Physics
General
Easy
Question
The two bodies of mass and respectively are tied to the ends of a massless string, which passes over a light and frictionless pulley. The masses are initially at rest and the released. Then acceleration of the centre of mass of the system is



 zero
The correct answer is:
In the pulley arrangement
But is in downward direction and in the upward direction ,
Acceleration of centre of mass
Related Questions to study
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If to terms, terms, , then
If to terms, terms, , then
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The coefficient of in is
The coefficient of in is
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Compounds (A) and (B) are –
Compounds (A) and (B) are –
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A triangle is inscribed in a circle. The vertices of the triangle divide the circle into three arcs of length 3, 4 and 5 units. Then area of the triangle is equal to:
A triangle is inscribed in a circle. The vertices of the triangle divide the circle into three arcs of length 3, 4 and 5 units. Then area of the triangle is equal to:
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If one root of the equation is reciprocal of the one of the roots of equation then
Let one of the roots of the equation be .
Then as per question one of the roots of the equation will be.
Multiplying equation 1 by and equation 2 by a, then subtracting, we get:
putting the value in equation 1
Then as per question one of the roots of the equation will be.
Multiplying equation 1 by and equation 2 by a, then subtracting, we get:
putting the value in equation 1
If one root of the equation is reciprocal of the one of the roots of equation then
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Let one of the roots of the equation be .
Then as per question one of the roots of the equation will be.
Multiplying equation 1 by and equation 2 by a, then subtracting, we get:
putting the value in equation 1
Then as per question one of the roots of the equation will be.
Multiplying equation 1 by and equation 2 by a, then subtracting, we get:
putting the value in equation 1
Maths
If the quadratic equation and have a common root then is equal to
The two quadratic equations are ￼ and
Let be the common root.
Now,
subtracting the equations, we get
now putting the value in equation1
Let be the common root.
Now,
subtracting the equations, we get
now putting the value in equation1
If the quadratic equation and have a common root then is equal to
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The two quadratic equations are ￼ and
Let be the common root.
Now,
subtracting the equations, we get
now putting the value in equation1
Let be the common root.
Now,
subtracting the equations, we get
now putting the value in equation1
physics
Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on frictionless horizontal surface. An impulsive force gives a velocity of 14 to the heavier block in the direction of the lighter block. The velocity of centre of mass of the system at that very moment is
At the time of applying the impulsive force block of 10 kg pushes the spring forward but 4 kg mass is at rest.
Hence,
Hence,
Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on frictionless horizontal surface. An impulsive force gives a velocity of 14 to the heavier block in the direction of the lighter block. The velocity of centre of mass of the system at that very moment is
physicsGeneral
At the time of applying the impulsive force block of 10 kg pushes the spring forward but 4 kg mass is at rest.
Hence,
Hence,
Maths
In a Δabc if b+c=3a then has the value equal to –
In a Δabc if b+c=3a then has the value equal to –
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In a simplifies to
In a simplifies to
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In a triangle ABC, a: b: c = 4: 5: 6. Then 3A + B equals to :
In a triangle ABC, a: b: c = 4: 5: 6. Then 3A + B equals to :
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physics
A bullet of mass is fired with a velocity of 50 at an angle with the horizontal. At the highest point of its trajectory, it collides had on with a bob of massless string of length m and gets embedded in the bob. After the collision, the string moves to an angle of 120. What is the angle
Velocity of bullet at highest point of its trajectory = 50 in horizontal direction.
As bullet of mass collides with pendulum bob of mass 3 and two stick together, their common velocity
As now under this velocity pendulum bob goes up to an angel 120, hence
or
Comparing two answer of , we get
or
As bullet of mass collides with pendulum bob of mass 3 and two stick together, their common velocity
As now under this velocity pendulum bob goes up to an angel 120, hence
or
Comparing two answer of , we get
or
A bullet of mass is fired with a velocity of 50 at an angle with the horizontal. At the highest point of its trajectory, it collides had on with a bob of massless string of length m and gets embedded in the bob. After the collision, the string moves to an angle of 120. What is the angle
physicsGeneral
Velocity of bullet at highest point of its trajectory = 50 in horizontal direction.
As bullet of mass collides with pendulum bob of mass 3 and two stick together, their common velocity
As now under this velocity pendulum bob goes up to an angel 120, hence
or
Comparing two answer of , we get
or
As bullet of mass collides with pendulum bob of mass 3 and two stick together, their common velocity
As now under this velocity pendulum bob goes up to an angel 120, hence
or
Comparing two answer of , we get
or
physics
A spherical hollow is made in a lead sphere of radius such that its surface touches the outside surface of lead sphere and passes through the centre. What is the shift in the centre of lead sphere as a result of this hollowing?
Let centre of mass of lead sphere after hollowing be at point where
Mass of spherical hollow and
shift
Mass of spherical hollow and
shift
A spherical hollow is made in a lead sphere of radius such that its surface touches the outside surface of lead sphere and passes through the centre. What is the shift in the centre of lead sphere as a result of this hollowing?
physicsGeneral
Let centre of mass of lead sphere after hollowing be at point where
Mass of spherical hollow and
shift
Mass of spherical hollow and
shift
chemistry
On heating a mixture of ans , we get –
On heating a mixture of ans , we get –
chemistryGeneral