Physics-
General
Easy

Question

Two inclined planes are located as shown in figure. A particle is projected from the foot of one frictionless plane along its line with a velocity just sufficient to carry it to top after which the particle slides down the other frictionless inclined plane. The total time it will take to reach the point C is

  1. 2 blank s    
  2. 3 blank s    
  3. 2 square root of 2 blank s    
  4. 4 blank s    

The correct answer is: 4 blank s


    The time of ascent = time of descent equals t subscript 0 end subscript
    T equals total time of flight equals 2 t subscript 0 end subscript

    sin invisible function application 45 degree equals fraction numerator 9.8 over denominator B C end fraction equals fraction numerator 9.8 over denominator s end fraction
    therefore blank s equals 9.8 square root of 2
    therefore blank s equals u t plus fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent
    s equals 0 cross times t plus fraction numerator 1 over denominator 2 end fraction left parenthesis g sin invisible function application 45 degree right parenthesis t subscript 0 end subscript superscript 2 end superscript
    or 9.8 square root of 2 equals fraction numerator 9.8 over denominator 2 square root of 2 end fraction t subscript 0 end subscript superscript 2 end superscript
    therefore blank t subscript 0 end subscript superscript 2 end superscript equals 4
    therefore blank t subscript 0 end subscript equals 2 s
    therefore blank T equals 2 t subscript 0 end subscript minus 4 s

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