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Physics

General

Easy

Question

Rockets are launched in eastward direction to take advantage of

the clear sky on eastern side
the thinner atmosphere on this side
earth's rotation
earth's tilt

The correct answer is: earth's rotation

Related Questions to study

The additional K.E. to be provided to a satellite of mass m revolving around a planet of mass M , to transfer it from a circular orbit of radius R₁ to another radius R₂(R₂>R₁) is

The additional K.E. to be provided to a satellite of mass m revolving around a planet of mass M , to transfer it from a circular orbit of radius R₁ to another radius R₂(R₂>R₁) is

A reduction in atomic size with increase in atomic number is a characteristic of elements of

This is a characteristic of f-block elements (lanthanoid contraction)

A reduction in atomic size with increase in atomic number is a characteristic of elements of

chemistry-General

This is a characteristic of f-block elements (lanthanoid contraction)

A satellite moves in a circle around the earth, the radius of this circle is equal to one half of the radius of the moon's orbit the satellite completes one revolution in

A satellite moves in a circle around the earth, the radius of this circle is equal to one half of the radius of the moon's orbit the satellite completes one revolution in

parallel

Two satellites A and B go round a planet in circular orbits having rarely 4 R and If the speed of satellite A is 3V, then speed of satellite B is

Two satellites A and B go round a planet in circular orbits having rarely 4 R and If the speed of satellite A is 3V, then speed of satellite B is

The yellow coloured solution of salt of chromate ions change to orange colour on acidification due to the formation of

2 C r O subscript 4 end subscript superscript 2 minus end superscript plus 2 H to the power of plus end exponent rightwards arrow C r subscript 2 end subscript O subscript 7 end subscript superscript 2 minus end superscript plus H subscript 2 end subscript O

The yellow coloured solution of salt of chromate ions change to orange colour on acidification due to the formation of

chemistry-General

2 C r O subscript 4 end subscript superscript 2 minus end superscript plus 2 H to the power of plus end exponent rightwards arrow C r subscript 2 end subscript O subscript 7 end subscript superscript 2 minus end superscript plus H subscript 2 end subscript O

A person sitting in a chair in a satellite feels weightless because

A person sitting in a chair in a satellite feels weightless because

parallel

The time period of a satellite of earth is 5 hours If the separation between the earth and the satellite is increased to four times the previous value, the new time period will become ...... Hours

The time period of a satellite of earth is 5 hours If the separation between the earth and the satellite is increased to four times the previous value, the new time period will become ...... Hours

If $A equals open square brackets table row 4 cell x plus 2 end cell row cell 2 x minus 3 end cell cell x plus 1 end cell end table close square brackets$ is symmetric then trace of A is

If $A equals open square brackets table row 4 cell x plus 2 end cell row cell 2 x minus 3 end cell cell x plus 1 end cell end table close square brackets$ is symmetric then trace of A is

The oxidation number of Mn in the product of alkaline oxidative fusion of MnO₂ is

2 M n O subscript 2 end subscript plus 4 K O H plus O subscript 2 end subscript rightwards arrow 2 K subscript 2 end subscript stack M with plus 6 on top n O subscript 4 end subscript plus 2 H subscript 2 end subscript O

The oxidation number of Mn in the product of alkaline oxidative fusion of MnO₂ is

chemistry-General

2 M n O subscript 2 end subscript plus 4 K O H plus O subscript 2 end subscript rightwards arrow 2 K subscript 2 end subscript stack M with plus 6 on top n O subscript 4 end subscript plus 2 H subscript 2 end subscript O

parallel

When a satellite going round the earth in a circular orbit of radius r and speed v loses some of its energy, then r and v changes as

When a satellite going round the earth in a circular orbit of radius r and speed v loses some of its energy, then r and v changes as

If $f open parentheses x close parentheses equals vertical line log subscript 10 end subscript invisible function application x vertical line$ , then at $x equals 1$

As is evident from the graph of

f left parenthesis x right parenthesis

that it is continuous but not differentiable at

x equals 1

f to the power of ´ ´ end exponent open parentheses 1 to the power of plus end exponent close parentheses equals stack lim with x rightwards arrow 1 to the power of plus end exponent below invisible function application fraction numerator f open parentheses x close parentheses minus f left parenthesis 1 right parenthesis over denominator x minus 1 end fraction

rightwards double arrow f to the power of ´ ´ end exponent open parentheses 1 to the power of plus end exponent close parentheses equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator f open parentheses 1 plus h close parentheses minus f left parenthesis 1 right parenthesis over denominator h end fraction

rightwards double arrow f to the power of ´ ´ end exponent open parentheses 1 to the power of plus end exponent close parentheses equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator log subscript 10 end subscript invisible function application open parentheses 1 plus h close parentheses minus 0 over denominator h end fraction

rightwards double arrow f to the power of ´ ´ end exponent open parentheses 1 to the power of plus end exponent close parentheses equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator log invisible function application left parenthesis 1 plus h right parenthesis over denominator h. log subscript e end subscript invisible function application 10 end fraction equals fraction numerator 1 over denominator log subscript e end subscript invisible function application 10 end fraction equals log subscript 10 end subscript invisible function application e

f to the power of ´ ´ end exponent open parentheses 1 to the power of minus end exponent close parentheses equals stack lim with x rightwards arrow 1 to the power of plus end exponent below invisible function application fraction numerator f open parentheses x close parentheses minus f left parenthesis 1 right parenthesis over denominator x minus 1 end fraction

rightwards double arrow f to the power of ´ ´ end exponent open parentheses 1 to the power of minus end exponent close parentheses equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator f open parentheses 1 minus h close parentheses minus f left parenthesis 1 right parenthesis over denominator h end fraction

rightwards double arrow f to the power of ´ ´ end exponent open parentheses 1 to the power of minus end exponent close parentheses equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator log subscript 10 end subscript invisible function application open parentheses 1 minus h close parentheses over denominator h end fraction equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator log subscript e end subscript invisible function application left parenthesis 1 minus h right parenthesis over denominator h log subscript e end subscript invisible function application 10 end fraction equals negative log subscript 10 end subscript invisible function application e

If $f open parentheses x close parentheses equals vertical line log subscript 10 end subscript invisible function application x vertical line$ , then at $x equals 1$

As is evident from the graph of

f left parenthesis x right parenthesis

that it is continuous but not differentiable at

x equals 1

f to the power of ´ ´ end exponent open parentheses 1 to the power of plus end exponent close parentheses equals stack lim with x rightwards arrow 1 to the power of plus end exponent below invisible function application fraction numerator f open parentheses x close parentheses minus f left parenthesis 1 right parenthesis over denominator x minus 1 end fraction

rightwards double arrow f to the power of ´ ´ end exponent open parentheses 1 to the power of plus end exponent close parentheses equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator f open parentheses 1 plus h close parentheses minus f left parenthesis 1 right parenthesis over denominator h end fraction

rightwards double arrow f to the power of ´ ´ end exponent open parentheses 1 to the power of plus end exponent close parentheses equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator log subscript 10 end subscript invisible function application open parentheses 1 plus h close parentheses minus 0 over denominator h end fraction

rightwards double arrow f to the power of ´ ´ end exponent open parentheses 1 to the power of plus end exponent close parentheses equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator log invisible function application left parenthesis 1 plus h right parenthesis over denominator h. log subscript e end subscript invisible function application 10 end fraction equals fraction numerator 1 over denominator log subscript e end subscript invisible function application 10 end fraction equals log subscript 10 end subscript invisible function application e

f to the power of ´ ´ end exponent open parentheses 1 to the power of minus end exponent close parentheses equals stack lim with x rightwards arrow 1 to the power of plus end exponent below invisible function application fraction numerator f open parentheses x close parentheses minus f left parenthesis 1 right parenthesis over denominator x minus 1 end fraction

rightwards double arrow f to the power of ´ ´ end exponent open parentheses 1 to the power of minus end exponent close parentheses equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator f open parentheses 1 minus h close parentheses minus f left parenthesis 1 right parenthesis over denominator h end fraction

rightwards double arrow f to the power of ´ ´ end exponent open parentheses 1 to the power of minus end exponent close parentheses equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator log subscript 10 end subscript invisible function application open parentheses 1 minus h close parentheses over denominator h end fraction equals stack lim with h rightwards arrow 0 below invisible function application fraction numerator log subscript e end subscript invisible function application left parenthesis 1 minus h right parenthesis over denominator h log subscript e end subscript invisible function application 10 end fraction equals negative log subscript 10 end subscript invisible function application e

If $open parentheses table row cell x minus 2 y end cell cell 5 y end cell row 6 cell a minus 2 b end cell end table close parentheses equals 5 open parentheses table attributes columnalign left end attributes row 4 2 row cell fraction numerator b over denominator 5 end fraction end cell 6 end table close parentheses$ then a=x

If $open parentheses table row cell x minus 2 y end cell cell 5 y end cell row 6 cell a minus 2 b end cell end table close parentheses equals 5 open parentheses table attributes columnalign left end attributes row 4 2 row cell fraction numerator b over denominator 5 end fraction end cell 6 end table close parentheses$ then a=x

parallel

Which of the following statements about the interstitial compounds is incorrect?

Interstitial compounds are chemically inert, so, choice (2) is incorrect

Which of the following statements about the interstitial compounds is incorrect?

chemistry-General

Interstitial compounds are chemically inert, so, choice (2) is incorrect

Potential energy of a satellite having mass m and rotating at a height of 6.4 $cross times 10 to the power of 6$ m from the surface of earth

Potential energy of a satellite having mass m and rotating at a height of 6.4 $cross times 10 to the power of 6$ m from the surface of earth

The slant height of a cone is fixed as 7 cm. If the rate of increase in its height is 0.3 cm/sec. Then the rate of increase in volume when the height is 4cm

The slant height of a cone is fixed as 7 cm. If the rate of increase in its height is 0.3 cm/sec. Then the rate of increase in volume when the height is 4cm

parallel

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