Physics-
General
Easy

Question

The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 blank m is

  1. 225 blank J    
  2. 200 blank J    
  3. 400 blank J    
  4. 175 blank J    

The correct answer is: 200 blank J


    Work done W equals area under F minus S graph
    = area of trapezium A B C D plus area of trapezium C E F D
    equals fraction numerator 1 over denominator 2 end fraction cross times open parentheses 10 plus 15 close parentheses cross times 10 plus fraction numerator 1 over denominator 2 end fraction cross times left parenthesis 10 plus 20 right parenthesis cross times 5
    equals 125 plus 75 equals 200 blank J

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