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Physics-

General

Easy

Question

Three forces of magnitudes 6N, 6N and $square root of 72$ N at a corner of a cube along three sides as shown in figure. Resultant of these forces is

12 N along $O B$
18 N along $O A$
18 N along $O C$
12 N along $O E$

The correct answer is: 12 N along $O E$

The resultant of 5 N along $O C$ and 5 N along $O A$ is
$R equals square root of 6 to the power of 2 end exponent plus 6 to the power of 2 end exponent end root$
$equals square root of 72$ N along $O B$
The resultant of $square root of 72$ N along $O B$ and $square root of 72$ N along $O G$ is
$R to the power of ´ end exponent equals square root of 72 plus 72 end root equals 12$ N along $O E$ .

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