Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

Value of $tan invisible function application theta equals fraction numerator 2 over denominator square root of 5 end fraction comma$ find the value of sin²0^O +cos²0^O

$\frac{2 - \sqrt{5}}{3}$
$\sqrt{3}$
2
–2

The correct answer is: $fraction numerator 2 minus square root of 5 over denominator 3 end fraction$

Related Questions to study

The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

physics-General

The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

physics-General

In the given figure, if $P Q perpendicular P S comma P Q parallel to S R comma angle S Q R equals 28 to the power of ring operator end exponent text end text$ and $text end text angle Q R T equals 65 to the power of ring operator end exponent comma$ then the values of x and y respectively are

In the given figure, if $P Q perpendicular P S comma P Q parallel to S R comma angle S Q R equals 28 to the power of ring operator end exponent text end text$ and $text end text angle Q R T equals 65 to the power of ring operator end exponent comma$ then the values of x and y respectively are

parallel

In the given figure, if lines PQ and RS intersect at point T, such that $angle P R T equals 40 to the power of ring operator end exponent comma angle R P T equals 95 to the power of ring operator end exponent text end text$ and $text end text angle T S Q equals 75 to the power of ring operator end exponent comma text then end text angle S Q T$

In the given figure, if lines PQ and RS intersect at point T, such that $angle P R T equals 40 to the power of ring operator end exponent comma angle R P T equals 95 to the power of ring operator end exponent text end text$ and $text end text angle T S Q equals 75 to the power of ring operator end exponent comma text then end text angle S Q T$

In the given figure, if $A B parallel to D E comma angle B A C equals 35 to the power of ring operator end exponent text end text$ and $text end text angle C D E equals 53 to the power of ring operator end exponent$ , then DCE is

In the given figure, if $A B parallel to D E comma angle B A C equals 35 to the power of ring operator end exponent text end text$ and $text end text angle C D E equals 53 to the power of ring operator end exponent$ , then DCE is

In the given $capital delta X Y Z comma angle X equals 62 to the power of 0 end exponent comma angle X Y Z equals 54 to the power of ring operator end exponent$ If YO and ZO are the bisectors of ÐXYZ and ÐXZY respectively, then ÐOZY and ÐYOZ are

In the given $capital delta X Y Z comma angle X equals 62 to the power of 0 end exponent comma angle X Y Z equals 54 to the power of ring operator end exponent$ If YO and ZO are the bisectors of ÐXYZ and ÐXZY respectively, then ÐOZY and ÐYOZ are

parallel

In the given figure, sides QP and RQ of $capital delta P Q R$ are produced to points S and T respectively If $angle S P R equals 135 to the power of ring operator end exponent text and end text angle P Q T equals 110 to the power of ring operator end exponent$ then $angle text PRQ end text$ is

In the given figure, sides QP and RQ of $capital delta P Q R$ are produced to points S and T respectively If $angle S P R equals 135 to the power of ring operator end exponent text and end text angle P Q T equals 110 to the power of ring operator end exponent$ then $angle text PRQ end text$ is

In the given figure, an equilateral triangle EDC surmounts the square ABCD then the value of x is

In the given figure, an equilateral triangle EDC surmounts the square ABCD then the value of x is

In the given figure, AD BC $perpendicular$ and AE is the bisector of $angle$ BAC Then $angle$ DAE is

In the given figure, AD BC $perpendicular$ and AE is the bisector of $angle$ BAC Then $angle$ DAE is

parallel

In the given figure, XY is parallel to PQ, then the measures of the angles x⁰ and y⁰ are

In the given figure, XY is parallel to PQ, then the measures of the angles x⁰ and y⁰ are

In the given figure the sides AB and AC of a triangle are produced The bisectors of exterior angles B and C so formed intersect each other at point O $angle$ BOC is

In the given figure the sides AB and AC of a triangle are produced The bisectors of exterior angles B and C so formed intersect each other at point O $angle$ BOC is

In the given figure, the bisectors of $angle$ Q and $angle$ R meet at the point O then $angle$ QOR is

In the given figure, the bisectors of $angle$ Q and $angle$ R meet at the point O then $angle$ QOR is

parallel

In the given figure, $text PQ end text parallel to text SR end text text end text text If end text x equals fraction numerator 3 over denominator 5 end fraction y text and end text y equals fraction numerator 5 over denominator 7 end fraction z$ then the values of x, y and z are

In the given figure, $text PQ end text parallel to text SR end text text end text text If end text x equals fraction numerator 3 over denominator 5 end fraction y text and end text y equals fraction numerator 5 over denominator 7 end fraction z$ then the values of x, y and z are

In the triangle ABC, BC = CD and ( $angle$ ABC – $angle$ BA(c) = 30° The measure of $angle$ ABD is:

In the triangle ABC, BC = CD and ( $angle$ ABC – $angle$ BA(c) = 30° The measure of $angle$ ABD is:

In the figure below, the perimeter of the quadrilateral is 46cm, then the area of that quadrilateral is

In the figure below, the perimeter of the quadrilateral is 46cm, then the area of that quadrilateral is

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.