Maths-

General

Easy

Question

# Show the conjecture is false by finding a counterexample. The square root of any positive integer x is always less than x.

Hint:

### Take an example and check.

## The correct answer is: Thus we get 1 as the integer, whose square root is equal to itself to disprove the conjecture.

### Complete step by step solution:

Here take the integer x = 1

On taking square root, we get

Here, is never less than1.

Thus we get 1 as the integer, whose square root is equal to itself to disprove the

conjecture.

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