Science
Ingestion-and-Digestion-1
Easy

Question

Consider a finite charged rod. Electric field at Point P (shown) makes an angle theta with horizontal dotted line then angle theta is :-

  1. 60 to the power of ring operator end exponent  
  2. 28 to the power of ring operator end exponent   
  3. 44 to the power of ring operator end exponent   
  4. information insufficient  

The correct answer is: 28 to the power of ring operator end exponent


    Required angle equals fraction numerator theta subscript 2 end subscript minus theta subscript 1 end subscript over denominator 2 end fraction equals fraction numerator 88 to the power of ring operator end exponent minus 32 to the power of ring operator end exponent over denominator 2 end fraction equals fraction numerator 56 to the power of ring operator end exponent over denominator 2 end fraction equals 28 to the power of ring operator end exponent

    Book A Free Demo

    +91

    Grade*

    Related Questions to study

    ingestion-and-digestion-1
    science

    The diagram shows a uniformly charged hemisphere of radius R. It has volume charge density rho. If the electric field at a point 2R distance above its centre is E then what is the electric field at the point which is 2R below its centre?

    Apply principle of superposition
    Electric field due to a uniformly charged sphere =fraction numerator rho R over denominator 12 epsilon subscript 0 end subscript end fraction semicolon E subscript text reuliani  end text end subscript equals fraction numerator rho R over denominator 12 ϵ subscript 0 end subscript end fraction minus E

    The diagram shows a uniformly charged hemisphere of radius R. It has volume charge density rho. If the electric field at a point 2R distance above its centre is E then what is the electric field at the point which is 2R below its centre?
    scienceingestion-and-digestion-1

    Apply principle of superposition
    Electric field due to a uniformly charged sphere =fraction numerator rho R over denominator 12 epsilon subscript 0 end subscript end fraction semicolon E subscript text reuliani  end text end subscript equals fraction numerator rho R over denominator 12 ϵ subscript 0 end subscript end fraction minus E

    ingestion-and-digestion-1
    science

    A metallic rod of length l rotates at angular velocity omega about an axis passing through one end and perpendiuclar to the rod. If mass of electron is m and its charge is –e then the magnitude of potential difference between its two ends is

    When rod rotates the centripetal acceleration of electron comes from electric field E equals fraction numerator m r omega to the power of 2 end exponent over denominator e end fraction
    Thus, Error converting from MathML to accessible text.

    A metallic rod of length l rotates at angular velocity omega about an axis passing through one end and perpendiuclar to the rod. If mass of electron is m and its charge is –e then the magnitude of potential difference between its two ends is

    scienceingestion-and-digestion-1
    When rod rotates the centripetal acceleration of electron comes from electric field E equals fraction numerator m r omega to the power of 2 end exponent over denominator e end fraction
    Thus, Error converting from MathML to accessible text.
    ingestion-and-digestion-1
    science

    Uniform electric field of magnitude 100 V/m in space is directed along the line y equals 3 plus x. Find the potential difference between point A (3, 1) & B (1,3).

    Slope of line A B equals fraction numerator 3 minus 1 over denominator 1 minus 3 end fraction equals negative 1 which is perpendicular to direction of electric field

    Uniform electric field of magnitude 100 V/m in space is directed along the line y equals 3 plus x. Find the potential difference between point A (3, 1) & B (1,3).

    scienceingestion-and-digestion-1
    Slope of line A B equals fraction numerator 3 minus 1 over denominator 1 minus 3 end fraction equals negative 1 which is perpendicular to direction of electric field
    ingestion-and-digestion-1
    science

    A small electric dipole is placed at origin with its dipole moment directed along positive x-axis. The direction of electric field at point left parenthesis 2 comma times 2 square root of 2 comma 0 right parenthesis is

    tan invisible function application theta equals fraction numerator y over denominator x end fraction equals square root of 2 semicolon cot invisible function application theta equals fraction numerator 1 over denominator square root of 2 end fraction text  Also  end text tan invisible function application alpha equals fraction numerator tan invisible function application theta over denominator 2 end fraction equals fraction numerator 1 over denominator square root of 2 end fraction equals cot invisible function application theta rightwards double arrow theta plus alpha equals 90 to the power of ring operator end exponent

    A small electric dipole is placed at origin with its dipole moment directed along positive x-axis. The direction of electric field at point left parenthesis 2 comma times 2 square root of 2 comma 0 right parenthesis is

    scienceingestion-and-digestion-1
    tan invisible function application theta equals fraction numerator y over denominator x end fraction equals square root of 2 semicolon cot invisible function application theta equals fraction numerator 1 over denominator square root of 2 end fraction text  Also  end text tan invisible function application alpha equals fraction numerator tan invisible function application theta over denominator 2 end fraction equals fraction numerator 1 over denominator square root of 2 end fraction equals cot invisible function application theta rightwards double arrow theta plus alpha equals 90 to the power of ring operator end exponent
    ingestion-and-digestion-1
    science

    Four charges are placed at the circumference of a dial clock as shown in figure If the clock has only hour hand, then the resultant force on a charge q subscript 0 end subscript placed at the centre, points in the direction which shows the time as :–

    Four charges are placed at the circumference of a dial clock as shown in figure If the clock has only hour hand, then the resultant force on a charge q subscript 0 end subscript placed at the centre, points in the direction which shows the time as :–
    scienceingestion-and-digestion-1

    ingestion-and-digestion-1
    science

    For a spherically symmetrical charge distribution, electric field at a distance r from the centre of sphere is stack E with rightwards arrow on top equals k r to the power of 7 end exponent r where k is a constant. What will be the volume charge density at a distance r from the centre of sphere ?

    By using Gauss law Error converting from MathML to accessible text.
    (Note : Check dimensionally that r µ r6 )

    Error converting from MathML to accessible text.

    For a spherically symmetrical charge distribution, electric field at a distance r from the centre of sphere is stack E with rightwards arrow on top equals k r to the power of 7 end exponent r where k is a constant. What will be the volume charge density at a distance r from the centre of sphere ?

    scienceingestion-and-digestion-1
    By using Gauss law Error converting from MathML to accessible text.
    (Note : Check dimensionally that r µ r6 )

    Error converting from MathML to accessible text.
    ingestion-and-digestion-1
    science

    Two positrons (e+) and two protons (P) are kept on four corners of a square of side a as shown in figure. The mass of proton is much larger than the mass of positron. Let q denotes the charge on the proton as well as the positron then the kinetic energies of one of the positrons and one of the protons respectively after a very long time will be
    As mass of proton mass of positron so initial acceleration of positron is much larger than proton. Therefore positron reach far away in very short time as compare to proton

    2 K subscript e to the power of ´ end exponent end subscript equals open parentheses fraction numerator 4 k q to the power of 2 end exponent over denominator a end fraction plus fraction numerator 2 k q to the power of 2 end exponent over denominator a square root of 2 end fraction close parentheses minus fraction numerator k q to the power of 2 end exponent over denominator a square root of 2 end fraction rightwards double arrow K subscript e to the power of ´ end exponent end subscript equals fraction numerator q to the power of 2 end exponent over denominator 2 pi ϵ subscript 0 end subscript a end fraction open parentheses 1 plus fraction numerator 1 over denominator 4 square root of 2 end fraction close parentheses text  and  end text 2 K subscript p end subscript equals fraction numerator k q to the power of 2 end exponent over denominator a square root of 2 end fraction minus 0 rightwards double arrow K subscript p end subscript equals fraction numerator q to the power of 2 end exponent over denominator 8 square root of 2 pi ϵ subscript 0 end subscript a end fraction

    Two positrons (e+) and two protons (P) are kept on four corners of a square of side a as shown in figure. The mass of proton is much larger than the mass of positron. Let q denotes the charge on the proton as well as the positron then the kinetic energies of one of the positrons and one of the protons respectively after a very long time will be
    scienceingestion-and-digestion-1
    As mass of proton mass of positron so initial acceleration of positron is much larger than proton. Therefore positron reach far away in very short time as compare to proton

    2 K subscript e to the power of ´ end exponent end subscript equals open parentheses fraction numerator 4 k q to the power of 2 end exponent over denominator a end fraction plus fraction numerator 2 k q to the power of 2 end exponent over denominator a square root of 2 end fraction close parentheses minus fraction numerator k q to the power of 2 end exponent over denominator a square root of 2 end fraction rightwards double arrow K subscript e to the power of ´ end exponent end subscript equals fraction numerator q to the power of 2 end exponent over denominator 2 pi ϵ subscript 0 end subscript a end fraction open parentheses 1 plus fraction numerator 1 over denominator 4 square root of 2 end fraction close parentheses text  and  end text 2 K subscript p end subscript equals fraction numerator k q to the power of 2 end exponent over denominator a square root of 2 end fraction minus 0 rightwards double arrow K subscript p end subscript equals fraction numerator q to the power of 2 end exponent over denominator 8 square root of 2 pi ϵ subscript 0 end subscript a end fraction

    Grade-7
    science

    Which of the following steps of cellular respiration occurs after this step (step shown in the image)?

    • The given diagram shows link reaction. In this product of glycolysis ( pyruvate) is converted into substrate of Krebs cycle ( coenzyme A)
    • Krebs cycle converts the chemicals energy of acetyl coenzyme A into reducing power of NADH

    Which of the following steps of cellular respiration occurs after this step (step shown in the image)?

    scienceGrade-7
    • The given diagram shows link reaction. In this product of glycolysis ( pyruvate) is converted into substrate of Krebs cycle ( coenzyme A)
    • Krebs cycle converts the chemicals energy of acetyl coenzyme A into reducing power of NADH
    Grade-7
    science

    The oxidative phosphorylation process results in the production of adenosine triphosphate.

    • Oxidative is is the process by which ATP synthesis is coupled to the movement of electrons through mitochondrial electron transport chain 
    • Consumption of oxygen occurs in this step
    • Energy produced is in the form of ATP 

    The oxidative phosphorylation process results in the production of adenosine triphosphate.

    scienceGrade-7
    • Oxidative is is the process by which ATP synthesis is coupled to the movement of electrons through mitochondrial electron transport chain 
    • Consumption of oxygen occurs in this step
    • Energy produced is in the form of ATP 
    Grade-7
    science

    Choose the odd one out.

    • In aerobic respiration oxygen is used to produce energy from sugar ( glucose)
    • Carbondioxide  ,  water and ATP are produced at the various stages of the aerobic respiration 

    Choose the odd one out.

    scienceGrade-7
    • In aerobic respiration oxygen is used to produce energy from sugar ( glucose)
    • Carbondioxide  ,  water and ATP are produced at the various stages of the aerobic respiration 
    Grade-7
    science

    During ________________, a 6-carbon molecule is broken down into two 3-carbon pyruvate molecules.

    • Glycolysis is the process of breast down of six carbon compound glucose into two molecules of three carbon compound pyruvate 
    • It is the cytoplasmic process 
    • 2 molecules of ATP is released as energy 

    During ________________, a 6-carbon molecule is broken down into two 3-carbon pyruvate molecules.

    scienceGrade-7
    • Glycolysis is the process of breast down of six carbon compound glucose into two molecules of three carbon compound pyruvate 
    • It is the cytoplasmic process 
    • 2 molecules of ATP is released as energy 
    Grade-7
    science

    ______________ serves the straightforward objective of giving cells the energy they require to function.

    • Oxidative phosphorylation is the process by which ATP synthesis is the to the movement of electrons through mitochondrial electron transport chain 
    • Oxidation of previously formed NADH and FADH molecules 
    • ATP are produced and oxygen is consumed only in this step

    ______________ serves the straightforward objective of giving cells the energy they require to function.

    scienceGrade-7
    • Oxidative phosphorylation is the process by which ATP synthesis is the to the movement of electrons through mitochondrial electron transport chain 
    • Oxidation of previously formed NADH and FADH molecules 
    • ATP are produced and oxygen is consumed only in this step
    Grade-7
    science

    During the process of _________, the electrons extracted from food move down the electron transport chain in the inner membrane of the mitochondrion.

    Oxidative phosphorylation is the process by which ATP synthesis is coupled to the movement of electrons through mitochondrial electron transport chain

    During the process of _________, the electrons extracted from food move down the electron transport chain in the inner membrane of the mitochondrion.

    scienceGrade-7
    Oxidative phosphorylation is the process by which ATP synthesis is coupled to the movement of electrons through mitochondrial electron transport chain
    Grade-7
    science

    Identify the stage of cellular respiration, which takes place on the inner membrane of mitochondria.

    • At the inner mitochondrial membrane,  electron transport chain works
    • Electrons are passed through electron transport chain 
    • ATP synthesis is coupled to the movement of electrons. 

    Identify the stage of cellular respiration, which takes place on the inner membrane of mitochondria.

    scienceGrade-7
    • At the inner mitochondrial membrane,  electron transport chain works
    • Electrons are passed through electron transport chain 
    • ATP synthesis is coupled to the movement of electrons. 
    Grade-7
    science

    Suggest one word for each of the following statements.
    a).  Identify the stage in which energy from NADH and FADH2, which result from the previous stages of cellular respiration, is used to create ATP.
    b).  When Acetyl CoA and a four-carbon molecule join, a series of chemical processes known as ___________ takes place.
    c). The process by which glucose is broken down to provide energy is known as ____________.
    d). In mitochondria, _________ will be transformed into a two-carbon acetyl group.

    • In oxidative phosphorylation energy from NADH and FADH is used to create ATP 
    • When Acetyl coenzyme A and four carbon molecule oxaloacetate joins Krebs cycle takes place 
    • Glycolysis is the process in which glucose is broken down to produce energy 
    • In mitochondria pyruvate is broken down to produce two carbon acetyl group

    Suggest one word for each of the following statements.
    a).  Identify the stage in which energy from NADH and FADH2, which result from the previous stages of cellular respiration, is used to create ATP.
    b).  When Acetyl CoA and a four-carbon molecule join, a series of chemical processes known as ___________ takes place.
    c). The process by which glucose is broken down to provide energy is known as ____________.
    d). In mitochondria, _________ will be transformed into a two-carbon acetyl group.

    scienceGrade-7
    • In oxidative phosphorylation energy from NADH and FADH is used to create ATP 
    • When Acetyl coenzyme A and four carbon molecule oxaloacetate joins Krebs cycle takes place 
    • Glycolysis is the process in which glucose is broken down to produce energy 
    • In mitochondria pyruvate is broken down to produce two carbon acetyl group