Physics-
General
Easy

Question

Which of the following diagrams, shows correctly the dispersion of white light by a prism

  1.    
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The correct answer is:


    Because in dispersion of white light, the rays of different colours are not parallel to each other. Also deviation takes place in same direction.

    Related Questions to study

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    A ray of light incident normally on an isosceles right angled prism travels as shown in the figure. The least value of the refractive index of the prism must be

    A ray of light incident normally on an isosceles right angled prism travels as shown in the figure. The least value of the refractive index of the prism must be

    physics-General
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    A ray of monochromatic light is incident on one refracting face of a prism of angle 75 to the power of ring operator end exponent. It passes through the prism and is incident on the other face at the critical angle. If the refractive index of the material of the prism is square root of 2, the angle of incidence on the first face of the prism is

    From figure
    A equals r subscript 1 end subscript plus c equals r subscript 1 end subscript plus sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator mu end fraction close parentheses
    rightwards double arrow r subscript 1 end subscript equals 75 minus sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator mu end fraction close parentheses
    rightwards double arrow 75 minus 45 equals 3 0 to the power of o end exponent
    From Snell’s law At B
    mu equals fraction numerator sin invisible function application i over denominator sin invisible function application r subscript 1 end subscript end fraction rightwards double arrow square root of 2 equals fraction numerator sin invisible function application i over denominator sin invisible function application 3 0 to the power of o end exponent end fraction

    A ray of monochromatic light is incident on one refracting face of a prism of angle 75 to the power of ring operator end exponent. It passes through the prism and is incident on the other face at the critical angle. If the refractive index of the material of the prism is square root of 2, the angle of incidence on the first face of the prism is

    physics-General
    From figure
    A equals r subscript 1 end subscript plus c equals r subscript 1 end subscript plus sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator mu end fraction close parentheses
    rightwards double arrow r subscript 1 end subscript equals 75 minus sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator mu end fraction close parentheses
    rightwards double arrow 75 minus 45 equals 3 0 to the power of o end exponent
    From Snell’s law At B
    mu equals fraction numerator sin invisible function application i over denominator sin invisible function application r subscript 1 end subscript end fraction rightwards double arrow square root of 2 equals fraction numerator sin invisible function application i over denominator sin invisible function application 3 0 to the power of o end exponent end fraction
    General
    physics-

    A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 34°. If the shaded half of the prism is knocked off, the ray will

    By formula delta equals left parenthesis n minus 1 right parenthesis A rightwards double arrow 34 equals left parenthesis n minus 1 right parenthesis A and in the second position delta to the power of ´ end exponent equals left parenthesis n minus 1 right parenthesis fraction numerator A over denominator 2 end fraction
    therefore fraction numerator 34 over denominator delta to the power of ´ end exponent end fraction equals fraction numerator left parenthesis n minus 1 right parenthesis A over denominator left parenthesis n minus 1 right parenthesis fraction numerator A over denominator 2 end fraction end fraction or delta to the power of ´ end exponent equals fraction numerator 34 over denominator 2 end fraction equals 1 7 to the power of o end exponent

    A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 34°. If the shaded half of the prism is knocked off, the ray will

    physics-General
    By formula delta equals left parenthesis n minus 1 right parenthesis A rightwards double arrow 34 equals left parenthesis n minus 1 right parenthesis A and in the second position delta to the power of ´ end exponent equals left parenthesis n minus 1 right parenthesis fraction numerator A over denominator 2 end fraction
    therefore fraction numerator 34 over denominator delta to the power of ´ end exponent end fraction equals fraction numerator left parenthesis n minus 1 right parenthesis A over denominator left parenthesis n minus 1 right parenthesis fraction numerator A over denominator 2 end fraction end fraction or delta to the power of ´ end exponent equals fraction numerator 34 over denominator 2 end fraction equals 1 7 to the power of o end exponent
    parallel
    General
    physics-

    A prism ABC of angle 30° has its face AC silvered. A ray of light incident at an angle of 45° at the face AB retraces its path after refraction at face AB and reflection at face AC. The refractive index of the material of the prism is

    A prism ABC of angle 30° has its face AC silvered. A ray of light incident at an angle of 45° at the face AB retraces its path after refraction at face AB and reflection at face AC. The refractive index of the material of the prism is

    physics-General
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    A ray of light passes through an equilateral glass prism in such a manner that the angle of incidence is equal to the angle of emergence and each of these angles is equal to 3/4 of the angle of the prism. The angle of deviation is

    Is a band spectrum
    In the position of minimum deviation
    2 i equals A plus delta subscript m end subscript or delta subscript m end subscript equals 2 i minus A equals 90 minus 60 equals 3 0 to the power of o end exponent

    A ray of light passes through an equilateral glass prism in such a manner that the angle of incidence is equal to the angle of emergence and each of these angles is equal to 3/4 of the angle of the prism. The angle of deviation is

    physics-General
    Is a band spectrum
    In the position of minimum deviation
    2 i equals A plus delta subscript m end subscript or delta subscript m end subscript equals 2 i minus A equals 90 minus 60 equals 3 0 to the power of o end exponent
    General
    physics-

    A small particle of mass m blankis projected at an angle theta with the x-axis with an initial velocity v subscript 0 end subscript in the x-y plane as shown in the figure. A t blank a blank t i m e blank t less than fraction numerator v subscript 0 end subscript sin invisible function application theta over denominator g end fraction comma the angular momentum of the particle is

    L equals m open parentheses r cross times v close parentheses
    L equals m open square brackets v subscript 0 end subscript c o s theta blank t stack stack i with dot on top with hat on top plus open parentheses v subscript 0 end subscript s i n theta blank t minus fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent close parentheses stack stack j with dot on top with hat on top close square brackets
    cross times open square brackets v subscript 0 end subscript c o s theta blank stack stack i with dot on top with hat on top plus open parentheses v subscript 0 end subscript s i n theta minus g t close parentheses stack stack j with dot on top with hat on top close square brackets
    equals m v subscript 0 end subscript c o s theta blank t open square brackets negative fraction numerator 1 over denominator 2 end fraction g t close square brackets stack k with hat on top
    equals negative fraction numerator 1 over denominator 2 end fraction m g v subscript 0 end subscript t to the power of 2 end exponent c o s theta stack k with hat on top

    A small particle of mass m blankis projected at an angle theta with the x-axis with an initial velocity v subscript 0 end subscript in the x-y plane as shown in the figure. A t blank a blank t i m e blank t less than fraction numerator v subscript 0 end subscript sin invisible function application theta over denominator g end fraction comma the angular momentum of the particle is

    physics-General
    L equals m open parentheses r cross times v close parentheses
    L equals m open square brackets v subscript 0 end subscript c o s theta blank t stack stack i with dot on top with hat on top plus open parentheses v subscript 0 end subscript s i n theta blank t minus fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent close parentheses stack stack j with dot on top with hat on top close square brackets
    cross times open square brackets v subscript 0 end subscript c o s theta blank stack stack i with dot on top with hat on top plus open parentheses v subscript 0 end subscript s i n theta minus g t close parentheses stack stack j with dot on top with hat on top close square brackets
    equals m v subscript 0 end subscript c o s theta blank t open square brackets negative fraction numerator 1 over denominator 2 end fraction g t close square brackets stack k with hat on top
    equals negative fraction numerator 1 over denominator 2 end fraction m g v subscript 0 end subscript t to the power of 2 end exponent c o s theta stack k with hat on top
    parallel
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    physics-

    The figures represent three cases of a ray passing through a prism of angle A. The case corresponding to minimum deviation is

    The figures represent three cases of a ray passing through a prism of angle A. The case corresponding to minimum deviation is

    physics-General
    General
    Maths-

    If the normal at the point straight P left parenthesis theta right parenthesis to the ellipse x squared over 14 plus y squared over 5 equals 1 intersects it again at the point straight Q left parenthesis 2 theta right parenthesis, then cos space theta is

    G i v e n comma space t h e space e q u a t i o n space o f space e l l i p s e space x squared over 14 plus y squared over 5 equals 1
O n space c o m p a r i n g space w i t h space s tan d a r d space e q u a t i o n space o f space e l l i p s e space x squared over a squared plus y squared over b squared equals 1
a squared equals 14 space a n d space b squared equals 5
w e space k n o w space t h a t comma space p o i n t space o n space a n space e l l i p s e space i n space t h e space p a r a m e t r i c space f o r m space i s space left parenthesis a cos space x comma space b space sin space x right parenthesis
S o comma space P open parentheses theta close parentheses equals left parenthesis a cos theta comma space b sin theta right parenthesis
space space space space space space space space Q left parenthesis 2 theta right parenthesis equals left parenthesis a cos 2 theta comma space b sin 2 theta right parenthesis
s l o p e space o f space l i n e space P Q space equals fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction equals fraction numerator b sin 2 theta minus b sin theta over denominator a cos 2 theta minus a cos theta end fraction
A l s o comma space s l o p e space o f space n o r m a l space equals space a over b tan theta
A s space t h e space n o r a m l space p a s s e s space t h r o u g h space P Q comma
fraction numerator b sin 2 theta minus b sin theta over denominator a cos 2 theta minus a cos theta end fraction equals a over b tan theta
fraction numerator b left parenthesis sin 2 theta minus sin theta right parenthesis over denominator a left parenthesis cos 2 theta minus cos theta right parenthesis end fraction equals a over b fraction numerator sin theta over denominator cos theta end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets tan theta equals fraction numerator sin theta over denominator cos theta end fraction close square brackets
fraction numerator b left parenthesis 2 sin theta cos theta minus sin theta right parenthesis over denominator a left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis end fraction equals a over b fraction numerator sin theta over denominator cos theta end fraction space space space space space space space space space space space space space space space space open square brackets sin 2 theta equals 2 sin theta. cos theta space a n d space cos 2 theta equals 2 cos squared theta minus 1 close square brackets
fraction numerator b sin theta left parenthesis 2 cos theta minus 1 right parenthesis over denominator a left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis end fraction equals a over b fraction numerator sin theta over denominator cos theta end fraction
fraction numerator b left parenthesis 2 cos theta minus 1 right parenthesis over denominator a left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis end fraction equals a over b fraction numerator 1 over denominator cos theta end fraction
fraction numerator b squared left parenthesis 2 cos theta minus 1 right parenthesis over denominator a squared left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis end fraction equals fraction numerator 1 over denominator cos theta end fraction
fraction numerator 5 left parenthesis 2 cos theta minus 1 right parenthesis over denominator 14 left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis end fraction equals fraction numerator 1 over denominator cos theta end fraction
5 left parenthesis 2 cos theta minus 1 right parenthesis cos theta equals 14 left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis
10 cos squared theta minus 5 cos theta equals 28 cos squared theta minus 14 minus 14 cos theta
28 cos squared theta minus 10 cos squared theta minus 14 cos theta plus cos theta minus 14 equals 0
18 cos squared theta minus 9 cos theta minus 14 equals 0
18 cos squared theta minus 21 cos theta plus 12 cos theta minus 14 equals 0
3 cos theta left parenthesis 6 cos theta minus 7 right parenthesis plus 2 left parenthesis 6 cos theta minus 7 right parenthesis equals 0
left parenthesis 3 cos theta plus 2 right parenthesis left parenthesis 6 cos theta minus 7 right parenthesis equals 0
i f comma left parenthesis 6 cos theta minus 7 right parenthesis equals 0
cos theta equals 7 over 6 space n o t space p o s s i b l e space a s space v a l u e space a c n space n o t space b e space g r e a t e r space t h a n space 1.
i f left parenthesis 3 cos theta plus 2 right parenthesis equals 0
cos theta equals fraction numerator negative 2 over denominator 3 end fraction
S o comma space t h e space r e q u i r e d space a n s w e r space i s space fraction numerator negative 2 over denominator 3 end fraction.

 

    If the normal at the point straight P left parenthesis theta right parenthesis to the ellipse x squared over 14 plus y squared over 5 equals 1 intersects it again at the point straight Q left parenthesis 2 theta right parenthesis, then cos space theta is

    Maths-General
    G i v e n comma space t h e space e q u a t i o n space o f space e l l i p s e space x squared over 14 plus y squared over 5 equals 1
O n space c o m p a r i n g space w i t h space s tan d a r d space e q u a t i o n space o f space e l l i p s e space x squared over a squared plus y squared over b squared equals 1
a squared equals 14 space a n d space b squared equals 5
w e space k n o w space t h a t comma space p o i n t space o n space a n space e l l i p s e space i n space t h e space p a r a m e t r i c space f o r m space i s space left parenthesis a cos space x comma space b space sin space x right parenthesis
S o comma space P open parentheses theta close parentheses equals left parenthesis a cos theta comma space b sin theta right parenthesis
space space space space space space space space Q left parenthesis 2 theta right parenthesis equals left parenthesis a cos 2 theta comma space b sin 2 theta right parenthesis
s l o p e space o f space l i n e space P Q space equals fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction equals fraction numerator b sin 2 theta minus b sin theta over denominator a cos 2 theta minus a cos theta end fraction
A l s o comma space s l o p e space o f space n o r m a l space equals space a over b tan theta
A s space t h e space n o r a m l space p a s s e s space t h r o u g h space P Q comma
fraction numerator b sin 2 theta minus b sin theta over denominator a cos 2 theta minus a cos theta end fraction equals a over b tan theta
fraction numerator b left parenthesis sin 2 theta minus sin theta right parenthesis over denominator a left parenthesis cos 2 theta minus cos theta right parenthesis end fraction equals a over b fraction numerator sin theta over denominator cos theta end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets tan theta equals fraction numerator sin theta over denominator cos theta end fraction close square brackets
fraction numerator b left parenthesis 2 sin theta cos theta minus sin theta right parenthesis over denominator a left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis end fraction equals a over b fraction numerator sin theta over denominator cos theta end fraction space space space space space space space space space space space space space space space space open square brackets sin 2 theta equals 2 sin theta. cos theta space a n d space cos 2 theta equals 2 cos squared theta minus 1 close square brackets
fraction numerator b sin theta left parenthesis 2 cos theta minus 1 right parenthesis over denominator a left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis end fraction equals a over b fraction numerator sin theta over denominator cos theta end fraction
fraction numerator b left parenthesis 2 cos theta minus 1 right parenthesis over denominator a left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis end fraction equals a over b fraction numerator 1 over denominator cos theta end fraction
fraction numerator b squared left parenthesis 2 cos theta minus 1 right parenthesis over denominator a squared left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis end fraction equals fraction numerator 1 over denominator cos theta end fraction
fraction numerator 5 left parenthesis 2 cos theta minus 1 right parenthesis over denominator 14 left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis end fraction equals fraction numerator 1 over denominator cos theta end fraction
5 left parenthesis 2 cos theta minus 1 right parenthesis cos theta equals 14 left parenthesis 2 cos squared theta minus 1 minus cos theta right parenthesis
10 cos squared theta minus 5 cos theta equals 28 cos squared theta minus 14 minus 14 cos theta
28 cos squared theta minus 10 cos squared theta minus 14 cos theta plus cos theta minus 14 equals 0
18 cos squared theta minus 9 cos theta minus 14 equals 0
18 cos squared theta minus 21 cos theta plus 12 cos theta minus 14 equals 0
3 cos theta left parenthesis 6 cos theta minus 7 right parenthesis plus 2 left parenthesis 6 cos theta minus 7 right parenthesis equals 0
left parenthesis 3 cos theta plus 2 right parenthesis left parenthesis 6 cos theta minus 7 right parenthesis equals 0
i f comma left parenthesis 6 cos theta minus 7 right parenthesis equals 0
cos theta equals 7 over 6 space n o t space p o s s i b l e space a s space v a l u e space a c n space n o t space b e space g r e a t e r space t h a n space 1.
i f left parenthesis 3 cos theta plus 2 right parenthesis equals 0
cos theta equals fraction numerator negative 2 over denominator 3 end fraction
S o comma space t h e space r e q u i r e d space a n s w e r space i s space fraction numerator negative 2 over denominator 3 end fraction.

 
    General
    physics-

    A fighter plane enters inside the enemy territory, at time t equals 0 with velocity v subscript 0 end subscript equals 250 blank m s to the power of negative 1 end exponent and moves horizontally with constant acceleration a equals 20 m s to the power of negative 2 end exponent (see figure). An enemy tank at the border, spot the plane and fire shots at an angle theta equals 60 degree with the horizontal and with velocity u equals 600 blank m s to the power of negative 1 end exponent. At what altitude H of the plane it can be hit by the shot?

    If it is being hit then
    d equals v subscript 0 end subscript t plus fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent equals left parenthesis u cos invisible function application theta right parenthesis t
    or t equals fraction numerator u cos invisible function application theta minus v subscript 0 end subscript over denominator a divided by 2 end fraction

    therefore blank t equals fraction numerator 600 cross times fraction numerator 1 over denominator 2 end fraction minus 250 over denominator 10 end fraction equals 5 blank s
    H equals open parentheses u sin invisible function application theta close parentheses t minus fraction numerator 1 over denominator 2 end fraction cross times g t to the power of 2 end exponent
    equals 600 cross times fraction numerator square root of 3 over denominator 2 end fraction cross times 5 minus fraction numerator 1 over denominator 2 end fraction cross times 10 cross times 25
    H equals 2473 blank m

    A fighter plane enters inside the enemy territory, at time t equals 0 with velocity v subscript 0 end subscript equals 250 blank m s to the power of negative 1 end exponent and moves horizontally with constant acceleration a equals 20 m s to the power of negative 2 end exponent (see figure). An enemy tank at the border, spot the plane and fire shots at an angle theta equals 60 degree with the horizontal and with velocity u equals 600 blank m s to the power of negative 1 end exponent. At what altitude H of the plane it can be hit by the shot?

    physics-General
    If it is being hit then
    d equals v subscript 0 end subscript t plus fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent equals left parenthesis u cos invisible function application theta right parenthesis t
    or t equals fraction numerator u cos invisible function application theta minus v subscript 0 end subscript over denominator a divided by 2 end fraction

    therefore blank t equals fraction numerator 600 cross times fraction numerator 1 over denominator 2 end fraction minus 250 over denominator 10 end fraction equals 5 blank s
    H equals open parentheses u sin invisible function application theta close parentheses t minus fraction numerator 1 over denominator 2 end fraction cross times g t to the power of 2 end exponent
    equals 600 cross times fraction numerator square root of 3 over denominator 2 end fraction cross times 5 minus fraction numerator 1 over denominator 2 end fraction cross times 10 cross times 25
    H equals 2473 blank m
    parallel
    General
    physics-

    A light ray is incident by grazing one of the face of a prism and after refraction ray does not emerge out, what should be the angle of prism while critical angle is C</em

    A light ray is incident by grazing one of the face of a prism and after refraction ray does not emerge out, what should be the angle of prism while critical angle is C</em

    physics-General
    General
    physics-

    A particle of mass m is rotating in a horizontal circle of radius R and is attached to a hanging mass M as shown in the figure. The speed of rotation required by the mass m keep M steady is

    To keep the mass M steady, let T is the tension in the string joining the two. Then for particle m comma
    T equals fraction numerator m v to the power of 2 end exponent over denominator R end fraction open parentheses i close parentheses
    For mass M comma
    T equals M g left parenthesis i i right parenthesis
    From Eqs. (i) and (ii)
    fraction numerator m v to the power of 2 end exponent over denominator R end fraction equals M g ⟹ v equals square root of fraction numerator M g R over denominator m end fraction end root

    A particle of mass m is rotating in a horizontal circle of radius R and is attached to a hanging mass M as shown in the figure. The speed of rotation required by the mass m keep M steady is

    physics-General
    To keep the mass M steady, let T is the tension in the string joining the two. Then for particle m comma
    T equals fraction numerator m v to the power of 2 end exponent over denominator R end fraction open parentheses i close parentheses
    For mass M comma
    T equals M g left parenthesis i i right parenthesis
    From Eqs. (i) and (ii)
    fraction numerator m v to the power of 2 end exponent over denominator R end fraction equals M g ⟹ v equals square root of fraction numerator M g R over denominator m end fraction end root
    General
    physics-

    Figure shows the variation of the stopping potential (V0) with the frequency (v) of theincident radiations for two different photosensitive material M1 and M2 .What are the values of work functions for M1 and M2 respectively

    Figure shows the variation of the stopping potential (V0) with the frequency (v) of theincident radiations for two different photosensitive material M1 and M2 .What are the values of work functions for M1 and M2 respectively

    physics-General
    parallel
    General
    physics-

    The respective angles of the flint and crown glass prisms are A to the power of apostrophe and A. They are to be used for dispersion without deviation, then the ratio of their angles A apostrophe divided by A will be

    Since A left parenthesis mu subscript y end subscript minus 1 right parenthesis plus A to the power of ´ end exponent left parenthesis mu subscript y ´ end subscript minus 1 right parenthesis equals 0 rightwards double arrow fraction numerator A to the power of ´ end exponent over denominator A end fraction equals negative open parentheses fraction numerator mu subscript y end subscript minus 1 over denominator mu subscript y ´ end subscript minus 1 end fraction close parentheses

    The respective angles of the flint and crown glass prisms are A to the power of apostrophe and A. They are to be used for dispersion without deviation, then the ratio of their angles A apostrophe divided by A will be

    physics-General
    Since A left parenthesis mu subscript y end subscript minus 1 right parenthesis plus A to the power of ´ end exponent left parenthesis mu subscript y ´ end subscript minus 1 right parenthesis equals 0 rightwards double arrow fraction numerator A to the power of ´ end exponent over denominator A end fraction equals negative open parentheses fraction numerator mu subscript y end subscript minus 1 over denominator mu subscript y ´ end subscript minus 1 end fraction close parentheses
    General
    physics-

    The two lines A and B shown in figure are the agraphs of the de Broglie wavelength l as function of fraction numerator 1 over denominator square root of V end fraction (V is the accelerating potential) for two particles having the same charge
    Which of the two represents the particle of heavier mass ?

    The two lines A and B shown in figure are the agraphs of the de Broglie wavelength l as function of fraction numerator 1 over denominator square root of V end fraction (V is the accelerating potential) for two particles having the same charge
    Which of the two represents the particle of heavier mass ?

    physics-General
    General
    physics-

    In a photoelectric experiment anode potential is plotted against plate current

    In a photoelectric experiment anode potential is plotted against plate current

    physics-General
    parallel

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