction$

Horizontal component of velocity at $A$

$v subscript H end subscript equals u cos invisible function application 60 degree equals fraction numerator u over denominator 2 end fraction blank therefore A C equals u subscript H end subscript cross times t equals fraction numerator u t over denominator 2 end fraction$
$A B equals A C sec invisible function application 30 degree equals fraction numerator u t over denominator 2 end fraction cross times fraction numerator 2 over denominator square root of 3 end fraction equals fraction numerator u t over denominator 2 end fraction$

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