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Physics-

General

Easy

Question

The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of $20 blank m$ is

$225 J$
$200 J$
$400 J$
$175 J$

The correct answer is: $200 blank J$

Work done $W equals$ area under $F minus S$ graph
= area of trapezium $A B C D plus$ area of trapezium $C E F D$
$equals fraction numerator 1 over denominator 2 end fraction cross times open parentheses 10 plus 15 close parentheses cross times 10 plus fraction numerator 1 over denominator 2 end fraction cross times left parenthesis 10 plus 20 right parenthesis cross times 5$
$equals 125 plus 75 equals 200 blank J$

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