science
Grade-7
Easy

Question

A car moving at a velocity of 6.5 m/s increases its velocity uniformly to 78 m/s in 10 s. Work out its acceleration with a proper sign.

  1. + 7.15 m/s2
  2. +8.2 m/s2
  3. -7.15 m/s2
  4. +-8.25 m/s2

hintHint:

Final velocity(v) = Initial velocity(u) + acceleration(across times time(t).

The correct answer is: + 7.15 m/s2


    Given:
    Initial velocity (u) = 6.5ms-1
    Final velocity (v) = 78ms-1
    Time taken (t) = 10s
    Acceleration (a) =?
    Formula:
    v = u + at 
    Solution: 
    78 space equals space 6.5 space plus thin space a space cross times space 10 space
a space equals space fraction numerator 78 space minus space 6.5 over denominator 10 end fraction space equals space fraction numerator plus 71.5 over denominator 10 end fraction space equals space plus 7.15 m s to the power of negative 2 end exponent
    ANSWER: 
    acceleration of a car is +7.15ms-2

    Positive acceleration means the direction of acceleration is same as of the direction of velocity.

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