Physics-
General
Easy

Question

Velocity-time graph of a particle of mass 2 kg moving in a straight line is as shown in figure. Work done by all forces on the particle is

  1. 400 J    
  2. negative 400 blank J    
  3. negative 200 blank J    
  4. 200 J    

The correct answer is: negative 400 blank J


    Initial velocity of particle, v subscript i end subscript equals 20 blank m s to the power of negative 1 end exponent
    Final velocity of the particle, v subscript f end subscript equals 0
    According to work-energy theorem,
    W subscript n e t end subscript equals increment K E equals K subscript f end subscript minus K subscript i end subscript
    equals fraction numerator 1 over denominator 2 end fraction m left parenthesis v subscript f end subscript superscript 2 end superscript minus v subscript i end subscript superscript 2 end superscript right parenthesis
    equals fraction numerator 1 over denominator 2 end fraction cross times 2 left parenthesis 0 to the power of 2 end exponent minus 20 to the power of 2 end exponent right parenthesis
    equals negative 400 blank J

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