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Physics-

General

Easy

Question

The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in $6 blank s e c$ are respectively

$8 m, 16 m$
$16 m, 8 m$
$16 m, 16 m$
$8 m, 8 m$

The correct answer is: $8 blank m comma blank 16 blank m$

Displacement = Summation of all the area with sign
$equals open parentheses A subscript 1 end subscript close parentheses plus open parentheses negative A subscript 2 end subscript close parentheses plus open parentheses A subscript 3 end subscript close parentheses equals open parentheses 2 cross times 4 close parentheses plus open parentheses negative 2 cross times 2 close parentheses plus open parentheses 2 cross times 2 close parentheses$

$therefore D i s p l a c e m e n t equals 8 blank m$
Distance = Summation of all the areas without sign
$equals open vertical bar A subscript 1 end subscript close vertical bar plus open vertical bar negative A subscript 2 end subscript close vertical bar plus open vertical bar A subscript 3 end subscript close vertical bar equals open vertical bar 8 close vertical bar plus open vertical bar negative 4 close vertical bar plus open vertical bar 4 close vertical bar equals 8 plus 4 plus 4$
$therefore D i s t a n c e equals 16 blank m$

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